/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 213 The two mine cars of equal mass ... [FREE SOLUTION] | 91Ó°ÊÓ

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The two mine cars of equal mass are connected by a rope which is initially slack. Car \(A\) is given a shove which imparts to it a velocity of \(4 \mathrm{ft} / \mathrm{sec}\) with \(\operatorname{car} B\) initially at rest. When the slack is taken up, the rope suffers a tension impact which imparts a velocity to car \(B\) and reduces the velocity of car \(A\). (a) If 40 percent of the kinetic energy of car \(A\) is lost during the rope impact, calculate the velocity \(v_{B}\) imparted to car \(B\) (b) Following the initial impact, car \(B\) overtakes car \(A\) and the two are coupled together. Calculate their final common velocity \(v_{C}\).

Short Answer

Expert verified
The velocity imparted to car B is 0.9 ft/s, and the final common velocity is 2 ft/s.

Step by step solution

01

Determine Initial Kinetic Energy of Car A

The initial kinetic energy of car A can be calculated using the formula for kinetic energy, \( KE = \frac{1}{2}mv^2 \). Since we don't have the mass, we can represent it as \( m \) and write the initial kinetic energy as \( KE_A = \frac{1}{2}m(4)^2 \). Simplifying, \( KE_A = 8m \).
02

Calculate Kinetic Energy Lost by Car A

Since 40% of the initial kinetic energy is lost during the rope impact, the energy lost is \( 0.4 \times 8m = 3.2m \). Thus, the kinetic energy after impact is \( KE_{A, final} = 8m - 3.2m = 4.8m \).
03

Determine Final Velocity of Car A after Impact

Using the kinetic energy formula \( KE = \frac{1}{2}mv^2 \) again for car A's final kinetic energy, we set it equal to \( 4.8m \). Solving for the final velocity \( v_{A, final} \), \( \frac{1}{2}m(v_{A, final})^2 = 4.8m \), simplifies to \( (v_{A, final})^2 = 9.6 \), so \( v_{A, final} = \sqrt{9.6} \approx 3.1 \) ft/s.
04

Apply Conservation of Momentum

Before the impact, car A has momentum \( mv_A \) and car B has none. After the impact, the momentum is shared: \( mv_{A, final} + mv_B = mv_A \). Substitute values: \( m(3.1) + mv_B = m(4) \). Simplifying, \( v_B = 4.0 - 3.1 = 0.9 \) ft/s.
05

Calculate Final Common Velocity after Coupling

When car B overtakes car A and they couple, use the conservation of momentum: \( m(v_{A, final}) + m(v_B) = 2m(v_C) \). Substitute the known values to find \( v_C \): \( 3.1 + 0.9 = 2v_C \). Simplifying, \( v_C = \frac{4}{2} = 2 \) ft/s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy is an important concept in mechanics that refers to the energy an object possesses due to its motion. It is calculated using the formula: \[ \text{KE} = \frac{1}{2}mv^2 \] where \( m \) is the mass of the object and \( v \) is its velocity. This formula tells us that kinetic energy is directly proportional to both the mass of the object and the square of its velocity.
In our exercise, car A starts with an initial velocity of \( 4 \, \text{ft/sec} \). Hence, its initial kinetic energy is \( 8m \) (as \( KE_A = \frac{1}{2}m(4)^2 \)). When the rope takes up slack and imparts velocity to car B, 40% of car A's kinetic energy is lost, leaving it with \( 4.8m \) kinetic energy.
This loss of energy results from the conversion into other forms such as heat or sound during the impact. Understanding kinetic energy helps us in evaluating how energy is distributed between car A and car B during this exchange.
Conservation of Momentum
The principle of conservation of momentum is a fundamental concept in mechanics, stating that the total momentum of a closed system remains constant if no external forces act on it. Momentum is defined as the product of an object's mass and velocity: \[ p = mv \]
In the context of our problem, consider momentum is transferred from car A to car B upon the rope's impact. Before the impact, car A has a momentum of \( mv_A \) while car B is stationary and has zero momentum. Post-impact, the momentum is shared between the two cars. According to the law of conservation of momentum:\[ mv_{A, \text{final}} + mv_B = mv_A \]
By substituting known values, we discovered car B's velocity, \( v_B = 0.9 \, \text{ft/sec} \). Here the momentum lost by car A is exactly gained by car B, showing a practical example of how conservation works in real scenarios.
  • Momentum is conserved, despite kinetic energy being lost.
  • This is pivotal in understanding collisional interactions.
Velocity Calculation
Calculating velocities in different stages of an interaction helps in understanding outcomes more clearly. Our original exercise showcases how velocity changes due to kinetic energy loss and momentum conservation.
After the initial energy transfer, car A's final velocity post-impact, \( v_{A, \text{final}} \), is \( 3.1 \, \text{ft/sec} \) using:\[ KE_{A, \text{final}} = \frac{1}{2}m(v_{A, \text{final}})^2 \] By solving, \( v_{A, \text{final}} = \sqrt{9.6} \)
Later, as car B overtakes and couples with car A, both cars move with a final common velocity, \( v_C \), calculated using the conservation of momentum:\[ 3.1 + 0.9 = 2v_C \] After rearranging and solving, this results in \( v_C = 2 \, \text{ft/sec} \).
  • Each stage of motion provides insight into how forces and energy influence speed.
  • Velocity calculation is key to concluding dynamic interactions in mechanics.

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