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The gauge pressure of water at \(C\) is \(40 \mathrm{lb} / \mathrm{in}^{2}\). If water flows out of the pipe at \(A\) and \(B\) with velocities \(v_{A}=12 \mathrm{ft} / \mathrm{s}\) and \(v_{B}=25 \mathrm{ft} / \mathrm{s},\) determine the horizontal and vertical components of force exerted on the elbow necessary to hold the pipe assembly in equilibrium. Neglect the weight of water within the pipe and the weight of the pipe. The pipe has a diameter of 0.75 in. at \(C,\) and at \(A\) and \(B\) the diameter is 0.5 in. \(\gamma_{w}=62.4 \mathrm{lb} / \mathrm{ft}^{3}\)

Short Answer

Expert verified
The horizontal and vertical forces required at the elbow to hold the pipe assembly in equilibrium can be found by summing up the forces at points A and B. These are calculated by applying Bernoulli's equation and the principles of fluid dynamics, assuming that the system is in equilibrium. The exact values will depend on the specific numbers obtained in the calculations.

Step by step solution

01

Apply Bernoulli's Equation

The loop C-A-B is a closed system and Bernoulli's equation applies. Because elevation is not changing significantly and the system is in equilibrium, the force due to pressure at C equals the force due to pressure and velocity at A and B. This means: \n \(P_{C}=\frac{1}{2} \gamma_{w} v_{A}^{2} + P_{A} = \frac{1}{2} \gamma_{w} v_{B}^{2} + P_{B}\), where \(P_{C}\), \(P_{A}\) and \(P_{B}\) are the pressures at points C, A, and B respectively.
02

Convert Units and Calculate Pressures

First, convert the given pressure at C, \(P_{C} = 40 lb/in^{2}\), to \(lb/ft^{2}\) by multiplying by 144. Also, convert the velocities at A and B to \(ft^{2}/s^{2}\) by squaring the given velocities. Using Bernoulli's equation, we then calculate \(P_{A}\) and \(P_{B}\), the pressures at A and B respectively.
03

Determine the Forces at A and B

The horizontal and vertical forces exerted at each point can be found by multiplying the pressure at each point with the respective cross-sectional area of the pipe. This can be done with the equation \(F = P \cdot A\), where \(F\) is the force, \(P\) is the pressure and \(A\) is the cross-sectional area, \(A = \pi d^{2}/4\), \(d\) being the diameter of the pipe. We also need to remember that the force at A is downward and to the right, whereas the force at B is upwards and to the right.
04

Calculate Horizontal and Vertical Components of Force

To find the forces necessary to hold the assembly in equilibrium, we calculate the sum of horizontal and vertical components at A and B separately. The net horizontal and vertical forces must be zero, as the system is in equilibrium. If they were not zero, the system would move in the direction of the resultant force.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bernoulli's Equation
In fluid mechanics, Bernoulli's equation is a mathematical representation of the energy conservation principle for a flowing fluid. It elucidates the relationship between the fluid's pressure, its speed, and the gravitational potential energy at various points along the flow path. More specifically, the equation asserts that an increase in the fluid's speed leads to a decrease in pressure, and vice versa.

The general form of the equation is: \[ P + \frac{1}{2}\gamma v^2 + \gamma h = \text{constant}\]Where:
  • \(P\) is the static pressure in the fluid.
  • \(v\) is the fluid velocity.
  • \(\gamma\) is the weight density of the fluid (the product of its density and gravitational acceleration).
  • \(h\) is the elevation above a reference level.
In the presented exercise, the elevation change is negligible, and hence, the term involving \(h\) can be ignored. Bernoulli's equation simplifies to equating the pressure energy and kinetic energy per unit volume of the fluid at points C, A, and B. This simplified approach allows for the calculation of the unknown pressures by considering the known velocity of the fluid at different points of the system.
Hydrostatic Pressure
Hydrostatic pressure is the pressure exerted by a fluid at rest due to the force of gravity. It increases linearly with the depth of the fluid, given that the density of the fluid remains constant. The formula for hydrostatic pressure at a certain depth is:\[ P = \gamma h\]Where:\(P\) is the pressure at the depth, \(\gamma\) is the fluid's weight density, and \(h\) is the depth of the fluid. In the context of the exercise, the system is being considered without significant elevation changes, thus the vertical variation of hydrostatic pressure can be disregarded. Nevertheless, the concept is essential in understanding that within a closed system such as a pipe, the fluid pressure can vary due to other factors such as fluid velocity, which is explored in Bernoulli's equation.
Cross-Sectional Area
The cross-sectional area of a pipe or channel is an important factor when considering fluid flow. It determines the rate at which a volume of fluid can pass through a given section of the pipe. The cross-sectional area is found using the geometric formula for the area of a circle, since most pipes have a circular cross-section:\[ A = \frac{\pi d^2}{4}\]Where \(A\) represents the area and \(d\) is the diameter of the pipe. An essential component of the exercise solution is to calculate the force exerted by the fluid on the pipe wall, this can be done by multiplying the pressure at that point by the cross-sectional area. Understanding how diameter, and hence, area, affects fluid dynamics is crucial since changes in pipe diameter influence the velocity and pressure of a fluid, concepts that are tied into Bernoulli's equation and hydrostatic pressure.
Equilibrium in Fluid Dynamics
In fluid dynamics, equilibrium refers to a condition where all the forces acting on a system are balanced, resulting in no net force and thus no acceleration of the fluid elements or the system containing the fluid. In the context of our exercise, this occurs when the pipe assembly is stationary because the forces due to pressure and flow at different points in the system are in balance.

For equilibrium, the sum of horizontal and vertical components of forces must equal zero. In the exercise's solution, this principle is used to calculate the forces necessary to hold the assembly in place at points A and B. The horizontal and vertical forces were obtained from pressure differentials and cross-sectional areas of the pipe, then combined to ensure that their net effect would keep the system stable, without motion. Understanding the equilibrium conditions in a fluid system is critical in designing and predicting the behavior of structures that interact with fluids, such as pipes, dams, and even aircraft.

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Most popular questions from this chapter

The 15 -kg block \(A\) slides on the surface for which \(\mu_{k}=0.3 .\) The block has a velocity \(v=10 \mathrm{m} / \mathrm{s}\) when it is \(s=4 \mathrm{m}\) from the 10 -kg block \(B\). If the unstretched spring has a stiffness \(k=1000 \mathrm{N} / \mathrm{m},\) determine the maximum compression of the spring due to the collision. Take \(e=0.6\).

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