/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 34 The \(300-\mathrm{kg}\) bar \(B\... [FREE SOLUTION] | 91Ó°ÊÓ

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The \(300-\mathrm{kg}\) bar \(B\), originally at rest, is being towed over a series of small rollers. Determine the force in the cable when \(t=5 \mathrm{~s}\), if the motor \(M\) is drawing in the cable for a short time at a rate of \(v=\left(0.4 t^{2}\right) \mathrm{m} / \mathrm{s},\) where \(t\) is in seconds \((0 \leq t \leq 6 \mathrm{~s}) .\) How far does the bar move in \(5 \mathrm{~s} ?\) Neglect the mass of the cable, pulley, and the rollers.

Short Answer

Expert verified
The force in the cable when t=5s is 1200N and the bar moves 33.33m in 5s.

Step by step solution

01

Calculate the Acceleration

Differentiate the velocity function \(v=0.4t^{2}\) with respect to time. This yields \(a= dv/dt = 0.8t\)
02

Calculate the Force

Substitute the value of acceleration at t=5s into the formula of Newton's second law (F=ma). So, \(F = m \cdot a = 300kg \cdot 0.8 \cdot 5s = 1200N\)
03

Calculate the Displacement

Integrate the velocity function \(v=0.4t^{2}\) from 0 to 5s to calculate the displacement: \(\int_{0}^{5} 0.4t^{2} dt = [0.4/3 \cdot t^{3}]_{0}^{5} = 33.33m\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acceleration and Force Calculation
Understanding acceleration in the context of force calculation is crucial to solving many problems in engineering mechanics dynamics. Acceleration is the rate at which an object changes its velocity. It's a vector quantity, meaning it has both magnitude and direction. In the context of the given problem, where a bar of mass is being towed, we're looking for the bar's acceleration at a specific time to calculate the force exerted on it.

First, we obtain the bar's acceleration by differentiating the velocity function, which is expressed as a function of time. Since the velocity function is given by the equation \(v=0.4t^2\), taking the derivative with respect to time gives us the acceleration at any time t: \(a= dv/dt = 0.8t\). By evaluating this at \(t=5s\), we find the acceleration at that specific moment.

Once we have the acceleration, we use Newton's second law of motion to connect force, mass, and acceleration. Newton's law tells us that force is equal to mass times acceleration \(F=ma\), so by substituting the known values of the bar's mass and its acceleration at \(t=5s\), we can calculate the towing force in the cable. Thus, force calculation is an application of the principles of dynamics that predicts how an object will behave under the influence of various forces.
Newton's Second Law of Motion
Newton's second law of motion is a cornerstone of classical mechanics which states that the acceleration of an object is directly proportional to the net force acting on the object and inversely proportional to its mass. The law is succinctly given by the equation \(F = ma\), where \(F\) is the force applied to the object, \(m\) is the mass of the object, and \(a\) is the acceleration the object undergoes.

In practical terms, when analyzing the motion of the bar being towed by the cable, we apply Newton's second law to find the net force exerted by the cable on the bar. Given that the bar's mass is \(300-\text{kg}\) and the acceleration at the time of interest (\(t=5s\)) is \(4\text{m/s}^2\), we plug these values into Newton's equation to find the force. This fundamental law joins forces with calculus to describe the motion of the bar quantitatively, offering a predictive understanding of how it will react to the applied force. Newton's second law is instrumental in engineering as it enables engineers to design systems and structures that can handle specified forces, translating the principles of physics into practical applications.
Kinematic Equations
Kinematic equations are used in physics to describe the motion of bodies without considering the forces that cause the motion. These equations relate the variables of motion - position, velocity, acceleration, and time - in a way that allows us to predict the motion of an object. In the context of our problem, calculating how far the bar moves in a given time is a classic application of kinematic principles.

The displacement of the bar, for instance, is calculated by integrating the velocity function over time. Here, we integrated the function \(v=0.4t^2\) from 0 to 5s and found the distance the bar travels to be 33.33 meters. This integration process yields the cumulative effect of the velocity over time, which translates to how much ground the bar covers while being towed.

Kinematic equations are incredibly useful tools in engineering mechanics for analyzing scenarios from simple to complex motion. Whether it's a car braking to a stop or a crane lifting an object, understanding and applying these equations enable us to predict and control motion in numerous engineering applications, ensuring safety and efficiency in the designs.

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