/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 A block of ice sliding without f... [FREE SOLUTION] | 91Ó°ÊÓ

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A block of ice sliding without friction down a \(20^{\circ}\) slope has acceleration (a) \(9.8 \mathrm{~m} / \mathrm{s}^{2} ;\) (b) \(4.9 \mathrm{~m} / \mathrm{s}^{2} ;\) (c) \(3.4 \mathrm{~m} / \mathrm{s}^{2} ;\) (d) \(2.2 \mathrm{~m} / \mathrm{s}^{2}\).

Short Answer

Expert verified
The block's acceleration is approximately 3.4 m/s², closest to option (c).

Step by step solution

01

Understanding the Problem

We need to find the acceleration of a block of ice sliding down a frictionless incline angled at \(20^\circ\). We are given multiple-choice options for the value of the acceleration.
02

Identify Forces Acting on the Block

Since the block is sliding down a frictionless incline, the only force acting along the incline is the component of gravity. The gravitational force can be split into two components: parallel and perpendicular to the incline.
03

Use Newton's Second Law

For motion along the incline, apply Newton's second law: \[ F = ma \]where \( F \) is the force parallel to the incline, \( m \) is the mass of the block, and \( a \) is the acceleration we seek.
04

Calculate Gravitational Component Along the Incline

The parallel component of gravitational force is given by:\[ F = mg \sin \theta \]where \( g = 9.8 \ \mathrm{m/s^2} \) is the acceleration due to gravity and \( \theta \) is the angle of the incline (\( 20^\circ \)).
05

Solve for Acceleration

Set the parallel component of gravitational force equal to \( ma \):\[ mg \sin \theta = ma \]We can cancel \( m \) from both sides and solve for \( a \):\[ a = g \sin \theta \]Substitute the given values:\[ a = 9.8 \cdot \sin 20^\circ \approx 9.8 \cdot 0.342 \approx 3.35 \ \mathrm{m/s^2} \]
06

Choose the Closest Answer

Compare the computed acceleration \( 3.35 \ \mathrm{m/s^2} \) with the given options. The closest value is \( 3.4 \ \mathrm{m/s^2} \) from option (c).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newton's Second Law
Newton's Second Law is a fundamental principle in Physics that connects the concepts of force, mass, and acceleration. It states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. This can be mathematically described by the formula: \[ F = ma \]Where:
  • \( F \) represents the net force applied to the object.
  • \( m \) is the mass of the object.
  • \( a \) is the acceleration.
This law is essential in predicting how objects will move when subjected to different forces.In the context of the block of ice sliding down the incline, Newton's Second Law helps us determine the acceleration of the block. Despite the frictionless surface, the gravitational force acts on the block, pulling it down. By applying the second law, we can set up an equation to solve for the acceleration using the force component along the incline.
Frictionless Incline
Inclines or ramps are common surfaces where Physics problems often involve calculating the movement of objects along them. A frictionless incline means that there is no resistance opposing the motion of the object due to rough contact between surfaces. This simplifies problems because the only force to consider is the component of gravity acting along the incline. When dealing with a frictionless incline, like in our problem, the path is clear of any frictional forces which tend to complicate motion calculations. Therefore, the object, such as the block of ice, slides down solely under the influence of its weight and the gravitational pull. "Frictionless" implies that energy losses due to frictional forces are absent, making it simpler to apply pure gravitational calculations to determine motion characteristics such as acceleration. This assumption offers an ideal setting to practice applying Newton’s laws without the additional complexity of friction.
Gravitational Force Components
Gravitational force on an object can be thought of as being split into components when the object is on an incline. This is significant in understanding motion on inclined surfaces, especially in a Physics problem of this nature.Imagine the gravitational force acting straight downwards by weight, which is \( mg \), where \( g \) is acceleration due to gravity. For an object to move down an incline, we break this force into two components:
  • The component perpendicular to the slope: this does not affect motion along the slope.
  • The component parallel to the slope: this is responsible for the movement.
The parallel component is given by \( mg \sin \theta \), where \( \theta \) is the angle of the incline. This component is critical for determining the acceleration using Newton's Second Law. In the exercise, it is this parallel force component that we use to find the acceleration by equating it to \( ma \), leading us to determine the block's acceleration as \( 3.4 \, \mathrm{m/s^2} \), similar to choice (c) from the options.

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Most popular questions from this chapter

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