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Viscous damping is added to an initially undamped spring-mass system. For what value of the damping ratio \(\zeta\) will the damped natural frequency \(\omega_{d}\) be equal to 90 percent of the natural frequency of the original undamped system?

Short Answer

Expert verified
\( \zeta \approx 0.436 \).

Step by step solution

01

Identify the Relationship Between Damped and Natural Frequencies

The damped natural frequency \( \omega_d \) is defined in terms of the undamped natural frequency \( \omega_n \) and the damping ratio \( \zeta \). This relationship is given by the formula \( \omega_d = \omega_n \sqrt{1 - \zeta^2} \).
02

Set the Damped to Undamped Frequency Ratio to 90%

According to the problem, \( \omega_d \) is 90% of \( \omega_n \). Therefore, we set up the equation \( \omega_d = 0.9 \omega_n \).
03

Substitute the Known Values

Substitute \( \omega_d = 0.9 \omega_n \) into \( \omega_d = \omega_n \sqrt{1 - \zeta^2} \). The equation becomes \( 0.9 \omega_n = \omega_n \sqrt{1 - \zeta^2} \).
04

Simplify the Equation

Divide both sides of the equation by \( \omega_n \), resulting in \( 0.9 = \sqrt{1 - \zeta^2} \).
05

Solve for the Damping Ratio \( \zeta \)

Square both sides to remove the square root: \( 0.81 = 1 - \zeta^2 \). Rearrange to solve for \( \zeta^2 \): \( \zeta^2 = 1 - 0.81 \). This simplifies to \( \zeta^2 = 0.19 \).
06

Find the Value of \( \zeta \)

Take the square root of both sides to solve for \( \zeta \): \( \zeta = \sqrt{0.19} \). Calculating gives \( \zeta \approx 0.43589 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Spring-Mass System
A spring-mass system is a fundamental concept in mechanical vibrations, involving a mass attached to a spring. This simple system is used to model the behavior of more complex mechanical systems. The spring provides a restoring force that is proportional to the displacement of the mass from its equilibrium position.
The basic characteristics of a spring-mass system include:
  • Spring Constant, \(k\): This measures the stiffness of the spring. A larger value indicates a stiffer spring.
  • Mass, \(m\): The object that experiences vibrations when displaced from its equilibrium.
Understanding this system lays the groundwork for analyzing more advanced concepts such as damping and natural frequencies.
The motion of a spring-mass system without any external forces or damping is described by simple harmonic motion, characterized by sinusoidal waveforms.
Damping Ratio
The damping ratio, denoted as \(\zeta\), is a dimensionless measurement used to describe how oscillations in a system decay over time. It plays a crucial role in determining the nature of the system’s response.
Damping can be categorized into several types, such as underdamped, critically damped, and overdamped, each defined by the value of \(\zeta\):
  • Underdamped (\(\zeta < 1\)): The system oscillates with gradually decreasing amplitude.
  • Critically Damped (\(\zeta = 1\)): The system returns to equilibrium in the shortest possible time without oscillating.
  • Overdamped (\(\zeta > 1\)): The system returns to equilibrium without oscillating, but more slowly than the critically damped case.
The damping ratio thus helps in assessing whether the oscillations will persist over time or diminish quickly.
Natural Frequency
Natural frequency, represented as \(\omega_n\), is the rate at which a system tends to oscillate in the absence of any driving or damping force. For a spring-mass system, it is a fundamental property based on the mass and stiffness of the spring.
The formula to determine natural frequency is:\[\omega_n = \sqrt{\frac{k}{m}}\]where \(k\) is the spring constant, and \(m\) is the mass.
The natural frequency is reflective of the system's inherent ability to resonate. When external forces match this frequency, resonance can occur, leading to larger amplitude oscillations. Understanding natural frequency is essential as it allows us to predict how a system will respond under various conditions.
Viscous Damping
Viscous damping is a type of damping mechanism where the force is proportional to the velocity of the moving object. It acts as a "drag" force that removes energy from the system, reducing the amplitude of oscillations over time.
In practical applications, viscous damping is crucial for controlling vibrations to prevent structural damage or ensure comfort and stability.
Key aspects include:
  • Damping Force: Proportional to velocity. Given by \(c \, \dot{x}\), where \(c\) is the damping coefficient and \(\dot{x}\) is the velocity.
  • Effect on Frequency: Affects the damped natural frequency \(\omega_d\), which is always less than the undamped natural frequency \(\omega_n\).
Viscous damping is a crucial factor in designing systems that need to minimize sustain and rapid decay in vibrations.

