/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 The \(400-\mathrm{kg}\) mine car... [FREE SOLUTION] | 91Ó°ÊÓ

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The \(400-\mathrm{kg}\) mine car is hoisted up the incline using the cable and motor \(M\). For a short time, the force in the cable is \(F=\left(3200 t^{2}\right) \mathrm{N},\) where \(t\) is in seconds. If the car has an initial velocity \(v_{1}=2 \mathrm{~m} / \mathrm{s}\) when \(t=0\), determine its velocity when \(t=2 \mathrm{~s}\)

Short Answer

Expert verified
The velocity of the car at \(t = 2s\) is \(66 m/s\).

Step by step solution

01

Determination of acceleration

Start by identifying what you know. We know that force \(F = 3200t^2 N\), mass \(m = 400 kg\) and \(F = ma\). Rearranging for acceleration, we get \(a = F/m\). Substituting the values of \(F\) and \(m\) into the acceleration equation, we get \(a = 3200t^2/400 = 8t^2 m/s^2\).
02

Calculation of acceleration at t = 2s

Substitute \(t = 2s\) into the equation for acceleration we derived to get the acceleration at \(t=2s\). The calculation is as follows: \(a = 8(2^2) m/s^2 = 32 m/s^2\).
03

Calculation of velocity at t = 2s

Now, using the equation for velocity \(v_2 = v_1 + at\), where \(v_1 = 2m/s\) is the initial velocity, \(a = 32 m/s^2\) is the acceleration, and \(t = 2s\), substitute these values into the equation to calculate \(v_2\). Hence, \(v_2 = 2 + 32*2 = 2 + 64 = 66 m/s\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newton's Second Law
Newton's Second Law of Motion is a fundamental principle that relates the force applied to an object, its mass, and the resulting acceleration. This law can be formulated as \( F = ma \), where \( F \) is the force in newtons (N), \( m \) is the mass of the object in kilograms (kg), and \( a \) is the acceleration in meters per second squared (\( m/s^2 \)).

In the mine car acceleration problem, the force exerted by the motor through the cable causes the car to accelerate in accordance with Newton's second law. Here, the mine car's mass is given as 400 kg, and the force is a function of time, \( F(t) = 3200t^2 \). As the force changes with time, the acceleration of the car is not constant. It's important to understand that in real-world problems like this, forces can change over time, affecting the acceleration accordingly.
Kinematics Equations
Kinematics is the branch of physics that deals with motion without considering the forces that cause the motion. The kinematics equations enable us to relate the variables of motion – displacement, velocity, acceleration, and time – without the need for understanding the underlying forces.

One such equation that's often used when dealing with constant acceleration is \( v_2 = v_1 + at \). Here, \( v_2 \) is the final velocity, \( v_1 \) is the initial velocity, \( a \) is the constant acceleration, and \( t \) is the time. During the mine car problem, we use this kinematics equation to find the velocity of the car after 2 seconds, given its initial velocity and calculated acceleration.
Force and Motion
The concepts of force and motion are tightly intertwined in physics. Force causes an object to accelerate, which is a change in its velocity – and velocity is a vector quantity that defines the speed and direction of motion.

In this context, the force exerted by the motor on the mine car through the cable causes the car to move upward along the incline. This force is not constant but varies with time as \( F = 3200t^2 \). The exercise demonstrates how varying forces influence the motion of objects and how we can calculate the resulting changes in velocity using the kinematics equation.
Acceleration Calculation
Acceleration is defined as the rate at which an object's velocity changes with time. In mathematical terms, it is the derivative of velocity with respect to time. For practical calculations, when acceleration is constant, it can be calculated simply as \( a = \frac{\Delta v}{\Delta t} \), where \( \Delta v \) is the change in velocity and \( \Delta t \) is the change in time.

However, in our mine car problem, the acceleration is not constant, but instead varies as a function of time, \( a(t) = 8t^2 \). By plugging the relevant time into the acceleration function, we can determine the instantaneous acceleration at that moment, which allows us to subsequently compute the car's velocity at any given time using the kinematics equations.

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Most popular questions from this chapter

Prove that if the block is released from rest at point \(B\) of a smooth path of arbitrary shape, the speed it attains when it reaches point \(A\) is equal to the speed it attains when it falls freely through a distance \(h\); i.e., \(v=\sqrt{2 g h}\).

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