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The escalator steps move with a constant speed of \(0.6 \mathrm{~m} / \mathrm{s}\). If the steps are \(125 \mathrm{~mm}\) high and \(250 \mathrm{~mm}\) in length, determine the power of a motor needed to lift an average mass of \(150 \mathrm{~kg}\) per step. There are 32 steps.

Short Answer

Expert verified
The required power of the motor is approximately 882 Watts.

Step by step solution

01

Convert Dimensions to Base Units

First, convert the height of the steps from millimeters to meters for consistency in units, by multiplying by \(10^{-3}\). The height of each step in meters is therefore \(125 \times 10^{-3} m = 0.125 m\). Similarly, convert the length of each step to meters, which gives \(250 \times 10^{-3} m = 0.25 m\).
02

Calculate Total Height and Total Time

Calculate the total height that the steps cover by multiplying the height of a single step by the total number of steps: \(0.125 m/step \times 32 steps = 4 m\). Calculate the total time taken to cover this distance by dividing the total height by the speed of the escalator: \(4 m / 0.6 m/s = 6.67 s\).
03

Calculate Work Done

The work done in lifting mass in the gravitational field (which effectively is the gravitational potential energy) is calculated by multiplying the mass, gravitation field strength, and height, i.e, \(150 kg \times 9.81 m/s^2 \times 4 m = 5886 J\), where \(9.81 m/s^2\) is the approximate value of gravity on Earth, \(150 kg\) is the mass, and \(4 m\) is the total height.
04

Calculate Power

Finally, calculate the power, which is the work done per unit time. So, power = work / time = \(5886 J / 6.67 s = 882 W\) (watts).

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