/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 74 The assembly consists of two blo... [FREE SOLUTION] | 91Ó°ÊÓ

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The assembly consists of two blocks \(A\) and \(B\) which have a mass of \(20 \mathrm{~kg}\) and \(30 \mathrm{~kg}\), respectively. Determine the speed of each block when \(B\) descends \(1.5 \mathrm{~m}\). The blocks are released from rest. Neglect the mass of the pulleys and cords.

Short Answer

Expert verified
The speed of both block A and block B when B descends 1.5 m can be found by solving the resulting quadratic equation from the energy conservation law. The velocity will be the same for both blocks due to the connection through the pulley system.

Step by step solution

01

Set up the energy conservation equation

Identify that this is an energy conversion problem where there is a transformation of potential energy into kinetic energy. Specifically, for block B, potential energy is decreasing as it descends 1.5m, while block A is gaining kinetic energy as it moves along with block B. Write down the general form of the energy conservation equation: \( \Delta KE + \Delta PE = 0 \)
02

Substitute known values

Apply the energy conservation law to block B's potential energy and the kinetic energy of both blocks (since both blocks move at the same velocity). Fill in the known values into the equation: \(0.5 \cdot m_A \cdot v^2 + 0.5 \cdot m_B \cdot v^2 - m_B \cdot g \cdot h = 0\). Here, \(m_A\) is the mass of block A (20 kg), \(m_B\) is the mass of block B (30 kg), \(g\) is the acceleration due to gravity (9.8 m/s\(^2\)), \(h\) is the height block B descends (1.5 m), and \(v\) is the velocity we want to find.
03

Solve for the velocity

Rearrange the equation to solve for v. Simplify the equation to obtain the value of the velocity. This might entail first combine similar terms, reorder the equation as needed, and then use a square root operation at the end to solve for v.

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