Chapter 3: Problem 4
Simplify the following expressions: (a) \(\cos A \tan A\) (b) \(\sin \theta \cot \theta\)(c) \(\tan B \operatorname{cosec} B\) (d) \(\cot 2 x \sec 2 x\) (e) \(\tan \theta \tan \left(\frac{\pi}{2}+\theta\right)\) (f) \(\frac{\sin 2 t}{\cos t}\) [Hint: see Question 2.] (g) \(\sin ^{2} A+2 \cos ^{2} A\) (h) \(2 \cos ^{2} B-1\) (i) \(\left(1+\cot ^{2} X\right) \tan ^{2} X\) (j) \(\left(\sin ^{2} A+\cos ^{2} A\right)^{2}\) (k) \(\frac{1}{2} \sin 2 A \tan A\) (1) \(\left(\sec ^{2} t-1\right) \cos ^{2} t\) (m) \(\frac{\sin 2 A}{\cos 2 A}\) (n) \(\frac{\sin A}{\sin 2 A}\) (o) \(\left(\tan ^{2} \theta+1\right) \cot ^{2} \theta\) (p) \(\cos 2 A+2 \sin ^{2} A\)
Short Answer
Step by step solution
Simplify cos A tan A
Simplify sin theta cot theta
Simplify tan B cosec B
Simplify cot 2x sec 2x
Simplify tan theta tan (pi/2 + theta)
Simplify sin 2t / cos t
Simplify sin^2 A + 2 cos^2 A
Simplify 2 cos^2 B - 1
Simplify (1 + cot^2 X) tan^2 X
Simplify (sin^2 A + cos^2 A)^2
Simplify (1/2) sin 2A tan A
Simplify (sec^2 t - 1) cos^2 t
Simplify sin 2A / cos 2A
Simplify sin A / sin 2A
Simplify (tan^2 theta + 1) cot^2 theta
Simplify cos 2A + 2 sin^2 A
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Pythagorean Identity
- \(\sin^2 \theta = 1 - \cos^2 \theta\)
- \(\cos^2 \theta = 1 - \sin^2 \theta\)
- \(1 + \tan^2 \theta = \sec^2 \theta\)
- \(1 + \cot^2 \theta = \csc^2 \theta\)
Trigonometric Simplification
- **Substitution of identities**: Replacing complex functions with equivalent expressions, such as using \(\tan \theta = \frac{\sin \theta}{\cos \theta}\).
- **Cancellation**: Identifying terms that cancel each other out, a common tactic when dealing with fractions.
- **Factorization**: Breaking down expressions into products of simpler terms, aiding in cancellation or further simplification.
Trigonometric Functions
- **Sine (\(\sin\))**
- **Cosine (\(\cos\))**
- **Tangent (\(\tan\))**
- **Cosecant (\(\csc\))**, equivalent to \(\frac{1}{\sin}\)
- **Secant (\(\sec\))**, equivalent to \(\frac{1}{\cos}\)
- **Cotangent (\(\cot\))**, equivalent to \(\frac{1}{\tan}\)