/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 Block \(A\) has a weight of \(8 ... [FREE SOLUTION] | 91Ó°ÊÓ

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Block \(A\) has a weight of \(8 \mathrm{lb}\) and block \(B\) has a weight of \(6 \mathrm{lb}\). They rest on a surface for which the coefficient of kinetic friction is \(\mu_{k}=0.2\). If the spring has a stiffness of \(k=20 \mathrm{lb} / \mathrm{ft}\), and it is compressed \(0.2 \mathrm{ft}\), determine the acceleration of each block just after they are released. Prob. 13-13

Short Answer

Expert verified
The acceleration of block A is \(0.3 \, ft/s^2\) and the acceleration of block B is \(0.47 \, ft/s^2\).

Step by step solution

01

Calculate the Spring Force

Using Hooke's Law, which states the force exerted by a spring is equal to the spring constant multiplied by the displacement of the spring from its equilibrium position, the spring force can be calculated as \( F_{spring} = k * x = 20 \, lb/ft * 0.2 \, ft = 4 \, lb \).
02

Calculate the Frictional Force

The force of kinetic friction is given by \( F_{friction} = \mu_k * m * g \), where \( m \) is the mass of the object, \( g \) is the acceleration due to gravity, and \( \mu_k \) is the coefficient of kinetic friction. For block A, the friction force is \( F_{frictionA} = \mu_k * m_A * g = 0.2 * 8 \, lb = 1.6 \, lb \). For block B, the friction force is \( F_{frictionB} = \mu_k * m_B * g = 0.2 * 6 \, lb = 1.2 \, lb \).
03

Using Newton's Second Law

According to Newton's second law, the acceleration of an object is the net force acting upon it divided by its mass. Therefore, for block A, \( a_A = (F_{spring} - F_{frictionA}) / m_A = (4 lb - 1.6 lb) / 8 lb = 0.3 \, ft/s^2 \). For block B, \( a_B = (F_{spring} - F_{frictionB}) / m_B = (4 lb - 1.2 lb) / 6 lb = 0.47 \, ft/s^2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Spring Force
The concept of spring force, rooted in Hooke's Law, is crucial for understanding how springs store and release energy. Hooke's Law states that the force exerted by a spring is directly proportional to the displacement of the spring from its natural length. This force is calculated using the formula: \( F_{spring} = k \times x \). Here, \( k \) represents the spring constant, a measure of the spring's stiffness, and \( x \) denotes the displacement or compression amount. For instance, in the given problem, a spring with a constant \( k = 20 \) lb/ft is compressed by 0.2 ft, creating a spring force of \( 4 \) lb. This spring force contributes to the motion of the blocks by providing the required energy to overcome other resisting forces, such as kinetic friction. Understanding spring force allows you to predict how a spring will react under different amounts of compression or tension.
Kinetic Friction
Kinetic friction is a type of force that opposes the motion between two surfaces sliding past each other. It is crucial in dynamics because it affects the movement of objects. The force of kinetic friction is calculated using the formula: \( F_{friction} = \mu_k \times N \), where \( \mu_k \) is the coefficient of kinetic friction and \( N \) is the normal force. The normal force is generally equal to the weight of the object when it is on a horizontal surface. In our exercise, block A has a weight of 8 lb and block B has a weight of 6 lb. With a kinetic friction coefficient of 0.2, the frictional forces for block A and B are 1.6 lb and 1.2 lb respectively. This frictional force acts against the spring force, reducing the net force and, consequently, the acceleration of the blocks.
Newton's Second Law
Newton's Second Law of Motion forms the basis for analyzing dynamic systems. It asserts that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. The mathematical expression of Newton's Second Law is: \( a = \frac{F_{net}}{m} \). Here, \( a \) is the acceleration, \( F_{net} \) is the total net force acting on the object, and \( m \) is the mass of the object. In the context of the exercise, we use this law to find the acceleration of blocks A and B once they are released from the spring's compression. For block A, considering the net force as the spring force minus the friction force, we calculate the acceleration. Similarly for block B. This helps us understand how these forces work together to influence motion.

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Most popular questions from this chapter

The \(2-\mathrm{kg}\) pendulum bob moves in the vertical plane with a velocity of \(8 \mathrm{~m} / \mathrm{s}\) when \(\theta=0^{\circ} .\) Determine the initial tension in the cord and also at the instant the bob reaches \(\theta=30^{\circ} .\) Neglect the size of the bob.

A motorcyclist in a circus rides his motorcycle within the confines of the hollow sphere. If the coefficient of static friction between the wheels of the motorcycle and the sphere is \(\mu_{s}=0.4\), determine the minimum speed at which he must travel if he is to ride along the wall when \(\theta=90^{\circ}\). The mass of the motorcycle and rider is \(250 \mathrm{~kg}\), and the radius of curvature to the center of gravity is \(\rho=20 \mathrm{ft}\). Neglect the size of the motorcycle for the calculation. Prob. 13-66

The coefficient of static friction between the \(200-\mathrm{kg}\) crate and the flat bed of the truck is \(\mu_{s}=0.3\). Determine the shortest time for the truck to reach a speed of \(60 \mathrm{~km} / \mathrm{h}\), starting from rest with constant acceleration, so that the crate does not slip. Prob.

The collar has a mass of \(2 \mathrm{~kg}\) and travels along the smooth horizontal rod defined by the equiangular spiral \(r=\left(e^{\theta}\right) \mathrm{m}\), where \(\theta\) is in radians. Determine the tangential force \(F\) and the normal force \(N\) acting on the collar when \(\theta=45^{\circ}\), if the force \(F\) maintains a constant angular motion \(\dot{\theta}=2 \mathrm{rad} / \mathrm{s}\) Prob. 13-104

Block \(A\) has a mass \(m_{A}\) and is attached to a spring having a stiffness \(k\) and unstretched length \(l_{0}\). If another block \(B\), having a mass \(m_{B}\), is pressed against \(A\) so that the spring deforms a distance \(d\), show that for separation to occur it is necessary that \(d>2 \mu_{k} g\left(m_{A}+m_{B}\right) / k\), where \(\mu_{k}\) is the coefficient of kinetic friction between the blocks and the ground. Also, what is the distance the blocks slide on the surface before they separate? Probs. 13-41/42

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