Chapter 15: Problem 60
A large plane having uniform charge density has an electric field just outside the plane that points directly toward the plane with magnitude \(1.25 \times 10^{4} \mathrm{~N} / \mathrm{C}\). What is the surface charge density?
Short Answer
Expert verified
The surface charge density is approximately \(2.21 \times 10^{-7} \, \text{C/m}^2\).
Step by step solution
01
Understanding the Problem
We have a plane with a uniform charge density and an electric field just outside the plane with a magnitude of \(1.25 \times 10^{4} \, \text{N/C}\). We need to find the surface charge density, \(\sigma\).
02
Using Gauss's Law for a Plane
For a plane with a uniform charge density, the electric field \(E\) just outside is given by \(E = \frac{\sigma}{2\varepsilon_0}\), where \(\varepsilon_0\) is the permittivity of free space \(\varepsilon_0 = 8.85 \times 10^{-12} \, \text{C}^2/\text{N}\cdot\text{m}^2\).
03
Rearranging Gauss's Law Formula
We rearrange the formula to solve for the surface charge density: \(\sigma = 2\varepsilon_0 E\).
04
Plugging in the Values
Substitute \(E = 1.25 \times 10^{4} \, \text{N/C}\) and \(\varepsilon_0 = 8.85 \times 10^{-12} \, \text{C}^2/\text{N}\cdot\text{m}^2\) into the formula: \[\sigma = 2 \times (8.85 \times 10^{-12}) \times (1.25 \times 10^{4})\].
05
Calculating the Surface Charge Density
Calculate \(\sigma\): \(\sigma = 2 \times 8.85 \times 1.25 \times 10^{-8} \approx 2.21 \times 10^{-7} \, \text{C/m}^2\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Gauss's Law
Gauss's Law is a fundamental principle in electromagnetism that relates the electric flux through a closed surface to the charge enclosed by that surface. This law can be written as \( \Phi_E = \frac{Q}{\varepsilon_0} \), where \( \Phi_E \) is the electric flux, \( Q \) is the total charge enclosed, and \( \varepsilon_0 \) is the permittivity of free space. In simpler terms, Gauss's Law helps us understand how electric charges distribute electric fields in the space around them.
- In the case of a plane with uniform charge distribution, the electric field is perpendicular to the surface of the plane.
- Using Gauss's Law, the electric field \( E \) just outside an infinite charged plane is related to the surface charge density \( \sigma \) by the equation \( E = \frac{\sigma}{2\varepsilon_0} \).
Surface Charge Density
Surface charge density, symbolized as \( \sigma \), refers to the amount of electric charge per unit area on a surface. It's an important concept when discussing electric fields generated by charged surfaces.
- Surface charge density is typically measured in coulombs per square meter \( (\text{C/m}^2) \).
- It summarises how much charge is packed onto the surface of, for example, a plane or conductor.
- The formula \( \sigma = 2\varepsilon_0 E \) allows us to compute \( \sigma \) if we know the electric field \( E \) and the permittivity of free space \( \varepsilon_0 \).
Permittivity of Free Space
The permittivity of free space, denoted as \( \varepsilon_0 \), is a physical constant that measures the ability of a vacuum to permit electric field lines. It plays a crucial role in calculations involving electric fields and forces. Understanding this concept will help you analyze many problems in electromagnetism.
- It is a universal constant, approximately equal to \( 8.85 \times 10^{-12} \, \text{C}^2/\text{N} \cdot \text{m}^2 \).
- \( \varepsilon_0 \) appears in Gauss's Law, acting as a scale factor that directly influences how electric fields are calculated in a vacuum.
- In conjunction with Gauss's Law, it helps relate surface charge density \( \sigma \) to electric field \( E \) using the equation \( \sigma = 2\varepsilon_0 E \).