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Calculate the means and standard deviations of: (a) \(1,2,3,4,5\) (b) \(2.1,2.3,2.7,2.6\) (c) \(37,26,19,21,19,25,17\) (d) \(6,6,6,6,6,6\) (e) \(-1,2,-3,4,-5,6\)

Short Answer

Expert verified
(a) Mean: 3, SD: 1.41; (b) Mean: 2.425, SD: 0.2385; (c) Mean: 23.43, SD: 5.827; (d) Mean: 6, SD: 0; (e) Mean: 0.5, SD: 3.86.

Step by step solution

01

Calculate the Mean of List (a)

The mean of a list of numbers is calculated by taking the sum of the numbers and dividing by the count of numbers. For list (a), which is \(1, 2, 3, 4, 5\):\[\text{Mean} = \frac{1 + 2 + 3 + 4 + 5}{5} = \frac{15}{5} = 3\]
02

Calculate the Standard Deviation of List (a)

First, find the variance by calculating the average of the squared differences from the Mean. Then take the square root of the variance.For list (a):\[1^2 + 2^2 + 3^2 + 4^2 + 5^2 = 1 + 4 + 9 + 16 + 25 = 55\]\[\text{Variance} = \frac{(1-3)^2 + (2-3)^2 + (3-3)^2 + (4-3)^2 + (5-3)^2}{5} = \frac{4 + 1 + 0 + 1 + 4}{5} = \frac{10}{5} = 2\]\[\text{Standard Deviation} = \sqrt{2} \approx 1.41\]
03

Calculate the Mean of List (b)

For list (b), which is \(2.1, 2.3, 2.7, 2.6\):\[\text{Mean} = \frac{2.1 + 2.3 + 2.7 + 2.6}{4} = \frac{9.7}{4} = 2.425\]
04

Calculate the Standard Deviation of List (b)

Calculate the variance:\[\text{Variance} = \frac{(2.1-2.425)^2 + (2.3-2.425)^2 + (2.7-2.425)^2 + (2.6-2.425)^2}{4}\]\[= \frac{0.105625 + 0.015625 + 0.075625 + 0.030625}{4} = \frac{0.2275}{4} = 0.056875\]\[\text{Standard Deviation} = \sqrt{0.056875} \approx 0.2385\]
05

Calculate the Mean of List (c)

For list (c), which is \(37, 26, 19, 21, 19, 25, 17\):\[\text{Mean} = \frac{37 + 26 + 19 + 21 + 19 + 25 + 17}{7} = \frac{164}{7} \approx 23.43\]
06

Calculate the Standard Deviation of List (c)

Calculate the variance for list (c):\[\text{Variance} = \frac{(37-23.43)^2 + (26-23.43)^2 + (19-23.43)^2 + (21-23.43)^2 + (19-23.43)^2 + (25-23.43)^2 + (17-23.43)^2}{7}\]Calculating each squared difference and averaging:\[= \frac{(13.57)^2 + (2.57)^2 + (4.43)^2 + (2.43)^2 + (4.43)^2 + (1.57)^2 + (6.43)^2}{7} = \frac{237.77}{7} \approx 33.967\]\[\text{Standard Deviation} \approx \sqrt{33.967} \approx 5.827\]
07

Calculate the Mean of List (d)

For list (d), which is \(6, 6, 6, 6, 6, 6\):\[\text{Mean} = \frac{6 + 6 + 6 + 6 + 6 + 6}{6} = 6\]
08

Calculate the Standard Deviation of List (d)

All values are identical to the mean, so all squared differences are zero, thus variance and standard deviation are zero:\[\text{Variance} = 0, \quad \text{Standard Deviation} = 0\]
09

Calculate the Mean of List (e)

For list (e), which is \(-1, 2, -3, 4, -5, 6\):\[\text{Mean} = \frac{-1 + 2 - 3 + 4 - 5 + 6}{6} = \frac{3}{6} = 0.5\]
10

Calculate the Standard Deviation of List (e)

Calculate the variance for list (e):\[\text{Variance} = \frac{(-1-0.5)^2 + (2-0.5)^2 + (-3-0.5)^2 + (4-0.5)^2 + (-5-0.5)^2 + (6-0.5)^2}{6}\]\[= \frac{2.25 + 2.25 + 12.25 + 12.25 + 30.25 + 30.25}{6} = \frac{89.5}{6} \approx 14.917\]\[\text{Standard Deviation} \approx \sqrt{14.917} \approx 3.86\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean
When we talk about the mean in statistics, we are discussing a measure known as the average. It provides a single, representative value of a data set, offering an easy way to understand the typical magnitude of values. To calculate the mean, add together all numbers in your dataset and then divide by the total count of numbers.
For example, if you have the numbers 1, 2, 3, 4, and 5:

\[\text{Mean} = \frac{1 + 2 + 3 + 4 + 5}{5} = 3\]

Here, 3 is the mean. It's a quick snapshot of the distribution and center point of the data set.
Standard Deviation
Standard deviation is a measure that helps you understand how spread out the numbers in a data set are around the mean. In simpler terms, it tells you how much the values deviate from the average. A small standard deviation means numbers are very close to the average, while a large one indicates numbers are spread out.

Calculating standard deviation involves finding the square root of the variance. For example, suppose you have the dataset 1, 2, 3, 4, 5, and you need the standard deviation:

- Calculate the mean, as we did earlier.
- Find differences between each number and the mean and square them: \((1-3)^2, (2-3)^2, ... \)
- Calculate the average of those squared differences to get variance.
- Take the square root of the variance.

This calculation tells us how much deviation exists from the average, providing insight into data consistency.
Variance
Variance plays a crucial role in statistics as it provides an insight into how data is spread out. It's the average of the squared differences from the mean, and is a stepping stone to calculating the standard deviation.

To find variance, follow these steps:
  • Determine the mean of the data set.
  • Subtract the mean from each number to find the difference.
  • Square each of these differences.
  • Calculate the mean of these squared differences.

For instance, for the data set 1, 2, 3, 4, 5, once you've obtained the mean, replace each number with the square of their difference from the mean, add those numbers, and divide by the number of data points. This value gives you the variance. Understanding variance helps in grasping the degree of data spread.
Data Analysis
Data analysis involves examining datasets to extract useful information and insights. It is a fundamental skill for interpreting large amounts of information that can then be used to make informed decisions. In statistics, analyzing data isn't just about calculating figures like mean or standard deviation but understanding what those figures represent in the context of the dataset.

For example, a data set's mean can show where the average value lies, while variance and standard deviation tell you about how much the data varies. Each of these calculations, through proper analysis, allows you to decide whether data is consistent, predict trends, or identify anomalies. Through systematic steps of organizing, transforming, and evaluating data, conclusions and predictions can be developed that have practical applications in real-world scenarios. Understanding these analyses is crucial, especially since they form the basis of reliable research and decision-making processes in various fields.

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Most popular questions from this chapter

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