Chapter 10: Problem 24
Water flows through a \(1.5-\mathrm{cm}\) -diameter hose into a \(12-\mathrm{L}\) bucket, which it fills in \(90 \mathrm{~s}\). What's the speed of the water in the hose? (a) \(0.19 \mathrm{~m} / \mathrm{s}\) (b) \(0.36 \mathrm{~m} / \mathrm{s}\) (c) \(0.75 \mathrm{~m} / \mathrm{s}\) (d) \(0.85 \mathrm{~m} / \mathrm{s}\).
Short Answer
Step by step solution
Convert Diameter to Radius
Calculate Cross-Sectional Area of the Hose
Determine Volume Flow Rate
Apply Continuity Equation to Find Speed
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Fluid Mechanics
Fluid mechanics encompass several key principles:
- Fluid Statics: The study of fluids at rest. It involves the analysis of pressure in a fluid or at the fluid boundary.
- Fluid Dynamics: Focuses on fluids in motion. This involves studying the forces and changes occurring as a fluid flows.
- Hydrodynamics: A part of fluid dynamics concerning the flow of water and other liquids.
Continuity Equation
The mathematical representation of the continuity equation is:\[ Q = A \times v \]where:
- \( Q \) is the volume flow rate, or the volume of fluid per unit time. This is measured in cubic meters per second (m³/s).
- \( A \) is the cross-sectional area of the pipe or hose, which is calculated using the formula for the area of a circle: \( A = \pi r^2 \), where \( r \) is the radius.
- \( v \) is the velocity or speed of the fluid along the pipe or hose, measured in meters per second (m/s).
Flow Rate Calculation
To find the flow rate, you calculate the amount of fluid flowing through a given cross-sectional area over time. This is represented as:\[ Q = \frac{V}{t} \]where:
- \( Q \) is the volume flow rate (m³/s).
- \( V \) is the volume of fluid that flows past a point in the system (measured in m³).
- \( t \) is the time (in seconds) over which the fluid passes.