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A \(20-\mathrm{k} \Omega\) resistor, a \(30-\mathrm{k} \Omega\) resistor, and a \(75-\mathrm{k} \Omega\) resistor are in parallel across a battery. The current in the \(20-\mathrm{k} \Omega\) resistor is \(0.125 \mathrm{~mA}\). Find (a) the battery emf and (b) the current in each of the other resistors.

Short Answer

Expert verified
(a) The battery emf is 2.5 V. (b) Currents are 0.0833 mA and 0.0333 mA for 30 kΩ and 75 kΩ resistors, respectively.

Step by step solution

01

Understand the Setup

These are three resistors connected in parallel. The voltage drop across each resistor is the same, and it's equal to the battery's electromotive force (emf).
02

Use Ohm's Law for the Known Resistor

Given the current through the 20 kΩ resistor is 0.125 mA, find the voltage (which is also the emf of the battery) using Ohm's Law: \[ V = I imes R \] Substitute the values: \[ V = 0.125 imes 10^{-3} imes 20 imes 10^{3} = 2.5 ext{ Volts} \].This 2.5 V is the emf of the battery.
03

Calculate Current Through the 30 kΩ Resistor

Using the same voltage (2.5V) for the other resistors, apply Ohm's Law again to find the current through the 30 kΩ resistor:\[ I = \frac{V}{R} = \frac{2.5}{30 imes 10^{3}} = 0.0833 ext{ mA} \]
04

Calculate Current Through the 75 kΩ Resistor

Apply Ohm's Law for the 75 kΩ resistor using the known voltage 2.5V:\[ I = \frac{V}{R} = \frac{2.5}{75 imes 10^{3}} = 0.0333 ext{ mA} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Current in Parallel Circuits
In parallel circuits, each component or branch has the same voltage across its terminals. This is one of the fundamental properties that distinguishes parallel circuits from series circuits. Because the voltage is constant in each branch, parallel circuits are very advantageous for distributing power to multiple devices from a single source.
It’s important to remember that while the voltage is constant in a parallel circuit, the current is not distributed equally. Instead, the total current flowing from the source is divided among the parallel branches. The amount of current that flows through each branch depends on the resistance of that branch. The lower the resistance, the higher the current that flows through it.
  • Voltage is the same across all components in a parallel circuit.
  • The total current is the sum of the currents through each parallel branch.
When solving problems involving parallel circuits, you can use Ohm’s Law, which states that the current (I) in a resistor is equal to the voltage (V) across the resistor divided by the resistance (R) of the resistor: \[ I = \frac{V}{R} \] This relationship allows us to calculate the current through each resistor, as we can see in the exercise discussed.
Resistor Calculations
Resistor calculations in parallel circuits might initially seem complex, but they actually follow a straightforward pattern. In parallel configurations, the total or equivalent resistance can be calculated using the reciprocal formula. However, when given specific resistors and a fixed voltage, it becomes easier to individually calculate the current through each resistor.
Using Ohm's Law, once you know the voltage (or emf) across the entire parallel circuit, calculating the current flowing through each resistor becomes a matter of simple division:
  • Calculate the current through a resistor using
    \[ I = \frac{V}{R} \]
  • If you have the current for one resistor and need to find the overall effect, remember that for any new resistor added in parallel, the total resistance of the circuit decreases, which subsequently increases the circuit’s total current.
    • For a 20 kΩ resistor with a 2.5V drop, the current is 0.125 mA.
    • For a 30 kΩ resistor with the same 2.5V drop, the current becomes 0.0833 mA.
    • With a 75 kΩ resistor, it reduces further to 0.0333 mA.
    Each resistor carries a different portion of the total current based on its resistance value.
    Electromotive Force (emf)
    Electromotive Force, or emf, is an essential component in circuitry. It is often described as the "pressure" that pushes electric current to flow through a circuit. In the scenario provided, the emf of the battery was determined using one branch of the parallel circuit, specifically the 20 kΩ resistor. By knowing the current in this branch, which was 0.125 mA, the voltage across it—or the emf—was determined to be 2.5 volts, showcasing Ohm's Law in action.
    Though referred to as a "force," emf is actually a potential difference, measured in volts, not a force in the mechanical sense. It provides the energy per unit charge needed to drive the current through the resistance of the entire circuit without any inherent loss of energy.
    • The emf is constant across all branches in a parallel circuit.
    • It powers the circuit and maintains the voltage across resistors.
    In practical terms, as shown, there's a universal application: once the emf is known, it can directly be used to compute other unknowns in the circuit, like the current through different resistors as we calculated for 30 kΩ and 75 kΩ resistors previously.

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    Most popular questions from this chapter

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