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The jet transport \(B\) is flying north with a velocity \(v_{B}=600 \mathrm{km} / \mathrm{h}\) when a smaller aircraft \(A\) passes underneath the transport headed in the \(60^{\circ} \mathrm{di}\) rection shown. To passengers in \(B,\) however, \(A\) appears to be flying sideways and moving east. Determine the actual velocity of \(A\) and the velocity which \(A\) appears to have relative to \(B\)

Short Answer

Expert verified
The actual velocity of A is approximately 692.82 km/h, and its velocity relative to B is 346.41 km/h eastward.

Step by step solution

01

Define the Velocity Components

To solve this problem, we need to consider the velocity components of the aircraft. Let's define the velocity of aircraft A as \( \vec{v}_A \), and we know aircraft B is flying north with a velocity \( v_B = 600 \text{ km/h} \). We have to resolve \( \vec{v}_A \) into its components because it is flying at a \(60^\circ\) angle.
02

Resolve the Velocity of A into Components

Since aircraft A is flying at an angle of \(60^\circ\), we use trigonometry to find its components: \( v_{A_x} = v_A \cdot \cos(60^\circ) \) for the eastward component, and \( v_{A_y} = v_A \cdot \sin(60^\circ) \) for the northward component.
03

Define Relative Velocity of A with Respect to B

To find how A appears to B, we calculate the relative velocity \( \vec{v}_{A/B} = \vec{v}_A - \vec{v}_B \). Since \( \vec{v}_B \) is purely northward (0 in the eastward direction), we have \( v_{B_x} = 0 \) and \( v_{B_y} = 600 \text{ km/h} \).
04

Calculate the Components of Relative Velocity

Using the relation from Step 3, the eastward component of relative velocity is \( v_{A/B_x} = v_{A_x} - 0 = v_A \cdot \cos(60^\circ) \) and the northward component is \( v_{A/B_y} = v_{A_y} - 600 = v_A \cdot \sin(60^\circ) - 600 \). According to the given condition, these components show that \( v_{A/B_y} = 0 \), because A moves eastward according to B.
05

Solve for Speed of A Using the Condition

Since \( v_{A/B_y} = 0 \), it implies \( v_A \cdot \sin(60^\circ) = 600 \). Solving for \( v_A \), we get \( v_A = \frac{600}{\sin(60^\circ)} = \frac{600}{\sqrt{3}/2} = 600 \cdot \frac{2}{\sqrt{3}} \approx 692.82 \text{ km/h} \).
06

Calculate Apparent Eastward Velocity

The apparent eastward velocity of A with respect to B, which passengers observe, is given by \( v_{A/B_x} = v_A \cdot \cos(60^\circ) \approx 692.82 \cdot 0.5 = 346.41 \text{ km/h} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometry in Physics
Understanding the relationship between angles and distances is crucial in physics, particularly when dealing with motion analysis. Trigonometry helps break down complex motion into simple components. This exercise revolves around the use of trigonometry to resolve the velocity of an aircraft flying at a certain angle. By considering the angle of flight, we can determine how the velocity vector splits into horizontal and vertical components.
For any vector, such as the velocity of aircraft A, flying at an angle, trigonometric functions like cosine and sine are pivotal. The cosine function helps find the horizontal (or eastward) component, while the sine function finds the vertical (or northward) component.
  • The cosine of the angle gives the horizontal component: \( v_{A_x} = v_A \cdot \cos(60^\circ) \)
  • The sine of the angle gives the vertical component: \( v_{A_y} = v_A \cdot \sin(60^\circ) \)
By applying these trigonometric functions, we can understand the distribution of velocity in different directions and hence further analyze the motion effectively.
Velocity Components
In physics, velocity components are an effective way to describe a velocity vector concerning its direction. The velocity vector of any motion can be split into two perpendicular components. This concept simplifies the analysis of motion, especially in two-dimensional plane.
When analyzing the aircraft, A, its velocity components are essential in determining the actual and relative motion. As stated:
  • The eastward component (horizontal) is crucial since it helps us gauge how far the craft moves on the east direction: \( v_{A_x} = v_A \cdot \cos(60^\circ) \)
  • The northward component (vertical) is vital for measuring the craft's northward velocity: \( v_{A_y} = v_A \cdot \sin(60^\circ) \)
The precise decomposition of velocity into components allows for separate analysis, paving the way for calculating their effects on relative motion.
Aircraft Motion Analysis
Analyzing the motion of an aircraft involves understanding both its real and relative velocities. This is particularly interesting when two aircraft are moving in different directions or at different speeds, as in this exercise.
The relative velocity provides insight into how one aircraft appears to another. Here, aircraft A flies at an angle but appears to move purely eastward from the viewpoint of aircraft B. Calculation of relative velocity components confirms this:
  • The eastward relative velocity: \( v_{A/B_x} = v_A \cdot \cos(60^\circ) \)
  • The northward component is zero because: \( v_{A/B_y} = 0 \), showing A looks like it moves sideways to B.
Understanding the apparent motion relative to another moving object is fundamental in aviation safety and efficiency. Aircraft motion analysis using relative velocity is a standard procedure to ensure seamless operations, avoiding mid-air collisions or flight path discrepancies.

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