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Block \(A\) has a mass \(m_{A}\) and is attached to a spring having a stiffness \(k\) and unstretched length \(l_{0} .\) If another block \(B,\) having a mass \(m_{B},\) is pressed against \(A\) so that the spring deforms a distance \(d\), determine the distance both blocks slide on the smooth surface before they begin to separate. What is their velocity at this instant?

Short Answer

Expert verified
The blocks will slide a distance \(d\) and the velocity at this instant can be found from the equation \(1/2 * k * d^2 = 1/2 * (mA + mB) * v^2\).

Step by step solution

01

Potential Energy

Start by determining the potential energy stored in the spring when the blocks are pressed against each other. The potential energy PE can be found using Hooke's Law for springs, \(PE = 1/2 * k * d^2\). We know the spring constant \(k\) and the distance \(d\) the spring is deformed.
02

Conservation of Energy

Set up conservation of mechanical energy. As there are no other external forces acting on the system, the total energy of the system is conserved i.e., the potential energy of the system when the spring is pressed will convert entirely into kinetic energy when the blocks start moving. The equation will be \(1/2 * k * d^2 = 1/2 * (mA + mB) * v^2\). This equation can be solved for velocity \(v\).
03

Calculate the Distance

In the case of Hooke’s law, the spring will return to its equilibrium position when all the potential energy has turned into kinetic energy. The distance slid will be equal to the distance the spring was originally deformed, which was \(d\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Potential Energy
Potential energy is a fundamental concept in spring mechanics and physics in general. It refers to the energy stored in an object due to its position relative to other objects. In the context of springs, potential energy is stored when the spring is either compressed or stretched.

For a spring, the potential energy (PE) is calculated using Hooke's Law, which relates the force needed to compress or stretch the spring to the distance it is deformed. The formula is given by:
  • \(PE = \frac{1}{2} k d^2\)
Here, \(k\) is the spring stiffness, a constant that measures how difficult it is to stretch or compress the spring, and \(d\) is the deformation distance from the spring's natural length.

This potential energy is "stored" in the spring when compressed and is waiting to be converted into another form of energy, usually kinetic energy, when the spring returns to its natural state.
Conservation of Energy
The principle of conservation of energy is a cornerstone in the study of mechanics. It states that energy cannot be created or destroyed, only transformed from one form to another. In our spring-block system, this principle helps us predict how the system behaves as it moves.

When the spring is compressed, it stores potential energy. As the blocks are released, this potential energy gets converted into kinetic energy. Because there are no external forces like friction acting on the system (it's a smooth surface), the total mechanical energy (sum of potential and kinetic energy) remains constant.
  • The potential energy at maximum compression: \(\frac{1}{2} k d^2\).
  • Kinetic energy when the blocks begin to move: \(\frac{1}{2} (m_A + m_B) v^2\).
By setting these two equal, we find that all the potential energy transforms into kinetic energy, and we can solve for velocity.
Hooke's Law
Hooke's Law is a simple yet powerful principle used to describe the behavior of springs. It states that the force exerted by a spring is directly proportional to the amount it is stretched or compressed from its natural length. This relationship is expressed mathematically as:
  • \(F = -k x\)
Where:
  • \(F\) is the force exerted by the spring,
  • \(k\) is the spring constant (a measure of stiffness), and
  • \(x\) is the displacement from the equilibrium position.
The negative sign indicates that the force exerted by the spring opposes the direction of displacement. This means if you compress the spring, it pushes back against the compression, and if you stretch it, it pulls back to its original form.

Understanding Hooke's Law is crucial for calculating the energy stored in a spring, which is used to understand motion and forces in various physics problems.
Kinetic Energy
Kinetic energy is the energy that an object possesses due to its motion. Once the stored potential energy in the spring is completely converted, it turns into kinetic energy, and the blocks start moving. The formula for kinetic energy (KE) is:
  • \(KE = \frac{1}{2} mv^2\)
Where:
  • \(m\) is the mass of the object, and
  • \(v\) is its velocity.
In the block-spring system, the kinetic energy is distributed between the masses of blocks A and B. Initially, when released, the sum of their kinetic energies will equal the potential energy the spring initially had.

By discerning how speed \(v\) changes as potential energy turns into kinetic energy, we can determine the exact moment when the blocks will begin to move and predict their behavior on the track. Understanding kinetic energy is crucial as it links the study of motion to the concept of energy transformation.

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Most popular questions from this chapter

The 150-lb man lies against the cushion for which the coefficient of static friction is \(\mu_{s}=0.5 .\) Determine the resultant normal and frictional forces the cushion exerts on him if, it due to rotation about the \(z\) axis, he has a constant speed \(v=20 \mathrm{ft} / \mathrm{s} .\) Neglect the size of the man. Take \(\theta=60^{\circ}\).

The conveyor belt is designed to transport packages of various weights. Each 10 -kg package has a coefficient of kinetic friction \(\mu_{k}=0.15 .\) If the speed of the conveyor is \(5 \mathrm{m} / \mathrm{s},\) and then it suddenly stops, determine the distance the package will slide on the belt before coming to rest.

The collar, which has a weight of 3 lb, slides along the smooth rod lying in the horizontal plane and having the shape of a parabola \(r=4 /(1-\cos \theta),\) where \(\theta\) is in radians and \(r\) is in feet. If the collar's angular rate is constant and equals \(\dot{\theta}=4 \mathrm{rad} / \mathrm{s},\) determine the tangential retarding force \(P\) needed to cause the motion and the normal force that the collar exerts on the rod at the instant \(\theta=90^{\circ}\).

The 4 -kg smooth cylinder is supported by the spring having a stiffness of \(k_{A B}=120 \mathrm{N} / \mathrm{m} .\) Determine the velocity of the cylinder when it moves downward \(s=0.2 \mathrm{m}\) from its equilibrium position, which is caused by the application of the force \(F=60 \mathrm{N}\).

Block \(A\) has a weight of 8 lb and block \(B\) has a weight of 6 lb. They rest on a surface for which the coefficient of kinetic friction is \(\mu_{k}=0.2 .\) If the spring has a stiffness of \(k=20\) lb/ft, and it is compressed \(0.2 \mathrm{ft}\), determine the acceleration of each block just after they are released.

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