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The preliminary design for a "small" space station to orbit the earth in a circular path consists of a ring (torus) with a circular cross section as shown. The living space within the torus is shown in section \(A,\) where the "ground level" is \(20 \mathrm{ft}\) from the center of the section. Calculate the angular speed \(N\) in revolutions per minute required to simulate standard gravity at the surface of the earth \(\left(32.17 \mathrm{ft} / \mathrm{sec}^{2}\right) .\) Recall that you would be unaware of a gravitational field if you were in a nonrotating spacecraft in a circular orbit around the earth.

Short Answer

Expert verified
12.12 revolutions per minute.

Step by step solution

01

Understand the Context

The task involves finding the angular speed of a rotating space station that creates a force equivalent to Earth's gravity (32.17 ft/sec²) at a 'ground level' 20 ft from the center.
02

Relate Centripetal Force and Gravity

The centripetal acceleration required to simulate gravity is given by the formula for gravitational acceleration, which is equal to Earth's gravity at the surface. Therefore, set the centripetal force equal to 32.17 ft/sec².
03

Express Centripetal Acceleration

Centripetal acceleration is given by the formula \( a_c = r \omega^2 \), where \( r = 20 \) ft, the radius to the 'ground level,' and \( \omega \) is the angular velocity in radians per second.
04

Solve for Angular Velocity in Radians per Second

Set the centripetal acceleration equation to Earth's gravity: \( 20 \cdot \omega^2 = 32.17 \). Solve for \( \omega \) to find \( \omega = \sqrt{\frac{32.17}{20}} \approx 1.27 \) rad/sec.
05

Convert Angular Velocity to Revolutions per Minute

First, convert the angular velocity from radians per second to revolutions per second using the relation \( 1\, \text{rev} = 2\pi \text{ rad} \), then convert to revolutions per minute. So, \( N = \frac{1.27}{2\pi} \times 60 \approx 12.12 \) revolutions per minute.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Velocity
Angular velocity is a measure of how quickly an object turns or spins around a central point. In our space station scenario, angular velocity helps us determine the rate at which the station must spin to simulate Earth's gravity. The concept of angular velocity is vital when working with rotating objects, especially in physics and engineering.

In our exercise, the angular velocity was initially calculated in radians per second. A radian is a unitless measure of angle based on the radius of a circle. To find angular velocity (\( \omega \) ), we use the relationship between centripetal acceleration and angular velocity:
  • Centripetal acceleration (\( a_c \)) = radius (\( r \)) × angular velocity squared (\( \omega^2 \)).
For the space station, we set \( a_c \) equivalent to Earth’s gravitational force (32.17 ft/sec²), allowing us to solve for \( \omega \). This calculation helped find the necessary rotations per minute for the station.
Circular Motion
Circular motion refers to the movement of an object following a circular path. This principle is key in understanding how the space station generates a force equivalent to gravity. As it spins, centripetal force acts on objects inside the station, creating the sensation of gravity by pulling them toward the center of the circular path.

To better grasp circular motion, it’s essential to understand the concept of centripetal force, which keeps objects moving along their circular paths rather than flying outwards due to inertia. In our exercise:
  • The space station itself is the object in motion, creating a perceived force on anything inside it.
  • The radius of the station's circular path (20 ft) plays a crucial role in calculating the necessary angular velocity.
Understanding these dynamics helps comprehend how simulating gravity in space environments is possible, underlining the practical application of circular motion principles.
Gravitational Simulation
Gravitational simulation involves creating conditions that mimic gravity using physical forces, like in this rotating space station. It’s crucial for designing environments where humans might live or work in space, ensuring that they experience the pull similar to what is felt on Earth.

To simulate gravity, the space station rotates to create centripetal acceleration, simulating the gravitational pull at the Earth's surface. The formula connecting gravitational force with centripetal acceleration (\( a_c = r \omega^2 \)) shows how rotation speed and radius contribute to the simulation. In effect, objects and occupants inside feel as though they are subject to constant gravitational pull.

Gravitational simulation is especially beneficial for long duration space missions, aiding in the maintenance of muscle and bone density for astronauts. It demonstrates the clever use of physics in adapting to different environments beyond our planet.

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Most popular questions from this chapter

A small airplane flying horizontally with a speed of \(180 \mathrm{mi} / \mathrm{hr}\) at an altitude of \(400 \mathrm{ft}\) above a remote valley drops an emergency medical package at \(A\) The package has a parachute which deploys at \(B\) and allows the package to descend vertically at the constant rate of 6 ft/sec. If the drop is designed so that the package is to reach the ground 37 seconds after release at \(A,\) determine the horizontal lead \(L\) so that the package hits the target. Neglect atmospheric resistance from \(A\) to \(B\)

A car comes to a complete stop from an initial speed of \(50 \mathrm{mi} / \mathrm{hr}\) in a distance of \(100 \mathrm{ft}\). With the same constant acceleration, what would be the stopping distance \(s\) from an initial speed of \(70 \mathrm{mi} / \mathrm{hr} ?\)

A particle which moves with curvilinear motion has coordinates in meters which vary with time \(t\) in seconds according to \(x=2 t^{2}+3 t-1\) and \(y=5 t-2 .\) Determine the coordinates of the center of curvature \(C\) at time \(t=1\) s.

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