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The acceleration of a particle along a straight line is defined by \(a=(2 t-9) \mathrm{m} / \mathrm{s}^{2},\) where \(t\) is in seconds. At \(t=0, s=1 \mathrm{m}\) and \(v=10 \mathrm{m} / \mathrm{s} .\) When \(t=9 \mathrm{s},\) determine (a) the particle's position, (b) the total distance traveled, and (c) the velocity.

Short Answer

Expert verified
At \(t=9\) seconds, the particle's position is \(s(9) = - 27 m\), the total distance travelled is \(27 m\) and the velocity is \(v(9) = -27 m/s\).

Step by step solution

01

Finding the velocity function

To find the velocity function, integrate the given acceleration function with respect to time \(t\). The acceleration function given is \(a = 2t - 9\). Integrate this to get the velocity function, don't forget to include a constant of integration, \(C1\). So, \(v(t) = \int (2t - 9) dt = t^2 - 9t + C1\).
02

Determining \(C1\) using initial velocity

Now apply the initial conditions to find \(C1\). We know that at \(t=0\), \(v=10 m/s\). Substituting these values into our equation gives us \(10 = 0 - 0 + C1\), which tells us that \(C1 = 10\). So our velocity function becomes \(v(t) = t^2 - 9t + 10\).
03

Finding the position function

Next, calculate the position function by integrating the velocity function with respect to time \(t\). So, \(s(t) = \int (t^2 - 9t + 10) dt = (1/3)t^3 - (9/2)t^2 + 10t + C2\).
04

Determining \(C2\) using initial position

Determine the constant \(C2\) using the initial conditions at \(t=0\), where \(s=1 m\). Substituting \(t=0\) and \(s=1\) into the position function yields \(1 = 0 - 0 + 0 + C2\), so \(C2 = 1\). Thus, the position function becomes \(s(t) = (1/3)t^3 - (9/2)t^2 + 10t + 1\).
05

Calculating position, total distance and velocity at \(t=9s\)

Substitute \(t=9\) to find the particle's position, total distance travelled, and velocity. The position will be \(s(9)\), the velocity will be \(v(9)\), and the total distance travelled can be considered the same as the absolute position.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Particle Motion
In kinematics, particle motion is described by the changes in parameters such as position, velocity, and acceleration over time. Here, we have a particle moving along a straight line with acceleration given by the function \(a(t) = 2t - 9\, \text{m/s}^2\). This shows how the particle's acceleration changes with time.
To analyze particle motion effectively, we need to establish relationships among acceleration, velocity, and position.
  • Acceleration: Rate of change of velocity with time.
  • Velocity: Rate of change of position with time.
  • Position: Location of the particle at any given time.
Understanding how these properties change allows us to predict the future states of the particle. By performing integrations, we can derive velocity and position from acceleration.
Integration in Dynamics
Integration in dynamics involves finding an antiderivative, which helps in moving from acceleration to velocity and then to position. This is crucial in describing the complete path of a moving particle. Let's break it down:
First, integrating acceleration \(a(t) = 2t - 9\) gives us the velocity function \(v(t) = \int (2t - 9) \, dt = t^2 - 9t + C_1\). Here, \(C_1\) is a constant of integration that represents the initial condition.
Next, integrate velocity to obtain the position function:
\(s(t) = \int (t^2 - 9t + 10) \, dt = \frac{1}{3}t^3 - \frac{9}{2}t^2 + 10t + C_2\).
The constants \(C_1\) and \(C_2\) are determined using initial conditions, showing that integration is a powerful tool in linking various components of motion.
Initial Conditions in Mechanics
Initial conditions are essential to uniquely determine the constants that arise during integration. They provide specific information about the system at a chosen initial time.
Given the initial velocity \(v(0) = 10\, \text{m/s}\) and position \(s(0) = 1\, \text{m}\), these can be used to find \(C_1\) and \(C_2\).
  • For velocity, substitute \(t = 0\) into \(v(t) = t^2 - 9t + C_1\) to get \(10 = 0 + C_1\), resulting in \(C_1 = 10\).
  • For position, substitute \(t = 0\) into \(s(t) = \frac{1}{3}t^3 - \frac{9}{2}t^2 + 10t + C_2\) to get \(1 = C_2\), resulting in \(C_2 = 1\).
These initial conditions are vital as they allow the trajectory of the particle to be accurately described at any subsequent time \(t\). By applying them, we ensure our equations of motion are precise and reflect the true nature of the particle's path.

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