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An organ pipe with both ends open has fundamental frequency \(440 \mathrm{~Hz} .\) The frequency of its first overtone is (a) \(660 \mathrm{~Hz}\); (b) \(880 \mathrm{~Hz}\); (c) \(1320 \mathrm{~Hz}\); (d) \(1760 \mathrm{~Hz}\).

Short Answer

Expert verified
The frequency of the first overtone is 880 Hz, so the answer is (b).

Step by step solution

01

Understanding the Fundamental Frequency

For a pipe open at both ends, the fundamental frequency is the lowest frequency at which the air column in the pipe resonates. Given in the problem, this frequency is \(440 \text{ Hz}\).
02

Recognizing the Harmonic Series for Open Pipes

A pipe open at both ends supports harmonics (or overtones) that are integer multiples of the fundamental frequency. This means the series of frequencies is \(f, 2f, 3f, \ldots\) where \(f\) is the fundamental frequency.
03

Calculating the First Overtone

The first overtone for a pipe open at both ends is the second harmonic. Therefore, the frequency of the first overtone is twice the fundamental frequency \((2f)\).
04

Performing the Calculation

Given the fundamental frequency \(f = 440 \text{ Hz}\), the first overtone (second harmonic) is \(2 \times 440 = 880 \text{ Hz}\).
05

Final Answer Selection

Compare the calculated first overtone frequency \(880 \text{ Hz}\) with the given options. Option (b) matches our calculation: \(880 \text{ Hz}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Organ Pipes
Organ pipes are fascinating musical instruments that allow sound to resonate at specific frequencies. These pipes can have different configurations, such as being open at both ends or closed at one end. In this exercise, we are discussing an organ pipe that is open at both ends. This configuration allows air waves to move freely at both ends, creating a series of standing waves with nodes and antinodes.

A node is a point along the wave where there is no displacement, while an antinode is where the displacement is at its maximum. In pipes open at both ends, the antinodes are located at both openings, with nodes appearing within the pipe. This arrangement of nodes and antinodes leads to the term "harmonics"—a key concept to understand organ pipes.
Harmonics
Harmonics are integral to understanding how sounds are produced in musical instruments like organ pipes. When a fundamental frequency interacts with the properties of the pipe, it creates multiple frequencies that belong to a harmonic series. In an open pipe, these harmonics occur at integer multiples of the fundamental frequency.

For instance, if the fundamental frequency is denoted as \( f \), then the harmonics can be represented as \( f, 2f, 3f, \ldots \). This means the pipe supports multiple frequencies where each harmonic is a whole number times the base frequency. It's these harmonics that contribute to the richness and complexity of the sound produced by the instrument. They are crucial for musicians because they give each note its unique character and timbre.
Overtones
Overtones are closely related to harmonics but are understood in a slightly different light. In the world of music and acoustics, the term "overtone" specifically refers to the frequencies that are higher than the fundamental frequency. In simpler terms, the first overtone is actually the second harmonic, the second overtone is the third harmonic, and so on.

For an organ pipe open at both ends, the first overtone is double the fundamental frequency (which is the first harmonic), so it's often called the second harmonic. This means if the pipe resonates at a fundamental frequency of \( 440 \text{ Hz} \), the first overtone would be \( 880 \text{ Hz} \). Overtones, like harmonics, play a significant role in defining the sound quality and depth produced by musical instruments.

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Most popular questions from this chapter

A 1.12 -m-long organ pipe has one end open. Among its possible standing-wave frequencies is \(225 \mathrm{~Hz} .\) The next higher frequency is \(375 \mathrm{~Hz} .\) Do not assume that the speed of sound is \(343 \mathrm{~m} / \mathrm{s} .\) Find \((\) a \()\) the fundamental frequency and \((\mathrm{b})\) the sound speed.

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