Chapter 19: Problem 2
Find the particular solution of the following equations: (a) \(\frac{\mathrm{d} y}{\mathrm{~d} x}+4 y=7, \quad y(0)=1\) (b) \(\frac{\mathrm{d} x}{\mathrm{~d} t}-x=4, \quad x(0)=2\) (c) \(\frac{\mathrm{d} y}{\mathrm{~d} t}=3 y+2, \quad y(0)=2\) (d) \(\frac{\mathrm{d} y}{\mathrm{~d} x}=4 y-8, \quad y(1)=2\)
Short Answer
Step by step solution
Solve Differential Equation (a)
Solve Differential Equation (b)
Solve Differential Equation (c)
Solve Differential Equation (d)
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
First-order linear differential equations
- \( \frac{\mathrm{d} y}{\mathrm{d} x} + P(x)y = Q(x) \)
First-order linear differential equations are common in various fields like physics, engineering, and biology due to their widespread applicability in modeling real-world problems involving rates of change and dynamic systems.
Integrating factor method
To solve an equation of the form:
- \( \frac{\mathrm{d} y}{\mathrm{d} x} + P(x)y = Q(x) \)
This factor is then multiplied to both sides of the equation, transforming it into an exact differential, meaning the left side becomes the derivative of a product. Specifically:
- \( \frac{\mathrm{d}}{\mathrm{d}x}(\mu(x)y) = \mu(x)Q(x) \)
Particular solution
After solving the linear differential equation using the integrating factor or another method, you generally find a general solution that includes a constant of integration \( C \). This general solution represents a family of curves.
- Example: \( y = \frac{7}{4} + Ce^{-4x} \)
For instance, if an initial condition \( y(0) = 1 \) is given, substitute \( x = 0 \) and \( y = 1 \) to find \( C \). The particular solution aligns perfectly with the initial state described, providing one specific curve from the family of potential solutions.
Initial conditions
For example, given a differential equation of form \( \frac{\mathrm{d} y}{\mathrm{d} x} + 4y = 7 \) with an initial condition \( y(0) = 1 \), the initial condition indicates the specific point \( (x, y) \) lies on the solution curve when \( x = 0 \). Initial conditions:
- Provide a way to calculate the constant \( C \) in the general solution.
- Ensure the solution reflects the specific scenario or state.