/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 63 The spring system is connected t... [FREE SOLUTION] | 91Ó°ÊÓ

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The spring system is connected to a crosshead that oscillates vertically when the wheel rotates with a constant angular velocity of \(\omega .\) If the amplitude of the steady-state vibration is observed to be \(400 \mathrm{mm}\), and the springs each have a stiffness of \(k=2500 \mathrm{N} / \mathrm{m},\) determine the two possible values of \(\omega\) at which the wheel must rotate. The block has a mass of \(50 \mathrm{kg}\)

Short Answer

Expert verified
The two possible values of \(\omega\) at which the wheel must rotate are \(7.071 \, rad/sec\) and \(10 \, rad/sec\).

Step by step solution

01

Formulate the model equation

As this is a scenario of harmonic motion, we use the governing formula \(ω= √(k/m)\), where \(k\) is the spring stiffness and \(m\) is the mass.
02

Convert mm to m

In this step, we convert the amplitude of vibration from the given mm to m. Therefore, \(A = 400 \, mm = 0.4 \, m\)
03

Substitute the given values

Now we substitute the given values into the formula \(ω= √(k/m)\). Thus, \(ω= √(2500 / 50)= √50 = 7.071 \, rad/sec\)
04

Calculate the angular frequency

The angular frequency \(\omega\), given that the amplitude of vibration \(A\) is \(0.4m\), can be determined by \(\omega = 2\pi f = 2\pi/T\), where \(T = 2\pi \sqrt{m/k}\). By plugging the known values we find that \(\omega = 2\pi/ T = 2\pi/(2\pi \sqrt{50/2500}) = 10\, rad/sec\)
05

Identify possible values

The two possible \(\omega\) values are therefore \(7.071 \, rad/sec\) and \(10 \, rad/sec\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Angular Velocity in Harmonic Motion
Angular velocity is a crucial concept in harmonic motion, especially when dealing with rotating systems. In the context of harmonic motion, it's defined as the rate at which an object rotates or revolves around a center or a specific point, and it's usually measured in radians per second (rad/s).

Consider an object attached to a spring moving in a circular path. The angular velocity, denoted as \( \omega \), represents how fast this object is rotating. When the spring system described in the exercise completes a full rotation, the angular velocity comes into play. It's associated with the frequency of oscillation, \( f \), by the relation \( \omega = 2\pi f \), indicating the connection between linear and angular motion in the system.

Higher angular velocity means the system goes through more cycles per unit time, leading to a higher rate of oscillation. By understanding \( \omega \), students can better grasp how fast the crosshead is oscillating and determine the operational speeds that would result in specific behaviors of the spring system.
Spring Stiffness Impact on Harmonic Motion
Spring stiffness, represented by the symbol \( k \), is a measure of how resistant a spring is to being compressed or stretched. In other words, it's a constant that tells us how stiff the spring is and subsequently, how much force is needed to extend or compress it by a certain amount.

In the context of the exercise, the stiffness of the springs determines the system's natural frequency of vibration. The formula \( k = F/x \)—where \( F \) is the force applied, and \( x \) is the displacement—allows us to understand that a stiffer spring (higher \( k \) value) will require a greater force to achieve the same displacement compared to a less stiff spring.

The stiffness, coupled with the mass of the object \( m \) in the formula \( \omega = \sqrt{k/m} \), shows the direct proportionality between \( k \) and the square of the angular velocity. A stiffer spring with higher \( k \) value leads to higher angular velocity, consequently higher frequency, for the mass-spring system to undergo harmonic motion.
Vibration Amplitude and Its Significance
Vibration amplitude is another fundamental term in the study of harmonic motion, denoted as \( A \). It refers to the maximum extent of displacement from the rest position during one cycle of vibration. Essentially, it's the peak value of the motion, whether we're discussing vertical oscillation, as in the exercise, or any other harmonic movement.

In the case of our spring system, an amplitude of \( 400 \, mm = 0.4 \, m \) means that the crosshead moves a total of 0.8 meters up and down during each cycle of its motion. The amplitude is a critical factor because it tells us how intense the vibration is; the larger the amplitude, the more pronounced the motion.

Furthermore, amplitude is directly related to the energy in harmonic motion. More specifically, the kinetic and potential energies within the system vary proportionally to the square of the vibration amplitude. This means that any change in amplitude will have a squared effect on the energy, making it an essential parameter for understanding the dynamic behavior of the spring system.

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Most popular questions from this chapter

A \(3-\mathrm{kg}\) block is suspended from a spring having a stiffness of \(k=200 \mathrm{N} / \mathrm{m}\). If the block is pushed \(50 \mathrm{mm}\) upward from its equilibrium position and then released from rest, determine the equation that describes the motion. What are the amplitude and the natural frequency of the vibration? Assume that positive displacement is downward.

The bar has a weight of 6 lb. If the stiffness of the spring is \(k=8\) lb/ft and the dashpot has a damping coefficient \(c=60 \mathrm{lb} \cdot \mathrm{s} / \mathrm{ft},\) determine the differential equation which describes the motion in terms of the angle \(\theta\) of the bar's rotation. Also, what should be the damping coefficient of the dashpot if the bar is to be critically damped?

A block which has a mass \(m\) is suspended from a spring having a stiffness \(k .\) If an impressed downward vertical force \(F=F_{O}\) acts on the weight, determine the equation which describes the position of the block as a function of time.

Find the differential equation for small oscillations in terms of \(\theta\) for the uniform rod of mass \(m\). Also show that if \(c<\sqrt{m k} / 2,\) then the system remains underdamped. The rod is in a horizontal position when it is in equilibrium.

A flywheel of mass \(m,\) which has a radius of gyration about its center of mass of \(k_{O},\) is suspended from a circular shaft that has a torsional resistance of \(M=C \theta\). If the flywheel is given a small angular displacement of \(\theta\) and released, determine the natural period of oscillation.

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