Chapter 23: Problem 22
A \(50-\mathrm{mW}\) laser produces 532 -nm green light. The number of photons it emits each second is (a) \(1.3 \times 10^{17}\); (b) \(1.6 \times 10^{17}\) (c) \(2.7 \times 10^{17}\) (d) \(2.7 \times 10^{18}\).
Short Answer
Expert verified
The correct answer is (a) \(1.3 \times 10^{17}\).
Step by step solution
01
Calculate the Energy of a Single Photon
First, use the formula for the energy of a single photon: \[E = \frac{hc}{\lambda}\]where \(h\) is Planck's constant (\(6.626 \times 10^{-34} \text{ J} \cdot \text{s}\)), \(c\) is the speed of light (\(3 \times 10^8 \text{ m/s}\)), and \(\lambda\) is the wavelength (532 nm or 532\( \times 10^{-9} \text{ m}\)).Substitute the values in to get:\[E = \frac{(6.626 \times 10^{-34} \text{ J} \cdot \text{s}) \times (3 \times 10^8 \text{ m/s})}{532 \times 10^{-9} \text{ m}}\]Solving this, \(E \approx 3.73 \times 10^{-19} \text{ J}\) per photon.
02
Calculate the Number of Photons Emitted per Second
Next, determine the total energy output per second in joules:\[ P = 50 \text{ mW} = 50 \times 10^{-3} \text{ W} = 50 \times 10^{-3} \text{ J/s} \]To find the number of photons emitted per second, divide this power by the energy per photon:\[\text{Number of photons} = \frac{P}{E} = \frac{50 \times 10^{-3} \text{ J/s}}{3.73 \times 10^{-19} \text{ J/photon}}\]Solving this gives: \( \text{Number of photons} \approx 1.34 \times 10^{17} \).
03
Determine the Correct Answer
Compare the calculated value of the number of photons, \(1.34 \times 10^{17}\), with the given choices:(a) \(1.3 \times 10^{17}\) (b) \(1.6 \times 10^{17}\) (c) \(2.7 \times 10^{17}\) (d) \(2.7 \times 10^{18}\).The closest match is choice (a).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Planck's Constant
Planck's constant is a fundamental constant in physics that plays a crucial role in quantum mechanics. Denoted as \( h \), its value is approximately \( 6.626 \times 10^{-34} \text{ J} \cdot \text{s} \). This tiny number serves as a bridge between the quantifiable measures of energy and frequency in the quantum realm.
Understanding Planck's constant aids in determining the energy of individual photons, a cornerstone concept when exploring light and other electromagnetic waves. To find the energy \( E \) of a photon, one can use the formula:
Understanding Planck's constant aids in determining the energy of individual photons, a cornerstone concept when exploring light and other electromagnetic waves. To find the energy \( E \) of a photon, one can use the formula:
- \( E = h \times f \), where \( f \) is the frequency of the photon.
- Alternatively, \( E = \frac{hc}{\lambda} \), where \( c \) is the speed of light and \( \lambda \) is the wavelength.
Speed of Light
The speed of light is one of the fundamental constants of nature. Denoted \( c \), its value is \( 3 \times 10^8 \text{ m/s} \). This speed describes how fast light travels in a vacuum and is pivotal in the equation for calculating photon energy. Light's speed is not only crucial for physics calculations but also serves as a marker for understanding the structure and behavior of the universe. It helps define how electromagnetic waves, including visible light, propagate through space.
In the photon energy formula \( E = \frac{hc}{\lambda} \), \( c \) relates the frequency and wavelength of light. Practically speaking, the speed of light determines:
In the photon energy formula \( E = \frac{hc}{\lambda} \), \( c \) relates the frequency and wavelength of light. Practically speaking, the speed of light determines:
- How quickly information can be transmitted across distances.
- Limits on the rate at which signals can travel.
Wavelength of Light
Wavelength of light, denoted by \( \lambda \), is the distance between consecutive peaks of a wave. In lasers, this property determines the color and energy of the emitted light. For instance, the exercise above specifies a green light with a wavelength of 532 nm.
Converting this wavelength to standard SI units (meters) involves multiplying by \( 10^{-9} \), giving \( 532 \times 10^{-9} \text{ m} \). Wavelength is critical when calculating photon energy because:
Converting this wavelength to standard SI units (meters) involves multiplying by \( 10^{-9} \), giving \( 532 \times 10^{-9} \text{ m} \). Wavelength is critical when calculating photon energy because:
- It inversely relates to energy: shorter wavelengths mean higher energy and vice versa.
- It defines the type of electromagnetic wave, such as radio, microwave, or visible light.
Laser Power
Laser power refers to the total energy emitted by a laser per unit time. It is usually measured in watts (W) or milliwatts (mW), where 1 watt equals 1000 milliwatts.In the solved exercise, the laser power is given as \( 50 \text{ mW}\), equivalent to \( 50 \times 10^{-3} \text{ W} \). This power represents how much energy the laser emits each second.The concept of power is integral to understanding how efficiently a laser operates. Power calculations allow us to:
- Determine the intensity and potential applications of the laser.
- Calculate the number of photons emitted per second.
Photons Per Second
'Photons per second' is an expression of the number of light particles emitted by a source, like a laser, in one second.To find this, you divide the laser's total power by the energy of a single photon.Given the calculations from the exercise, with a laser power of \(50 \times 10^{-3} \text{ J/s}\) and single photon energy of approximately \(3.73 \times 10^{-19} \text{ J}\), the photon emission rate is found using:
- \( \text{Number of photons} = \frac{P}{E} \)