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The frictional moment \(M_{f}\) acting on a rotating turbine disk and its shaft is given by \(M_{f}=k \omega^{2}\) where \(\omega\) is the angular velocity of the turbine. If the source of power is cut off while the turbine is running with an angular velocity \(\omega_{0},\) determine the time \(t\) for the speed of the turbine to drop to one-half of its initial value. The moment of inertia of the turbine disk and shaft is \(I\)

Short Answer

Expert verified
The time \(t\) is \(\frac{I}{k \omega_{0}}\) for the turbine's speed to drop to half its initial value.

Step by step solution

01

Define Given Variables and Known Equation

The problem states that the frictional moment is given by \(M_{f} = k \omega^{2}\). We also know that the moment of inertia is \(I\), and the initial angular velocity is \(\omega_{0}\). We need to find the time \(t\) when the angular velocity is halved, i.e., \(\omega = \frac{\omega_{0}}{2}\).
02

Draw the Rotational Kinetic Equation Relation

The torque due to friction, \(M_{f} = k \omega^{2}\), results in a deceleration of the turbine. Using Newton's second law for rotation, the angular deceleration \(\alpha\) is \(\alpha = \frac{M_{f}}{I} = \frac{k \omega^{2}}{I}\).
03

Formulate the Differential Equation for Angular Velocity

Set up the differential equation for angular velocity: \(-I \frac{d\omega}{dt} = k \omega^{2}\). This results in \(\frac{d\omega}{\omega^2} = -\frac{k}{I} dt\) after rearranging terms. This differential equation can be solved by integrating both sides.
04

Integrate the Equation

Integrate both sides of the equation: \(\int_{\omega_{0}}^{\omega} \frac{d\omega}{\omega^2} = -\frac{k}{I} \int_{0}^{t} dt\), leading to \([ -\frac{1}{\omega}]_{\omega_{0}}^{\frac{\omega_{0}}{2}} = -\frac{k}{I} t\).
05

Solve the Integrated Equation

Calculate the left hand side of the equation: \(-\frac{1}{\frac{\omega_{0}}{2}} + \frac{1}{\omega_{0}} = -\frac{1}{\omega_{0}}\). Therefore, \(-\frac{1}{\omega_{0}/2} + \frac{1}{\omega_{0}} = \frac{2}{\omega_{0}} - \frac{1}{\omega_{0}} = \frac{1}{\omega_{0}}\).
06

Find Time t for Half-Speed

Substitute back into \(-\frac{1}{\omega} + \frac{1}{\omega_{0}} = -\frac{k}{I} t\), so we find \(\frac{1}{\frac{\omega_{0}}{2}} - \frac{1}{\omega_{0}} = \frac{k}{I} t\), hence \(t = \frac{I}{k \omega_{0}}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Deceleration
Angular deceleration is the rate at which the angular velocity of a rotating object decreases over time. When dealing with problems related to rotational dynamics, such as a turbine slowing down due to friction, understanding angular deceleration becomes crucial.
In the given problem, the angular deceleration, denoted by \( \alpha \), is produced by the frictional moment acting on the turbine disk.
Using Newton's second law for rotation, we know that \( \alpha = \frac{M_f}{I} \), where \( M_f = k \omega^2 \) and \( I \) is the moment of inertia of the disk and shaft combination.
Thus, \( \alpha = \frac{k \omega^2}{I} \).
  • This equation signifies that the angular deceleration is directly proportional to the square of angular velocity \( \omega \), leading to rapid deceleration as \( \omega \) increases.
  • The larger the frictional moment (dependent on \( k \omega^2 \)), the greater the deceleration force acting against the rotational motion, slowing it down quicker.
Moment of Inertia
The moment of inertia, represented by \( I \), is a measure of an object's resistance to changes in its rotation. It plays a similar role in rotational dynamics as mass does in linear motion, indicating how much torque is needed for a desired angular acceleration.
In the context of the turbine problem, \( I \) describes how the mass distribution of the disk and shaft affects its rotational behavior.
A higher moment of inertia suggests that the object will decelerate slower under the same frictional conditions.
  • Moment of inertia depends heavily on the distribution of mass relative to the axis of rotation. Closer mass distribution leads to a smaller \( I \), while farther distribution results in a larger \( I \).
  • It is a crucial factor in determining how quickly a rotating system, like our turbine, responds to applied torques, whether for acceleration or deceleration.
Understanding moment of inertia is essential to solving rotational dynamics problems as it provides insight into the system's inertia, affecting its angular velocity changes under external forces.
Differential Equation Integration
In problems involving changing variables over time, differential equations serve as powerful tools, particularly in analyzing rotational motion where variables like angular velocity change dynamically.
For our turbine exercise, integrating a differential equation was necessary to determine the time it takes for the speed to halve.
The starting differential equation was derived from the relation \( -I \frac{d\omega}{dt} = k \omega^2 \).This equation balances the frictional torque and the moment of inertia to model the system's deceleration.
  • To solve, both sides of the differential equation were integrated: \( \int_{\omega_0}^{\omega} \frac{d\omega}{\omega^2} = -\frac{k}{I} \int_{0}^{t} dt \), simplifying to \( -\left[\frac{1}{\omega}\right]_{\omega_0}^{\frac{\omega_0}{2}} = -\frac{k}{I} t \).
  • Integration processes helped unfold the relationship between time \( t \) and the decay of \( \omega \), eventually giving \( t = \frac{I}{k \omega_0} \) for \( \omega = \frac{\omega_0}{2} \).
Through integration, the dynamics of the system become clear, showing that differential calculus is indispensable in analyzing systems experiencing deceleration under constant changing forces like friction.

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Most popular questions from this chapter

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