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As indicated by the derivation, the principle of impulse and momentum is valid for observers in \(a n y\) inertial reference frame. Show that this is so, by considering the \(10-\mathrm{kg}\) block which slides along the smooth surface and is subjected to a horizontal force of \(6 \mathrm{~N}\). If observer \(A\) is in a fixed frame \(x\), determine the final speed of the block in 4 s if it has an initial speed of \(5 \mathrm{~m} / \mathrm{s}\) measured from the fixed frame. Compare the result with that obtained by an observer \(B\), attached to the \(x^{\prime}\) axis that moves at a constant velocity of \(2 \mathrm{~m} / \mathrm{s}\) relative to \(A\).

Short Answer

Expert verified
The final speed of the block is \(7.4m/s\) in both the stationary and moving reference frames. This validates the principle of impulse and momentum in any inertial reference frame.

Step by step solution

01

Calculation of final velocity in fixed frame

For observer \(A\) in a fixed frame, we can use the equation of motion that relates force, mass and acceleration: \(F = ma\). The force is \(6N\) and the mass is \(10kg\), so the acceleration \(a\) is \(F/m = 6N/10kg = 0.6m/s^2\). In the 4 seconds, the change in the block’s velocity due to this acceleration is \(Δv = a*t = 0.6m/s^2 * 4s = 2.4m/s\). Therefore, the final velocity of the block measured from the fixed frame, given an initial speed of \(5m/s\), is \(v = v_0 + Δv = 5m/s + 2.4m/s = 7.4m/s\).
02

Calculation of final velocity in moving frame

For observer \(B\) attached to the \(x’\) axis moving at \(2m/s\), the initial speed of the block relative to \(B\) is \(5m/s - 2m/s = 3m/s\), since relative velocities are subtracted. Over the 4 seconds, the block accelerates by the same amount \(Δv = 2.4m/s\) as before, because the force acting on it and its mass are the same. Therefore, the final velocity of the block relative to \(B\) is \(v’ = v_0’ + Δv = 3m/s + 2.4m/s = 5.4m/s\). However, because \(B\) is moving at \(2m/s\) relative to \(A\), we must add this speed to obtain the final velocity of the block as measured from the fixed frame: \(v = v’ + 2m/s = 5.4m/s + 2m/s = 7.4m/s\).
03

Comparing the results

The final speed of the block measured from the fixed frame is the same in both cases: \(7.4m/s\). This confirms that the principle of impulse and momentum is valid for observers in any inertial reference frame.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inertial Reference Frame
Understanding an inertial reference frame is crucial to grasp the principles of impulse and momentum. An inertial reference frame is essentially a viewpoint that either stays still or moves at a consistent speed without changing directions.
This means, in such a frame, objects do not experience any net external forces that could cause an acceleration. So, Newton's laws of motion, including the principle of impulse and momentum, hold true here.
In the given exercise, observer A is in a fixed inertial reference frame since no additional forces act on it other than the pre-defined parameters. This means that the calculations of force and motion dynamics are straightforward and can be calculated using standard physics formulas like F = ma. The consistency of physics in all inertial reference frames is what allows the calculation results, such as the block's final velocity, to be evaluated the same way by another observer in a different inertial frame, like observer B.
Force and Motion
Force and motion are intimately linked through Newton’s second law of motion, which states that the force applied to an object is equal to the mass of the object multiplied by its acceleration, expressed in the formula: \( F = ma \). In our exercise, this relationship helps us determine the acceleration of a block when a known force is applied.
With a block of 10 kg experiencing a horizontal force of 6 N, we can easily calculate the acceleration. By dividing the force by the mass, we get an acceleration of 0.6 m/s². This acceleration indicates how the velocity of the block will change over the course of time.
During a period of 4 seconds, the block's velocity increases due to this constant acceleration. Calculating the change in velocity, \( Δv = a \times t = 0.6 \times 4 = 2.4 \, \text{m/s} \), we see how motion is directly affected by force applied over time. If the initial velocity is known, we can then find the final velocity using \( v = v_0 + Δv \). Such straightforward calculations are possible thanks to the predictable relationship between force and motion.
Relative Velocity
Relative velocity is a concept that describes how the speed of an object changes as observed from different reference frames. This is particularly useful when observers in different frames measure the same physical process.
In the exercise, observer B moves with a constant velocity of 2 m/s relative to observer A. To find the initial speed of the block as seen by B, we subtract B's velocity from the block's velocity observed by A: \( 5 \, \text{m/s} - 2 \, \text{m/s} = 3 \, \text{m/s} \).
Despite the different initial readings, the block's acceleration due to the force remains unchanged because the force itself does not change between reference frames. Consequently, observer B observes the block accelerate by 2.4 m/s over 4 seconds, arriving at a final relative velocity of \( 5.4 \, \text{m/s} \).
Adding back B's velocity of 2 m/s gives a final velocity in line with observer A's calculations. Thus, both observers arrive at the same conclusion, demonstrating how relative velocity plays into understanding motion across different inertial frames.

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Most popular questions from this chapter

A snowblower having a scoop \(S\) with a crosssectional area of \(A_{\mathrm{s}}=0.12 \mathrm{~m}^{3}\) is pushed into snow with a speed of \(v_{s}=0.5 \mathrm{~m} / \mathrm{s}\). The machine discharges the snow through a tube \(T\) that has a cross-sectional area of \(A_{T}=0.03 \mathrm{~m}^{2}\) and is directed \(60^{\circ}\) from the horizontal. If the density of snow is \(\rho_{s}=104 \mathrm{~kg} / \mathrm{m}^{3},\) determine the horizontal force \(P\) required to push the blower forward, and the resultant frictional force \(F\) of the wheels on the ground, necessary to prevent the blower from moving sideways. The wheels roll freely.

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