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The "stone" \(A\) used in the sport of curling slides over the ice track and strikes another "stone" \(B\) as shown. If each "stone" is smooth and has a weight of \(47 \mathrm{lb}\), and the coefficient of restitution between the "stones" is \(e=0.8\), determine their speeds just after collision. Initially \(A\) has a velocity of \(8 \mathrm{ft} / \mathrm{s}\) and \(B\) is at rest. Neglect friction.

Short Answer

Expert verified
'stone' A has a speed of 1.6 ft/s and B has a speed of 6.4 ft/s just after the collision.

Step by step solution

01

Apply Conservation of Momentum

According to the law of conservation of momentum, the total momentum before collision should be equal to the total momentum after collision. If the speed of 'stone' A after collision is denoted as \(v_{a}\) and the speed of 'stone' B after collision denoted as \(v_{b}\), then the equation based on conservation of momentum can be written as \(47(8)+47(0) = 47v_{a} + 47v_{b} = 376 \rightarrow Equation (1)\)
02

Use Coefficient of Restitution

The coefficient of restitution, \(e\), represents the relative speed of the two objects after the collision in terms of their relative speed before collision. It can be formulated as \(e= (v_{b} - v_{a}) / (8 - 0) = 0.8 \rightarrow Equation (2)\)
03

Solve Simultaneously

The speed of the 'stones' after collision can be found by solving equations (1) and (2) simultaneously. The result would be:- \(v_{a} = 1.6\) ft /s (speed of 'stone' A just after collision )- \(v_{b} = 6.4\) ft /s (speed of 'stone' B just after collision)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Momentum
The principle of conservation of momentum is a fundamental concept in physics, especially when dealing with collisions. This principle tells us that within a closed system, where no external forces are acting, the total linear momentum remains constant. Momentum is calculated as the product of mass and velocity. In the case of the curled "stones" A and B, even though they aren't traditional curling stones, the concept still holds.
In our example, before the collision, stone A is moving with a velocity of 8 ft/s, while stone B is at rest. When these two stones collide, we apply the conservation of momentum to predict the resulting speeds. Using the equation:
  • Initial Momentum of A: 47 lb × 8 ft/s = 376 lb·ft/s
  • Initial Momentum of B: 47 lb × 0 ft/s = 0 lb·ft/s
  • Total Momentum before collision: 376 lb·ft/s
After the collision, the total momentum remains the same. This is how we set up our equation:\[ 47v_a + 47v_b = 376 \]By maintaining this equality, we ensure the momentum's conservation after the stones collide.
Coefficient of Restitution
The coefficient of restitution (often denoted as \( e \)) is a measure of how "bouncy" a collision is. It relates the relative velocity of two colliding objects after impact to their relative velocity before collision. The value ranges from 0 to 1, where 1 indicates a perfectly elastic collision with no loss of kinetic energy, and 0 represents a perfectly inelastic collision where the objects stick together.
For this exercise, the coefficient of restitution is given as 0.8, indicating a near-elastic collision but with some energy loss. The formula for the coefficient of restitution is:\[ e = \frac{v_b - v_a}{8 - 0} = 0.8 \]Here, 8 is the initial velocity of stone A, and 0 is the initial velocity of stone B. This formula enables us to calculate the velocities of both stones after the collision:
  • \( v_a \) is the velocity of stone A after collision.
  • \( v_b \) is the velocity of stone B after collision.
Using the known value of \( e \), we substitute and solve for these velocities, balancing energy conservation with perfectly realistic inelastic loss.
Collision Dynamics
Collision dynamics refers to the study of how two or more objects interact during a collision, focusing on the forces involved and the subsequent motion of the objects. In this context, the curling stones exhibit key characteristics of collision dynamics, such as momentum exchange and restitution.
When two objects collide, the key factors influencing the post-collision motion include:
  • The masses of the objects
  • The initial velocities
  • The coefficient of restitution
Prior to the collision, stone A has momentum due to its velocity of 8 ft/s, while stone B remains stationary. The collision transfers some of A’s momentum to B, adhering to conservation laws and restitution principles, resulting in different post-collision velocities.
Using the conservation of momentum:
  • \( 47v_a + 47v_b = 376 \)
And the coefficient of restitution:
  • \( \frac{v_b - v_a}{8} = 0.8 \)
These equations allow us to calculate the velocities. Solving these, we find post-collision velocities of 1.6 ft/s for A and 6.4 ft/s for B, highlighting the dynamic shift in motion post-collision. The interplay of momentum and energy conservation informs their motion, showcasing essential collision dynamics in action.

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Most popular questions from this chapter

The \(0.5-\mathrm{kg}\) ball is fired from the tube at \(A\) with a velocity of \(v=6 \mathrm{~m} / \mathrm{s}\). If the coefficient of restitution between the ball and the surface is \(e=0.8\), determine the height \(h\) after it bounces off the surface.

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Two smooth billiard balls \(A\) and \(B\) each have a mass of \(200 \mathrm{~g}\). If \(A\) strikes \(B\) with a velocity \(\left(v_{A}\right)_{1}=1.5 \mathrm{~m} / \mathrm{s}\) as shown, determine their final velocities just after collision. Ball \(B\) is originally at rest and the coefficient of restitution is \(e=0.85 .\) Neglect the size of each ball.

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