/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 A \(1.52-\mathrm{kg}\) book slid... [FREE SOLUTION] | 91Ó°ÊÓ

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A \(1.52-\mathrm{kg}\) book slides \(1.24 \mathrm{~m}\) along a level surface. The coefficient of kinetic friction between book and surface is \(0.140 .\) Find the work done by friction.

Short Answer

Expert verified
The work done by friction is approximately \(-2.59 \, \text{J}\).

Step by step solution

01

Understand the concept of work done by friction

The work done by friction is given by the formula: \( W = f_k imes d \), where \( f_k \) is the kinetic friction force and \( d \) is the distance over which the force acts.
02

Calculate the force of kinetic friction

The force of kinetic friction can be calculated using the formula: \( f_k = \mu_k \times N \), where \( \mu_k \) is the coefficient of kinetic friction and \( N \) is the normal force. Since the book is on a level surface, \( N = mg \), where \( m \) is the mass and \( g = 9.81 \, \text{m/s}^2 \) is the acceleration due to gravity. Calculate \( N = 1.52 \, \text{kg} \times 9.81 \, \text{m/s}^2 = 14.9112 \, \text{N} \). Then, calculate \( f_k = 0.140 \times 14.9112 \, \text{N} = 2.087568 \, \text{N} \).
03

Calculate the work done by friction

Now that \( f_k \) is known, calculate the work done by friction using the formula \( W = f_k \times d \) where \( d = 1.24 \, \text{m} \). Thus, \( W = 2.087568 \, \text{N} \times 1.24 \, \text{m} = 2.58956952 \, \text{J} \).
04

Consider the direction of friction force

Since friction always acts opposite to the direction of movement, the work done by friction is negative. Therefore, the work done by friction is \(-2.58956952 \, \text{J} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Friction
Kinetic friction is a force that opposes the motion of an object sliding across a surface. Imagine pushing a heavy book across a table; the resistance you feel is due to kinetic friction. This force depends on two main factors: the coefficient of kinetic friction and the normal force exerted on the object. The coefficient of kinetic friction, typically denoted as \( \mu_k \), is a dimensionless number representing the frictional properties between two surfaces in contact. It varies between different materials. For instance, rubber on concrete has a higher \( \mu_k \) than metal on ice, implying more friction. Kinetic friction can be calculated using the formula \( f_k = \mu_k \times N \), where \( N \) is the normal force. Remember, kinetic friction always acts in the opposite direction of the object's motion, which is why it slows objects down on surfaces. Understanding this concept is crucial when calculating the work done by friction since it tells us how much energy is lost due to friction when an object moves.
Normal Force
The normal force is a crucial concept in physics, especially when studying forces and motion on inclined planes or surfaces. It is the force exerted by a surface to support the weight of an object resting on it, acting perpendicular (hence "normal") to the surface. Think of placing a book on a table: the table exerts an upward force equal in magnitude to the book's weight to keep it from falling through. This is the normal force in action. On a level surface, the normal force often equals the gravitational force on the object, calculated as \( N = mg \), where \( m \) is the mass and \( g \approx 9.81 \, \text{m/s}^2 \) is the acceleration due to gravity. When surfaces are tilted, the normal force decreases because it only supports a portion of the gravitational force. For professionals and students, comprehending the normal force is critical for accurately calculating kinetic friction, allowing predictions of how objects move.
Coefficient of Friction
The coefficient of friction is a fundamental parameter that helps to predict how much frictional force is produced when two surfaces slide against each other. This coefficient can either be static or kinetic, depending on whether the surfaces are stationary or in motion. In our context, we focus on the coefficient of kinetic friction \( \mu_k \). This value quantifies the ease with which one material slides over another. Unlike force or length, the coefficient of friction is dimensionless, meaning it has no units because it is a ratio. Materials with high coefficients of friction create more frictional force, making it harder for objects to slide, while those with low coefficients make sliding easier. For example:
  • Rubber and asphalt have a high \( \mu_k \), useful for vehicle traction.
  • Ice has a low \( \mu_k \), explaining why slipping occurs.
Understanding \( \mu_k \) is crucial for predicting motion and analyzing problems like the given exercise, where the frictional force resists the sliding book's movement.

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Most popular questions from this chapter

While driving on a straight level highway in your \(1450-\mathrm{kg}\) car, you take your foot off the gas and find that your speed drops from \(65 \mathrm{mi} / \mathrm{h}\) to \(55 \mathrm{mi} / \mathrm{h}\) over one-tenth of a mile. Assuming your average speed during this interval was \(60 \mathrm{mi} / \mathrm{h},\) find the power (in watts and horsepower) needed to keep your car moving at a constant \(60 \mathrm{mi} / \mathrm{h}\).

Muscles are attached to bones by elastic bundles called tendons. For small stretches, tendons can be modeled as springs obeying Hooke's law. Experiments on the Achilles tendon found that it stretched \(2.66 \mathrm{~mm}\) with a \(125-\mathrm{kg}\) mass hung from it. (a) What is the spring constant of the Achilles tendon? (b) By how much would it have to stretch to store \(50.0 \mathrm{~J}\) of energy?

What power is needed to lift a \(350-\mathrm{kg}\) crate of bricks from the ground to the top of a 23.8 -m-high building in 1 minute?

Four identical springs with \(k=63.4 \mathrm{kN} / \mathrm{m}\) support a car, with the car's weight distributed equally among them. Find the maximum weight for the car if the springs should be compressed no more than \(4.0 \mathrm{~cm}\) when the car is at rest.

A horizontal spring with \(k=120 \mathrm{~N} / \mathrm{m}\) has one end attached to the wall. A \(250-\mathrm{g}\) block is pushed onto the free end, compressing the spring by \(0.150 \mathrm{~m}\). The block is then released, and the spring launches it outward. (a) Neglecting friction, what's its speed when it leaves the spring? (b) Repeat part (a) if the coefficient of kinetic friction is \(0.220 .\)

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