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Most popular questions from this chapter

Determine the amplitude of vertical vibration of the car as it travels at a velocity \(v=40 \mathrm{km} / \mathrm{h}\) over the wavy road whose contour may be expressed as a sine or cosine function with a double amplitude \(2 b=50 \mathrm{mm} .\) The mass of the car is \(1800 \mathrm{kg}\) and the stiffness of each of the four car springs is \(35 \mathrm{kN} / \mathrm{m}\) Assume that all four wheels are in continuous con- tact with the road, and neglect damping. Note that the wheelbase of the car and the spatial period of the road are the same at \(L=3 \mathrm{m},\) so that it may be assumed that the car translates but does not rotate. At what critical speed \(v_{c}\) is the vertical vibration of the car at its maximum?

During the design of the spring-support system for the 4000 -kg weighing platform, it is decided that the frequency of free vertical vibration in the unloaded condition shall not exceed 3 cycles per second. (a) Determine the maximum acceptable spring constant \(k\) for each of the three identical springs. (b) For this spring constant, what would be the natural frequency \(f_{n}\) of vertical vibration of the platform loaded by the 40 -Mg truck?

The block of weight \(W=100\) lb is suspended by two springs each of stiffness \(k=200 \mathrm{lb} / \mathrm{ft}\) and is acted upon by the force \(F=75 \cos 15 t\) lb where \(t\) is the time in seconds. Determine the amplitude \(X\) of the steady-state motion if the viscous damping coefficient \(c\) is \((a) 0\) and (b) 60 lb-sec/ft. Compare these amplitudes to the static spring deflection \(\delta_{\mathrm{st}}\)

Derive the equation of motion for the system shown in terms of the displacement \(x\). The masses are coupled through the light connecting rod \(A B C\) which pivots about the smooth bearing at point \(O .\) Neglect all friction, consider the rollers on \(m_{2}\) and \(m_{3}\) to be light, and assume small oscillations about the equilibrium position. State the system natural circular frequency \(\omega_{n}\) and the viscous damping ratio \(\zeta\) for \(m_{1}=15 \mathrm{kg}, m_{2}=12 \mathrm{kg}, m_{3}=8 \mathrm{kg}, k_{1}=400 \mathrm{N} / \mathrm{m}\) \(k_{2}=650 \mathrm{N} / \mathrm{m}, k_{3}=225 \mathrm{N} / \mathrm{m}, c_{1}=44 \mathrm{N} \cdot \mathrm{s} / \mathrm{m}, c_{2}=\) \(36 \mathrm{N} \cdot \mathrm{s} / \mathrm{m}, c_{3}=52 \mathrm{N} \cdot \mathrm{s} / \mathrm{m}, a=1.2 \mathrm{m}, b=1.8 \mathrm{m},\) and \(c=0.9 \mathrm{m}\)

A spring-mounted machine with a mass of \(24 \mathrm{kg}\) is observed to vibrate harmonically in the vertical direction with an amplitude of \(0.30 \mathrm{mm}\) under the action of a vertical force which varies harmonically between \(F_{0}\) and \(-F_{0}\) with a frequency of \(4 \mathrm{Hz}\) Damping is negligible. If a static force of magnitude \(F_{0}\) causes a deflection of \(0.60 \mathrm{mm},\) calculate the equivalent spring constant \(k\) for the springs which support the machine.

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