/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 175 A jet-propelled airplane with a ... [FREE SOLUTION] | 91Ó°ÊÓ

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A jet-propelled airplane with a mass of \(10 \mathrm{Mg}\) is flying horizontally at a constant speed of \(1000 \mathrm{km} / \mathrm{h}\) under the action of the engine thrust \(T\) and the equal and opposite air resistance \(R\). The pilot ignites two rocket-assist units, each of which develops a forward thrust \(T_{0}\) of \(8 \mathrm{kN}\) for \(9 \mathrm{s}\). If the velocity of the airplane in its horizontal flight is \(1050 \mathrm{km} / \mathrm{h}\) at the end of the \(9 \mathrm{s}\), calculate the timeaverage increase \(\Delta R\) in air resistance. The mass of the rocket fuel used is negligible compared with that of the airplane.

Short Answer

Expert verified
The average increase in air resistance \(\Delta R\) is 600 N.

Step by step solution

01

Convert Units

Start by converting the airplane's speed from kilometers per hour to meters per second. The initial speed is \(1000 \text{ km/h}\). Conversion factor: \[1 \text{ km/h} = \frac{1000}{3600} \text{ m/s} \approx 0.278 \text{ m/s} \]Thus, \(1000 \text{ km/h} = 1000 \times 0.278 \text{ m/s} = 277.78 \text{ m/s}\).The final speed is \(1050 \text{ km/h}\), which is:\(1050 \times 0.278 \text{ m/s} = 291.67 \text{ m/s}\).
02

Calculate Acceleration

The change in velocity \(\Delta v\) over time \(t\) is used to calculate acceleration.Given:- Initial velocity \(v_i = 277.78 \text{ m/s}\)- Final velocity \(v_f = 291.67 \text{ m/s}\)- Time \(t = 9 \text{ s}\)Using the formula for acceleration \(a = \frac{\Delta v}{t}\):\[a = \frac{291.67 - 277.78}{9} = \frac{13.89}{9} \approx 1.54 \text{ m/s}^2\]
03

Determine Total Thrust Force

Each rocket thrusts \(T_0 = 8000 \text{ N}\), and there are two rockets.Total thrust by rockets: \[F_{\text{thrust}} = 2 \times 8000 = 16000 \text{ N}\]
04

Apply Newton's Second Law

According to Newton's second law, the net force is equal to the mass times acceleration. The airplane mass is \(10 \text{ Mg} = 10,000 \text{ kg}\).The net force is:\[F_{\text{net}} = m \cdot a = 10000 \times 1.54 = 15400 \text{ N}\]
05

Calculate Increase in Air Resistance \(\Delta R\)

The total force produced by the rockets \(F_{\text{thrust}}\) minus the net force \(F_{\text{net}}\) is the average increase in air resistance.\[\Delta R = F_{\text{thrust}} - F_{\text{net}} = 16000 - 15400 = 600 \text{ N}\]
06

Conclusion

The time-average increase in air resistance during the 9 seconds of rocket thrust is \(\Delta R = 600 \text{ N}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Acceleration in Rocket Motion
Acceleration plays a crucial role in understanding how objects like airplanes change speed when additional forces are applied. It is defined as the rate at which an object's velocity changes. When looking at an airplane equipped with additional rocket units, like in the original exercise, we deal with two main velocity points: the initial and the final.
The acceleration of the airplane is calculated using the formula:\[a = \frac{\Delta v}{t}\]where:
  • \(\Delta v\) is the change in velocity,
  • \(t\) is the time over which this change occurs.
In the exercise, the initial speed of the airplane was 277.78 m/s and, after 9 seconds, the speed increased to 291.67 m/s when additional thrust was applied by the rockets. This resulted in an acceleration of approximately 1.54 m/s².
Acceleration tells us how quickly speed increases, essential for flight dynamics and achieving a stable trajectory.
Air Resistance and Its Impact on Flight
Air resistance, also known as drag, is a force that opposes the motion of an object through the air. It's an essential concept in aerodynamics that affects vehicles and high-speed aircraft. When an airplane is in motion, air resistance works directly against it, reducing its speed if not offset by other forces.
In our exercise, the airplane initially faced an air resistance equal to the engine thrust, allowing it to fly at a constant speed. However, when rocket thrust was initiated, the situation changed. The additional force from the rockets increased the speed, thereby also increasing the air resistance.
Air resistance is not constant; it varies with the speed of the object. As speed increases, so does air resistance. Thus, when the airplane's speed increased by using rockets, more force was needed to balance the increasing air resistance. The exercise calculated the average increase in air resistance, \(\Delta R\), to be 600 N during the 9 seconds of thrust.
Understanding Rocket Thrust in the Context of Newton's Second Law
Rocket thrust is crucial in altering an aircraft's velocity. It provides the forward force needed to increase speed or maintain motion against air resistance. Rocket thrust, in simple terms, is the force exerted by the expelled gases; this force propels the aircraft in the opposite direction.
For our airplane example, two rockets, each providing a thrust of 8,000 N, are attached. This additional force creates a combined thrust of 16,000 N, contributing significantly to the net force acting on the airplane.
Applying Newton's Second Law, we know that:\[F_{\text{net}} = m \cdot a\]where:
  • \(F_{\text{net}}\) is the net force,
  • \(m\) is the mass of the airplane (10,000 kg for this airplane),
  • \(a\) is the acceleration (1.54 m/s² as calculated earlier).
Thus, the net force required for this increased acceleration was calculated to be 15,400 N. The thrust had to overcome this net force and the increased air resistance to maintain the new speed, with the excess accounted as additional air resistance, calculated earlier as 600 N.

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Most popular questions from this chapter

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