/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 129 In a railroad classification yar... [FREE SOLUTION] | 91Ó°ÊÓ

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In a railroad classification yard, a 68 -Mg freight car moving at \(0.5 \mathrm{m} / \mathrm{s}\) at \(A\) encounters a retarder section of track at \(B\) which exerts a retarding force of \(32 \mathrm{kN}\) on the car in the direction opposite to \(\mathrm{mo}\) tion. Over what distance \(x\) should the retarder be activated in order to limit the speed of the car to \(3 \mathrm{m} / \mathrm{s}\) at \(C ?\)

Short Answer

Expert verified
The retarder should be activated over a distance of approximately 9.30 meters.

Step by step solution

01

Identify Given Data

First, identify and list down the information given in the problem. The mass of the freight car is given as 68 Mg, which is equivalent to 68000 kg. The initial speed of the car is 0.5 m/s, and we want to find the distance over which the car is slowed down to 3 m/s by a retarding force of 32 kN (32000 N).
02

Apply Work-Energy Principle

According to the work-energy principle, the work done by the retarder force will result in a change in the kinetic energy of the freight car. The work done, \( W \), is the retarding force \( F \) multiplied by the distance \( x \): \( W = F \cdot x \).
03

Calculate Initial and Final Kinetic Energies

The initial kinetic energy \( KE_{initial} \) can be calculated using the formula \( KE = \frac{1}{2} \cdot m \cdot v^2 \), where \( m \) is the mass and \( v \) is the velocity. For the initial kinetic energy: \( KE_{initial} = \frac{1}{2} \times 68000 \times (0.5)^2 = 8500 \) J. Calculate the final kinetic energy \( KE_{final} \) in a similar way: \( KE_{final} = \frac{1}{2} \times 68000 \times (3)^2 = 306000 \) J.
04

Calculate Work Done on the Car

The change in kinetic energy is given by \( KE_{final} - KE_{initial} \). Therefore, the work done \( W \) by the retarder is equal to the change in kinetic energy: \( W = 306000 - 8500 = 297500 \) J.
05

Find the Distance

Using the work-energy principle and the expression for work done \( W = F \cdot x \), we have \( 32000 \cdot x = 297500 \). Solve for \( x \): \( x = \frac{297500}{32000} \approx 9.30 \) m.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy is a fundamental concept in physics that describes the energy a body possesses due to its motion. This energy is directly proportional to the mass of the object and the square of its velocity. It can be calculated using the equation:
  • For an object with mass \( m \) and velocity \( v \), kinetic energy \( KE \) is given by: \( KE = \frac{1}{2} m v^2 \).
In the exercise, we calculate the kinetic energy of the freight car at two points: when it enters the retarder and when it exits. It starts with a lower speed of 0.5 m/s, which results in lower kinetic energy. As the problem progresses, the kinetic energy changes due to deceleration and changes in velocity. This decrease or increase in kinetic energy is approach crucial since it directly influences calculations of work done by forces acting in the mechanics scenario.
Kinetic energy allows us to understand how objects move and interact in situations involving motion, such as railroad dynamics.
Retarding Force
A retarding force acts in opposition to the direction of an object's motion, serving to slow it down. In the given problem, a retarding force of 32 kN opposes the motion of the cargo car, which has a significant effect on its velocity.
Retarding forces, like friction or air resistance, are crucial in controlling the movement of objects. They help to decelerate objects to the needed velocity or bring them to a stop. The work done by this retarding force can be calculated by multiplying the force by the distance over which it acts. In the problem:
  • The equation for work done by the retarder is given by \( W = F \cdot x \).
This work corresponds to the change in kinetic energy of the freight car as it moves from point B to point C with a deceleration.
Mechanics Problem Solving
Mechanics problem solving involves using principles of physics to analyze and predict the motion of objects. The work-energy principle is a particularly powerful tool in these types of problems. It states that the total work done by forces acting on an object results in a change in its kinetic energy.
  • In the exercise, we use this principle to determine the retarder distance required to reduce the speed of a freight car.
This involves calculating initial and final kinetic energies and using the known retarding force to find the distance. Problem-solving in mechanics often requires understanding how forces interact with motion and applying formulas to solve for unknowns. In the railroad yard problem, recognizing how the retarding force affects the car's kinetic energy helps us solve for the distance needed to safely regulate its speed.
By breaking down complex motions into simplified physics principles, problems become much more manageable.
Railroad Dynamics
Railroad dynamics involves understanding the movement and interaction of trains and cars on tracks. This field studies not just the motion, but also the forces exerted by and on the cars as they interact with the track and each other.
Dynamics like these are crucial for ensuring safety and efficiency in rail systems.
  • For instance, the retarding force applied in a rail yard manages the speed of cars.
  • It must be carefully calculated to ensure the cars reach desired speeds without causing unsafe conditions.
The problem illustrates this by asking for the calculation of a track section length necessary to slow down the freight car to a safer speed at point C. Understanding railroad dynamics helps engineers design safer rail systems and efficiently manage train movements, ensuring both cargo and passenger safety.

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Most popular questions from this chapter

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