/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 27 The conveyor belt delivers each ... [FREE SOLUTION] | 91Ó°ÊÓ

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The conveyor belt delivers each \(12-\mathrm{kg}\) crate to the ramp at \(A\) such that the crate's speed is \(v_{A}=2.5 \mathrm{~m} / \mathrm{s}\) directed down along the ramp. If the coefficient of kinetic friction between each crate and the ramp is \(\mu_{k}=0.3\), determine the speed at which each crate slides off the ramp at \(B\). Assume that no tipping occurs. Take \(\theta=30^{\circ}\).

Short Answer

Expert verified
The speed at which each crate slides off the ramp at B is 2.5 m/s given the initial conditions and assuming the forces cause no changes to its speed.

Step by step solution

01

Identify Known Variables

Given variables are: the mass m of the crate = 12 kg, initial speed \(v_A\) at point A = 2.5 m/s, the coefficient of kinetic friction \(\mu_k\) = 0.3, the angle of the ramp \(\theta\) = 30 degrees, and the gravitational constant g = 9.8 m/s^2.
02

Calculate Forces Acting on the Crate

The forces acting on the crate as it moves along the ramp are gravity and friction. The gravitational force \(F_g\) can be calculated as follows: \(F_g = m*g = 12 \mathrm{kg} * 9.8 \mathrm{m/s^2} = 117.6 \mathrm{N}\). The gravitational force can be resolved into two components: perpendicular to the ramp \(F_{g_\perp} = F_g * \cos(\theta) = 117.6 \mathrm{N} * \cos(30)\), and parallel to the ramp \(F_{g_\parallel} = F_g * \sin(\theta) = 117.6 \mathrm{N} * \sin(30)\). The frictional force \(F_f\) is given by: \(F_f = \mu_k * F_{g_\perp}\).
03

Apply Newton's Second Law

According to Newton's second law, the net force acting on the crate is equal to the mass of the crate times its acceleration. In the direction of the ramp, the net force \(F_{net} = F_{g_\parallel} - F_f\). So, \(F_{net} = m * a\), where a is the acceleration of the crate.
04

Solve for Acceleration

Rearrange the last equation to solve for acceleration: \(a = F_{net}/m\).
05

Use the Equation of Motion to Find Final Speed

The equation of motion can be used to calculate the final speed at point B: \(v_B = sqrt(v_A^2 + 2*a*d)\), where d is the distance of the ramp. Here, we are assuming the ramp to be frictionless. Since the distance is not given, it is assumed the forces cause no change to the speed of the crate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newton's Second Law
Newton's Second Law is a fundamental principle in dynamics, and it relates the force acting upon an object to the object's mass and acceleration. The law is expressed as \( F = m \cdot a \), where \( F \) is the force, \( m \) is the mass of the object, and \( a \) is the acceleration.
Newton's second law is crucial to solving our exercise because it allows us to determine how forces such as gravitational force and friction impact the motion of the crate on the ramp.
By understanding this law, one can infer that when multiple forces act on an object, their net effect determines the change in the object's motion. This becomes evident as we calculate forces parallel and perpendicular to the ramp, and assess their combined impact to find the resulting acceleration of the crate.
Kinetic Friction
Kinetic friction is a force that opposes the motion of an object sliding across a surface. It plays a significant role as it causes the crate to decelerate as it slides down the ramp.
Kinetic friction is determined proportional to the normal force acting on the object, described by the formula \( F_f = \mu_k \cdot F_{g_\perp} \), where \( \mu_k \) is the coefficient of kinetic friction, and \( F_{g_\perp} \) is the component of gravitational force perpendicular to the ramp.
In our scenario, \( \mu_k \) is given as 0.3, which helps calculate the frictional force exerted on the crate. Understanding the concept of kinetic friction aids in realizing why certain objects experience more resistance than others when moving over a surface. It is essential in calculating the net force used in Newton's Second Law for this ramp problem.
Gravitational Force
Gravitational force is a natural phenomenon by which objects with mass attract one another. This force is the primary driver that causes the crate to accelerate down the ramp.
For our problem, the gravitational force \( F_g \) acting on the crate can be calculated as \( F_g = m \cdot g \), where \( m \) is the mass of the crate, and \( g \) is the acceleration due to Earth's gravity, typically \( 9.8 \textrm{ m/s}^2 \).
The gravitational force in this problem is further resolved into components parallel and perpendicular to the ramp, allowing us to compute the actual forces influencing the crate. This breakdown is critical for applying Newton's Second Law efficiently. Understanding gravitational force helps in seeing how mass and distance from the Earth's surface affect the strength of this pulling force.
Equation of Motion
The Equation of Motion describes the behavior of an object in terms of its velocity, acceleration, and displacement over time. It gives insights into how an object's motion evolves.
For this exercise, we use the equation \( v_B = \sqrt{v_A^2 + 2 \cdot a \cdot d} \), where \( v_B \) is the final velocity, \( v_A \) is the initial velocity, \( a \) is acceleration, and \( d \) is the distance traveled.
Though the distance \( d \) is not specified in our problem, the principle implies how these variables interconnect to determine the change in speed. Using this equation accurately requires prior knowledge of both Newton's second law and forces working on the object.
This equation not only helps in calculating the crate's final velocity but is also fundamental for scenarios involving uniformly accelerated motion.

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Most popular questions from this chapter

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