/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 105 The blades and hub of the helico... [FREE SOLUTION] | 91Ó°ÊÓ

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The blades and hub of the helicopter rotor weigh 140 lb and have a radius of gyration of \(10 \mathrm{ft}\) about the \(z\) -axis of rotation. With the rotor turning at 500 rev/min during a short interval following vertical liftoff, the helicopter tilts forward at the rate \(\dot{\theta}=10\) deg/sec in order to acquire forward velocity. Determine the gyroscopic moment \(M\) transmitted to the body of the helicopter by its rotor and indicate whether the helicopter tends to deflect clockwise or counterclockwise, as viewed by a passenger facing forward.

Short Answer

Expert verified
The gyroscopic moment is approximately 3956.42 ft.lb, causing a clockwise deflection as viewed by a forward-facing passenger.

Step by step solution

01

Convert RPM to Rad/sec

First, convert the angular velocity of the rotor from revolutions per minute (RPM) to radians per second (rad/sec). The formula is \[\omega = \text{RPM} \times \frac{2\pi}{60}\]Given RPM = 500, we have:\[\omega = 500 \times \frac{2\pi}{60} = \frac{500 \times 2 \pi}{60} \approx 52.36 \text{ rad/sec}\]
02

Convert Angular Rate to Rad/sec

Next, convert the tilt rate \( \dot{\theta} \) from degrees per second to radians per second. The formula is \[\dot{\theta}_{\text{rad/sec}} = \dot{\theta}_{\text{deg/sec}} \times \frac{\pi}{180}\]Given \( \dot{\theta} = 10 \text{ deg/sec} \), we have:\[\dot{\theta}_{\text{rad/sec}} = 10 \times \frac{\pi}{180} \approx 0.1745 \text{ rad/sec}\]
03

Calculate the Moment of Inertia

Calculate the moment of inertia \( I \) of the rotor about the \( z \)-axis using the radius of gyration, \( k \). The formula is \[I = m k^2\]First, convert the weight to mass (lb to slugs) using the relation \( m = \frac{W}{g} \). Given the weight \( W = 140 \text{ lb} \) and gravity \( g = 32.2 \text{ ft/sec}^2 \),\[m = \frac{140}{32.2} \approx 4.35 \text{ slugs}\]Therefore, the moment of inertia is:\[I = 4.35 \times (10^2) = 435 \text{ slug.ft}^2\]
04

Find the Gyroscopic Moment

The gyroscopic moment \( M \) can be calculated using the formula for gyroscopic precession:\[M = I \omega \dot{\theta}\]Substitute the known values:\[M = 435 \times 52.36 \times 0.1745 \approx 3956.42 \text{ ft.lb}\]
05

Determine Direction of Deflection

The direction of the gyroscopic moment can be determined using the right-hand rule. Given that the helicopter tilts forward (\( \dot{\theta} > 0 \)), the gyroscopic effect will act perpendicular to this motion. For a forward tilt and the rotor spinning clockwise (as viewed from above), the gyroscopic moment will tilt the helicopter clockwise when viewed by a passenger facing forward.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Velocity
Angular velocity is a measure of how fast an object rotates or spins around an axis. It's about how quickly the angular position changes with time and is typically measured in radians per second. - **Conversion from RPM:** - To use angular velocity in calculations, we must often convert from revolutions per minute (RPM) to radians per second. - The conversion is done using the formula: \[ \omega = \text{RPM} \times \frac{2\pi}{60} \] - Using this formula, a rotor speed of 500 RPM becomes approximately 52.36 rad/sec. This step is crucial for accurate calculations.When dealing with real-world applications like helicopter dynamics, understanding and calculating angular velocity correctly helps in predicting how the vehicle will behave during maneuvers.
Moment of Inertia
The moment of inertia (\(I\)) is a physical quantity that determines how a body resists angular acceleration about an axis. Think of it as the rotational equivalent of mass in linear motion. It shows how difficult it is to change the rotational motion of an object.- **Formula and Calculation:** - The moment of inertia depends on the mass distribution relative to the rotation axis, given by\[ I = m k^2 \]where\(m\) is the mass and\(k\) is the radius of gyration. - Convert weight from pounds to mass in slugs using:\[ m = \frac{W}{g} \] - For the helicopter rotor, with weight 140 lb and radius of gyration 10 ft, the moment of inertia calculates to 435 slug.ft².Evaluating moment of inertia is essential to understanding how forces will affect the rotational motion of parts, like the helicopter rotor in our exercise.
Gyroscopic Precession
Gyroscopic precession is a fascinating effect where the axis of a rotating body, like a helicopter rotor, experiences a change in orientation when subjected to an external force. This gyroscopic effect is key to stability and control in systems using rotating masses.- **Understanding Precession:** - Precession is the result of angular momentum conservation governed by the formula:\[ M = I \omega \dot{\theta} \]where\(M\) is the moment of force,\(\omega\) is the angular velocity, and\(\dot{\theta}\) is the rate of tilt. - In our scenario, the rotor generates a gyroscopic moment of about 3956.42 ft.lb when the helicopter tilts at 10°/s.Mastering gyroscopic precession is critical because it allows engineers and pilots to predict how rotational forces affect maneuverability and stability.
Helicopter Dynamics
Helicopter dynamics is a complex yet crucial area of study that involves understanding how forces affect a helicopter's flight. Gyroscopic effects play a significant role in a helicopter's responsiveness to pilot inputs. - **Key Components:** - **Rotor Systems:** The main rotor dynamics are affected by elements like angular velocity and gyroscopic precession. - **Gyroscopic Moments:** As helicopters maneuver, gyroscopic moments influence movements such as forward tilting. - **Practical Implications:** - The gyroscopic moment resulting from rotor motion is a determinant of helicopter behavior, influencing aspects like directional stability. - In the given exercise, the moment results in the helicopter tilting clockwise, seen from the passenger perspective, when observed due to angular velocity and precession effects. Understanding these dynamics ensures that helicopter systems are designed for optimal control, stability, and aircraft safety.

