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An object is dropped from rest off the \(442-\mathrm{m}\) Sears Tower in Chicago. Its fall time is (a) \(45.1 \mathrm{~s} ;\) (b) \(19.1 \mathrm{~s} ;\) (c) \(9.5 \mathrm{~s} ;\) (d) \(4.7 \mathrm{~s}\).

Short Answer

Expert verified
The fall time is 9.5 seconds, option (c).

Step by step solution

01

Understand the Problem

The object is dropped from a height of 442 meters. We need to determine how long it takes to hit the ground. The object is under the influence of gravity, with an acceleration of approximately \( g = 9.8 \ \text{m/s}^2 \) downward. We must calculate the time of free fall.
02

Apply the Free Fall Formula

Use the kinematic equation for distance during free fall, \( h = \frac{1}{2} g t^2 \), where \( h \) is the height (442 m), \( g \) is the acceleration due to gravity (9.8 m/s²), and \( t \) is the time in seconds. Substitute the values: \( 442 = \frac{1}{2} \times 9.8 \times t^2 \).
03

Solve for Time

Rearrange the equation to solve for \( t^2 \):\[ t^2 = \frac{442 \times 2}{9.8} \]Calculate this to find \( t^2 \):\[ t^2 = \frac{884}{9.8} \approx 90.2 \]Take the square root of both sides to find \( t \):\[ t = \sqrt{90.2} \approx 9.5 \ \text{s} \]
04

Determine the Correct Answer

The calculated time is approximately 9.5 seconds. From the given options, option (c) 9.5 s matches our calculated result.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

kinematic equations
Kinematic equations serve as the foundation of motion analysis in physics, particularly when there are constant acceleration scenarios, like free fall. These equations relate the variables of motion, including displacement, velocity, acceleration, and time. In the context of a free-fall problem, we primarily utilize the equation for displacement:\[ h = \frac{1}{2} g t^2\]Here, the displacement \(h\) is the height from which the object is dropped, \(g\) is the acceleration due to gravity, and \(t\) is the time it takes to fall.
With kinematic equations, we can predict how fast or how far an object will move under constant acceleration, making them essential tools in physics.
acceleration due to gravity
The acceleration due to gravity is a crucial factor in free-fall problems. On Earth, this acceleration is approximately \(9.8 \, \text{m/s}^2\), directing downward towards the center of the planet. It's a constant value because, near the surface of the Earth, gravity doesn't fluctuate much over short distances. This constant allows us to apply kinematic equations reliably in these scenarios.
In free fall, this means an object's speed increases by approximately 9.8 meters per second every second, assuming no air resistance. Since the objects dropped from rest, this gravitational acceleration is the only force acting on it, propelling it in a straight path downward.
Understanding the role of gravity is essential in explaining why objects accelerate as they fall, offering insight into the natural phenomena of gravity.
Sears Tower problem
The Sears Tower problem provides a real-world context to apply our understanding of free fall and kinematic equations. By analyzing an object dropped from a known height—Sears Tower's remarkable 442 meters—we can use theoretical physics to calculate the time it takes to reach the ground. This helps illustrate the concepts practically:
- **Known Quantity**: The height, 442 m, enables us to input this known value directly into our equations. - **Gravity's Role**: Only gravity influences the fall, simplifying the model, as no initial velocity or air resistance are considered. - **Time Calculation**: By substituting into the kinematic equation, we solve for the time it takes the object to fall, deepening understanding through tangible application.
This problem, therefore, connects abstract physics principles with familiar, real-world landmarks, enriching the learning experience.
distance and time calculation
Calculating the distance and time in motion scenarios like free fall is straightforward thanks to kinematic equations. For the problem of an object dropped from Sears Tower, we use the equation:\[ h = \frac{1}{2} g t^2 \]Given:
- **Height (h)**: 442 meters- **Gravity (g)**: 9.8 m/s²We seek the time \(t\). First, rearrange the equation to solve for time squared:\[ t^2 = \frac{2h}{g} = \frac{2 \times 442}{9.8}\]Calculating gives \( t^2 \approx 90.2 \). Taking the square root, we find \( t \approx 9.5 \text{s} \).

Thus, the time for the object to reach the ground is readily calculated, emphasizing the practical utility and simplicity of these calculations for understanding motion under gravity.

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Most popular questions from this chapter

At the edge of a 12 -m-tall building, two children throw rocks at \(10 \mathrm{~m} / \mathrm{s}\), one upward and one downward. (a) Find the time until each rock hits the ground. (b) Find the speed of each when it hits.

You're driving down a straight highway at \(25 \mathrm{~m} / \mathrm{s}\). You apply the brakes and stop after \(10.0 \mathrm{~s}\) of constant acceleration. (a) Graph (a) your velocity and (b) your position, both versus time. (c) Draw a motion diagram, showing your car at 2.0 -s intervals.

A parachutist free falls \(440 \mathrm{~m}\) in \(10.0 \mathrm{~s}\). She then opens her chute and drops the remaining \(1350 \mathrm{~m}\). If her average velocity for the entire trip is \(3.45 \mathrm{~m} / \mathrm{s}\), what's her average velocity while the chute is open?

Jumping flea. For its size, the flea can jump to amazing heights - as high as \(30 \mathrm{~cm}\) straight up, about 100 times the flea's length. (a) For such a jump, what takeoff speed is required? (b) How much time does it take the flea to reach maximum height? (c) The flea accomplishes this leap using its extremely elastic legs. Suppose its upward acceleration is constant while it thrusts through a distance of \(0.90 \mathrm{~mm}\). What's the magnitude of that acceleration? Compare with \(g\).

A ball is launched straight up from the ground and falls straight back down. At any given position along the path, which of these quantities are the same and which are different for the upward and downward motions: velocity, speed, and acceleration?

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