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The density of water is \(1000 \mathrm{~kg} / \mathrm{m}^{3}\). Express the density of water in \(\mathrm{lb}_{\mathrm{m}} / \mathrm{ft}^{3}\) and \(\mathrm{lb}_{\mathrm{m}} /\) gallon \(\left(7.48\right.\) gallons \(\left.=1 \mathrm{ft}^{3}\right)\).

Short Answer

Expert verified
The density of water in \( \mathrm{lb}_{\mathrm{m}} / \mathrm{ft}^{3} \) is approximately \( 62.43 \, \mathrm{lb}_{\mathrm{m}} / \mathrm{ft}^{3} \) and in \( \mathrm{lb}_{\mathrm{m}} / \mathrm{gallon} \) it is approximately \( 8.35 \, \mathrm{lb}_{\mathrm{m}} / \mathrm{gallon}\).

Step by step solution

01

Convert kg/m^3 to lbm/ft^3

Start by using the given density of water, \( 1000 \, \mathrm{kg/m^3} \), and converting it into \(\mathrm{lb}_{\mathrm{m}} / \mathrm{ft}^{3}\) using the conversion formula: \( 1 \, \mathrm{ft} = 0.3048 \, \mathrm{m} \), \( 1 \, \mathrm{lb}_m = 0.453592 \, \mathrm{kg} \). So, \( 1000 \, \mathrm{kg/m^3} = 1000 \times ( \frac{1 \, \mathrm{lb}_m}{0.453592 \, \mathrm{kg}}) \times ( \frac{1 \, \mathrm{m}}{0.3048 \, \mathrm{ft}})^3\) is approximately equal to \( 62.43 \, \mathrm{lb}_{\mathrm{m}} / \mathrm{ft}^{3}\).
02

Convert lbm/ft^3 to lbm/gallon

Next, convert from \(\mathrm{lb}_{\mathrm{m}} / \mathrm{ft}^{3}\) to \(\mathrm{lb}_{\mathrm{m}} / \) gallon using the conversion ratio: \( 1 \, \mathrm{ft}^3 = 7.48 \) gallons. Therefore, \( 62.43 \, \mathrm{lb}_{\mathrm{m}} / \mathrm{ft}^{3} \times ( \frac{1 \, \mathrm{ft}^{3}}{7.48 \, \mathrm{gallons}}) \) is approximately equal to \( 8.35 \, \mathrm{lb}_{\mathrm{m}} / \mathrm{gallon}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unit Conversion
Unit conversion is a crucial process in a variety of scientific and engineering fields which involves converting a value expressed in one set of units to another. In our exercise, we are tasked with converting the density of water from one unit system (the metric system, kilograms per cubic meter) to another (the imperial system, pounds per cubic feet and pounds per gallon).

To accomplish this conversion, we use conversion factors. These factors are based on the relationship between the two units. For example, to convert kilograms to pounds, we use the fact that 1 pound mass (lbm) is equivalent to 0.453592 kilograms. Similarly, to convert cubic meters to cubic feet, we recognize that one cubic foot is 0.3048 meters cubed.

  • Identify the correct conversion factors between the units.
  • Apply the factors through multiplication or division, ensuring units cancel out appropriately.
  • Keep track of the units throughout the process to avoid mistakes.
Using these principles, we can accurately convert the density of water from metric to imperial units—a skill that is foundational in fields such as chemistry, physics, and engineering.
Mass Density
Mass density, often referred to simply as density, is a measure of mass per unit of volume. It tells us how much mass is contained in a specific volume of a material or substance. The density of water, for example, is a common reference point in the metric system, with a typical value of 1000 kg/m³ at standard temperature and pressure.

The concept of density is essential because it allows us to compare how much matter is packed into different substances or materials. For instance, metals are denser than water, which is why they sink in water.

When working with density:

  • Understanding the relationship between mass and volume is important. This relationship can help determine the buoyancy of an object in a fluid, like water.
  • Density can also be indicative of a substance's composition, as different elements and compounds have characteristic densities.
Density conversion, like the one shown in the exercise, enables us to express this value in different unit systems, depending on the context of the problem or the standards of the industry.
Engineering Fundamentals
Understanding unit conversion and density is part of the engineering fundamentals that underpin many aspects of design, analysis, and practical application in the field. Engineers frequently face problems that require them to use different unit systems and to understand the physical properties of materials.

In the context of our exercise, an engineer might need to convert the density of water from metric to imperial units for various reasons such as:

  • Working with international partners that use a different measurement system.
  • Adhering to industry standards or regulations that specify certain units.
  • Performing calculations for systems that involve components manufactured in different countries.
The ability to accurately and efficiently handle such conversions ensures seamless communication, standardization across international borders, and reduces the likelihood of errors that could result in structural failures or other types of engineering mishaps.

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Most popular questions from this chapter

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Convert the atmospheric pressure in the given un requested units. Show all the conversion step \(14.7 \mathrm{lb}_{\mathrm{f}} / \mathrm{in}^{2}\) to \(\mathrm{lb}_{\mathrm{f}} / \mathrm{ft}^{2}\), (b) \(14.7 \mathrm{lb}_{\mathrm{f}} / \mathrm{in}^{2}\) to \(\mathrm{Pa}\), (c) \(\mathrm{Ib}_{\mathrm{f}} / \mathrm{in}^{2}\) to \(\mathrm{kPa}\), (d) \(14.7 \mathrm{lb}_{\mathrm{f}} / \mathrm{in}^{2}\) to bar \((1 \mathrm{bar}=100\)

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