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The radial position of a fluid particle \(P\) in a certain centrifugal pump with radial vanes is approximated by \(r=r_{0} \cosh K t,\) where \(t\) is time and \(K=\dot{\theta}\) is the constant angular rate at which the impeller turns. Determine the expression for the magnitude of the total acceleration of the particle just prior to leaving the vane in terms of \(r_{0}, R,\) and \(K\)

Short Answer

Expert verified
The magnitude of total acceleration is \( a = RK^2 \sqrt{2} \).

Step by step solution

01

Understand the Problem

We have a radial position function for a fluid particle in the centrifugal pump, given as \( r = r_0 \cosh(Kt) \). Our goal is to find the total acceleration of the particle in terms of \( r_0, R, \text{ and } K \) just before it leaves the vane.
02

Identify Radial Acceleration

The radial acceleration is found using the second derivative of the radial position with respect to time \( t \). Start by finding the first derivative: \( \frac{dr}{dt} = r_0 K \sinh(Kt) \). The second derivative (radial acceleration) is \( \frac{d^2r}{dt^2} = r_0 K^2 \cosh(Kt) \).
03

Identify Tangential Acceleration

Tangential acceleration \( a_t \) is given by the radial distance \( r \) times the angular acceleration. Since the angular rate \( \dot{\theta} \) is constant, \( a_t = 0 \).
04

Identify Centripetal Acceleration

The centripetal acceleration \( a_c \) can be expressed as \( a_c = r \cdot \dot{\theta}^2 = r \cdot K^2 \). Substituting the radial position function, we have \( a_c = r_0 \cosh(Kt) K^2 \).
05

Calculate Total Acceleration

The total acceleration \( a \) of the particle is the vector addition of radial acceleration and centripetal acceleration. Thus, the magnitude is \( a = \sqrt{(r_0 K^2 \cosh(Kt))^2 + (r_0 \cosh(Kt) K^2)^2} \). Simplify to get \( a = r_0 K^2 \cosh(Kt) \sqrt{2} \), since the expressions under the square root are the same.
06

Substitute Just Prior to Leaving the Vane

Before leaving the vane, the radial position is near its maximum \( R \). Thus, substitute \( r = R \) in terms of hyperbolic identity for \( \cosh(Kt) \): \( R = r_0 \cosh(Kt) \), leading to \( \cosh(Kt) = \frac{R}{r_0} \).
07

Final Expression for Total Acceleration

Substitute \( \cosh(Kt) = \frac{R}{r_0} \) into the total acceleration equation: \( a = r_0 K^2 \frac{R}{r_0} \sqrt{2} \), which simplifies to \( a = RK^2 \sqrt{2} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radial Acceleration
Radial acceleration represents the change in velocity of a fluid particle as it moves radially in a centrifugal pump. When working with a radial position function, this acceleration is determined by calculating the second derivative of the position with respect to time. In this context, the radial position is given as \( r = r_0 \cosh(Kt) \). Here's a step-by-step breakdown of the process:

  • First derivative: The rate of change of radial position is: \( \frac{dr}{dt} = r_0 K \sinh(Kt) \).

  • Second derivative: This results in the radial acceleration: \( \frac{d^2r}{dt^2} = r_0 K^2 \cosh(Kt) \).

Radial acceleration is crucial for understanding how the fluid particle gains speed within the pump. It reflects the component of acceleration directed out from the center of rotation. This is important in scenarios where the particle is about to exit the vane, and it must be controlled carefully to avoid excessive wear on the machinery.
Tangential Acceleration
Tangential acceleration refers to the change in velocity of a fluid particle along the tangent to the path of motion in the centrifugal pump. It is linked to how swiftly the angle of rotation changes over time. When the angular rate is constant, the tangential acceleration becomes rather straightforward.


  • In our setup, the angular rate \( \dot{\theta} \) is constant, meaning the angular acceleration \( \alpha \) is zero.

  • Therefore, the tangential acceleration formula \( a_t = r \cdot \alpha \) leads to \( a_t = 0 \).

This implies that in scenarios where the angular motion is steady, like in this centrifugal pump, the tangential acceleration does not contribute to the total acceleration of the particle. Understanding this helps focus on the actual forces at play in the pump dynamics.
Centripetal Acceleration
Centripetal acceleration is an essential aspect of pump dynamics, representing the inward force acting on a fluid particle moving through the pump. This acceleration keeps the particle following the curved path through the vanes, preventing it from flying out straight due to inertia.

  • Formula: Centripetal acceleration can be calculated with \( a_c = r \cdot K^2 \).

  • Using radial position: Substitute \( r = r_0 \cosh(Kt) \) into the equation to find: \( a_c = r_0 \cosh(Kt) K^2 \).

This centripetal force ensures that even at high velocities, the fluid particle remains anchored to its designated path within the pump. Understanding this force is critical for designing pumps that can withstand high-speed rotations while ensuring optimal performance and safety of the fluid handling process. By recognizing the interplay of these forces, engineers can tailor the pump's operation to specific needs, balancing efficiency with structural integrity.

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