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Most popular questions from this chapter

Each of the slender rods of length \(l\) and mass \(m\) is welded to the circular disk which rotates about the vertical \(z\) -axis with an angular velocity \(\omega .\) Each rod makes an angle \(\beta\) with the vertical and lies in a plane parallel to the \(y-z\) plane. Determine an expression for the angular momentum \(\mathbf{H}_{O}\) of the two rods about the origin \(O\) of the axes.

The helicopter is nosing over at the constant rate \(q\) rad/s. If the rotor blades revolve at the constant speed \(p\) rad/s, write the expression for the angular acceleration \(\alpha\) of the rotor. Take the \(y\) -axis to be attached to the fuselage and pointing forward perpendicular to the rotor axis.

The assembly, consisting of the solid sphere of mass \(m\) and the uniform rod of length \(2 c\) and equal mass \(m,\) revolves about the vertical \(z\) -axis with an angular velocity \(\omega .\) The rod of length \(2 c\) has a diameter which is small compared with its length and is perpendicular to the horizontal rod to which it is welded with the inclination \(\beta\) shown. Determine the combined angular momentum \(\mathbf{H}_{O}\) of the sphere and inclined rod.

The flight simulator is mounted on six hydraulic actuators connected in pairs to their attachment points on the underside of the simulator. By programming the actions of the actuators, a variety of flight conditions can be simulated with translational and rotational displacements through a limited range of motion. Axes \(x-y-z\) are attached to the simulator with origin \(B\) at the center of the volume. For the instant represented, \(B\) has a velocity and an acceleration in the horizontal \(y\) -direction of \(3.2 \mathrm{ft} / \mathrm{sec}\) and \(4 \mathrm{ft} / \mathrm{sec}^{2},\) respectively. Simultaneously, the angular velocities and their time rates of change are \(\omega_{x}=1.4 \mathrm{rad} / \mathrm{sec}, \dot{\omega}_{x}=2 \mathrm{rad} / \mathrm{sec}^{2}, \omega_{y}=1.2 \mathrm{rad} / \mathrm{sec}\) \(\dot{\omega}_{y}=3 \mathrm{rad} / \mathrm{sec}^{2}, \omega_{z}=\dot{\omega}_{z}=0 .\) For this instant determine the magnitudes of the velocity and acceleration of point \(A\)

The housing of the electric motor is freely pivoted about the horizontal \(x\) -axis, which passes through the mass center \(G\) of the rotor. If the motor is turning at the constant rate \(\dot{\phi}=p,\) determine the angular acceleration \(\ddot{\psi}\) which will result from the application of the moment \(M\) about the vertical shaft if \(\dot{\gamma}=\dot{\psi}=0 .\) The mass of the frame and housing is considered negligible compared with the mass \(m\) of the rotor. The radius of gyration of the rotor about the \(z\) -axis is \(k_{z}\) and that about the \(x\) -axis is \(k_{x}\)

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