/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 171 The rotating element in a mixing... [FREE SOLUTION] | 91Ó°ÊÓ

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The rotating element in a mixing chamber is given a periodic axial movement \(z=z_{0} \sin 2 \pi n t\) while it is rotating at the constant angular velocity \(\dot{\theta}=\omega\) Determine the expression for the maximum magnitude of the acceleration of a point \(A\) on the rim of radius \(r .\) The frequency \(n\) of vertical oscillation is constant.

Short Answer

Expert verified
The maximum acceleration is \(\sqrt{(r \omega^2)^2 + ((2\pi n)^2 z_0)^2}\)."

Step by step solution

01

Identify the Position Functions

The position function for the axial movement is given as \(z = z_0 \sin(2\pi n t)\). The angular position as a function of time due to rotation is \(\theta(t) = \omega t\). A point on the rim of radius \(r\) has coordinates \((r \cos(\theta), r \sin(\theta), z)\).
02

Compute the Velocity Components

The velocity components can be found by differentiating the position functions with respect to time. For the axial movement, \(\dot{z} = \frac{d}{dt}[z_0 \sin(2\pi n t)] = 2\pi n z_0 \cos(2\pi n t)\). For the rotation, the tangential velocity components are \(\dot{x} = -r \omega \sin(\omega t)\) and \(\dot{y} = r \omega \cos(\omega t)\).
03

Calculate the Acceleration Components

Differentiate the velocity components to find acceleration. The axial acceleration is \(\ddot{z} = \frac{d}{dt}[2\pi n z_0 \cos(2\pi n t)] = -(2\pi n)^2 z_0 \sin(2\pi n t)\). The centripetal acceleration due to the rotation is \(\ddot{x} = -r \omega^2 \cos(\omega t)\) and \(\ddot{y} = -r \omega^2 \sin(\omega t)\).
04

Determine the Total Acceleration

The total acceleration is the vector sum of the axial and rotational accelerations. Hence, the magnitude of the total acceleration \(a\) is \[a = \sqrt{(\ddot{x})^2 + (\ddot{y})^2 + (\ddot{z})^2}.\] Substituting the expressions from the previous steps, we have \[a = \sqrt{(r \omega^2)^2 + ((2\pi n)^2 z_0 \sin(2\pi n t))^2}.\]
05

Find the Maximum Acceleration

The maximum magnitude of the acceleration occurs when \(\sin(2\pi n t) = \pm 1\). Substituting \(\sin(2\pi n t) = \pm 1\) in the total acceleration expression, it becomes \[a_{max} = \sqrt{(r \omega^2)^2 + ((2\pi n)^2 z_0)^2}.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rotational Motion
Rotational motion is a fundamental concept in dynamics. When an object spins around an axis, it undergoes rotational motion. This type of motion is described by angular velocity, denoted by \( \omega \), which is the rate of change of angular displacement. A point on a rotating body describes a circular path, and at any given instant, it moves tangentially. In our exercise, the mixing element is rotating with a constant angular velocity \( \omega \). This means that the motion repeats itself in cycles, leading to predictable movement. The coordinates of a point \( A \) on the rim are \((r \cos(\theta), r \sin(\theta), z)\), and it's important to understand how each point can have different velocities and accelerations, depending on their position on the rotating element. Here, tangential velocities are influenced by \( \omega \) and the radius \( r \), forming part of the dynamics in mechanical systems.
Axial Movement
Axial movement refers to movement along an axis. In the context of our exercise, it is represented by a sinusoidal function \(z = z_0 \sin(2\pi n t)\), indicating periodic vertical displacement of the mixing element. This function describes how the element moves up and down consistently over time, with \(z_0\) as the maximum amplitude and \(n\) as the frequency of the oscillation. This kind of movement adds an extra layer of complexity to the rotational motion, complicating the calculations of velocity and acceleration. The motion is harmonically oscillating, which means it repeats over time. Understanding the nature of axial movement is key in analyzing systems that exhibit synchronized rotational and translational motions.
Acceleration Calculation
Acceleration calculation is crucial in understanding dynamics. It involves determining how quickly a point speeds up or slows down. In the discussed exercise, the point \(A\) on the rim undergoes both axial and rotational accelerations. Axial acceleration is derived from the second derivative of the position function, leading to \( \ddot{z} = -(2\pi n)^2 z_0 \sin(2\pi n t) \). Here, the oscillation's frequency \( n \) and amplitude \( z_0 \) significantly influence the acceleration's magnitude. On the rotational side, centripetal acceleration is responsible for changing the direction of the velocity, calculated through \( \ddot{x} = -r \omega^2 \cos(\omega t) \) and \( \ddot{y} = -r \omega^2 \sin(\omega t) \). The total acceleration is a combination of these components. Therefore, calculating the magnitude of the resultant vector allows us to determine how each component contributes to the overall motion dynamics.
Mechanical Systems Analysis
Mechanical systems analysis involves studying movements and forces within a system to predict behavior. In the exercise, by analyzing both rotational and axial movements, a comprehensive understanding of the system's dynamic behavior is achieved. We calculate total acceleration with the equation \( a = \sqrt{(r \omega^2)^2 + ((2\pi n)^2 z_0 \sin(2\pi n t))^2} \). Finding the maximum acceleration provides insights into the system's limits and capabilities under maximum stress: when \( \sin(2\pi n t) = \pm 1 \). Such analysis helps engineers design more efficient mechanisms capable of withstanding varying conditions. Proper mechanical systems analysis ensures that components collaborate effectively, leading to safer and more reliable mechanical designs.

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Most popular questions from this chapter

A ship which moves at a steady 20 -knot speed \((1 \mathrm{knot}=1.852 \mathrm{km} / \mathrm{h})\) executes a turn to port by changing its compass heading at a constant counterclockwise rate. If it requires 60 seconds to alter course \(90^{\circ}\), calculate the magnitude of the acceleration a of the ship during the turn.

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