Chapter 10: Problem 2
Find \(\frac{\mathrm{d} y}{\mathrm{~d} x}\) when (a) \(y=\frac{1}{\sqrt{x}}\) (b) \(y=\mathrm{e}^{2 x / 3}\) (c) \(y=\mathrm{e}^{-x / 2}\) (d) \(y=\ln x\) (e) \(y=\operatorname{cosec}\left(\frac{2 x-1}{3}\right)\) (f) \(y=\tan ^{-1}(\pi x+3)\) (g) \(y=\tanh (2 x+1)\) (h) \(y=\sinh ^{-1}(-3 x)\) (i) \(y=\cot (\omega x+\pi)\) (j) \(y=\frac{1}{\sin (5 x+3)}\) (k) \(y=\cos 3 x\) (1) \(y=\frac{1}{\cos 3 x}\) (m) \(y=\tan (2 x+\pi)\) (n) \(y=\operatorname{cosech}\left(\frac{x-1}{2}\right)\) (o) \(y=\tanh ^{-1}\left(\frac{2 x+3}{7}\right)\)
Short Answer
Step by step solution
Derive Part A
Derive Part B
Derive Part C
Derive Part D
Derive Part E
Derive Part F
Derive Part G
Derive Part H
Derive Part I
Derive Part J
Derive Part K
Derive Part L
Derive Part M
Derive Part N
Derive Part O
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Chain Rule in Differentiation
In essence, if you have a function of the form \( y = f(g(x)) \), the chain rule states that the derivative \( \frac{\mathrm{d}y}{\mathrm{d}x} \) is found by differentiating the outer function \( f \) with respect to the inner function \( g \) and then multiplying this by the derivative of \( g \) with respect to \( x \). This can be neatly expressed with the formula:
- Find \( \frac{\mathrm{d}f}{\mathrm{d}g} \).
- Find \( \frac{\mathrm{d}g}{\mathrm{d}x} \).
- Multiply them: \( \frac{\mathrm{d}y}{\mathrm{d}x} = \frac{\mathrm{d}f}{\mathrm{d}g} \times \frac{\mathrm{d}g}{\mathrm{d}x} \).
Utilizing the Power Rule Effectively
Using the power rule saves a lot of time, as it bypasses the need for more complex operations when dealing with polynomial functions.Let's consider the example \( y = \frac{1}{\sqrt{x}} \). First, you rewrite the square root using exponents: \( y = x^{-1/2} \). Applying the power rule means multiplying the exponent \( -1/2 \) by \( x \) and reducing the exponent by one, yielding:
- Multiply exponent with function: \( -1/2 \times x^{-1/2} \).
- Decrease the exponent by 1: new exponent is \( -3/2 \).
Differentiating Trigonometric Functions
- The derivative of \( \sin(u) \) is \( \cos(u) \cdot \frac{\mathrm{d}u}{\mathrm{d}x} \).
- The derivative of \( \cos(u) \) is \( -\sin(u) \cdot \frac{\mathrm{d}u}{\mathrm{d}x} \).
- The derivative of \( \tan(u) \) is \( \sec^2(u) \cdot \frac{\mathrm{d}u}{\mathrm{d}x} \).
For example, with \( y = \tan(2x + \pi) \), applying the rule for tangent gives you the derivative:\[ 2\sec^2(2x + \pi) \]where \( 2 \) is the derivative of the inner function \( \frac{\mathrm{d}u}{\mathrm{d}x} \), which comes from \( u = 2x + \pi \). By recognizing and correctly applying these derivatives, you can tackle a wide range of problems involving trigonometric expressions with confidence.