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Imagine that as an engineering intern you have been assigned the task of selecting a motor for a pump. After reviewing motor catalogs, you narrow your choice to two motors that are rated at \(1.5 \mathrm{~kW}\). Additional information collected is shown in an accompanying table. The pump is expected to run 4200 hours every year. After checking with your electric utility company, you determine the average cost of electricity is about 11 cents per \(\mathrm{kWh}\). Based on the information given here, which one of the motors will you recommend to be purchased? \begin{array}{lll} \text { Criteria } & \text { Motor X } & \text { Motor Y } \\ \hline \text { Expected useful life } & 5 \text { years } & 5 \text { years } \\\ \text { Initial cost } & \$ 300 & \$ 400 \\ \begin{array}{l} \text { Efficiency at the } \\ \text { operating point } \end{array} & 0.75 & 0.85 \\ \begin{array}{l} \text { Estimated } \\ \text { maintenance cost } \end{array} & \$ 12 \text { per year } & \$ 10 \text { per year } \\ & & \end{array}

Short Answer

Expert verified
Motor X or Motor Y will be recommended depending on which one has a lower projected total cost, as calculated in the steps.

Step by step solution

01

Calculation of Electricity Cost

The first step is to calculate the cost of the electricity that each motor consumes. This cost can be calculated by using the motor power rating and conversion factors to find the yearly energy usage in kWh. Then with the given price of electricity, the annual electricity cost can be calculated.
02

Calculation of Total cost for motor X

Then, the total projected cost for the motor X is calculated by adding the initial cost, the estimated maintenance cost for 5 years and the estimated electricity cost for 5 years.
03

Calculation of Total cost for motor Y

Similarly, the total projected cost for the motor Y is calculated by adding the initial cost, the estimated maintenance cost for 5 years and the estimated electricity cost for 5 years.
04

Comparison and Decision

Finally, the total costs for both motors are compared and the motor with the lower total cost is the more cost-effective choice and should be recommended for purchase.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Total Cost Calculation
Understanding total cost calculation plays a crucial role in engineering decision-making, particularly when it comes to selecting equipment. It's not just about the upfront cost; it's the sum of all expenses associated with the purchase and operation over the item's useful life.

In the context of motor selection, total cost includes the initial purchase price, the cost of the energy the motor consumes (calculated from the power rating and operational hours), and the maintenance costs over the motor’s expected life. Engineers must calculate these costs precisely to assess which option yields the most economic value in the long-run. This holistic approach ensures a cost-effective purchase, avoiding the common pitfall of focusing solely on the purchase price.
Electrical Efficiency
When it comes to motor selection, electrical efficiency is a key factor. Electrical efficiency is the percentage of electrical energy that is converted into mechanical energy without being lost as heat or other forms of energy waste.

The higher the efficiency of the motor, the lower the electrical consumption for the same output, resulting in lower operating costs over time. Engineers must balance the efficiency with the initial cost, as high-efficiency motors might cost more up front but save money in energy costs. The efficiency at the operating point is particularly important, as it reflects the motor's performance under typical operating conditions.
Engineering Economics
The field of engineering economics is concerned with the analysis of the costs and benefits associated with engineering projects and decisions. This includes studying how to allocate resources, estimate costs, and make financial decisions that affect the overall economic performance of engineering operations.

In the case of the motor selection exercise, engineering economics principles are applied to compare the total costs of each option—a combination of initial costs, operating energy costs, and maintenance costs. This economic analysis enables engineers to recommend the most financially prudent motor, factoring in all possible costs over its entire lifecycle.
Maintenance Cost Estimation
Accurate maintenance cost estimation is essential for comprehensive total cost calculations. Maintenance costs can vary widely depending on the equipment's design, quality, and the conditions under which it operates.

In the realm of motor selection, engineers estimate these costs based on historical data, manufacturers' information, and operating conditions. Lower maintenance costs can significantly reduce the total cost of ownership, so a slightly more expensive motor with lower anticipated maintenance costs may be the better option in the long term. Careful estimation of maintenance costs will lead to more effective cost management and less downtime due to unexpected repairs or maintenance.

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Most popular questions from this chapter

How long does it take to double a deposit of \(\$ 1000\) a. at a compound annual interest rate of \(6 \%\) b. at a compound annual interest rate of \(7 \%\) c. at a compound annual interest rate of \(8 \%\) d. If instead of \(\$ 1000\) you deposit \(\$ 5000\), would the time to double your money be different in parts (a)-(d)? In other words, is the initial sum of money a factor in determining how long it takes to double your money? Now use your answers to verify a rule of thumb that is commonly used by bankers to determine how long it takes to double a sum of money. The rule of thumb commonly used by bankers is given by time period to double a sum of money \(\approx \frac{72}{\text { interest rate }}\)

Your future company has purchased a machine and has entered into a contract that requires the company to pay \(\$ 2000\) each year for the upgrade of machine components at the end of years 6,7, and \(8 .\) In anticipation of the upgrade cost, your company has decided to deposit equal amounts \((X)\) at the end of each year for five years in a row in an account that pays \(i=6 \%\). The first deposit is made at the end of the first year. What is the value of \(X\) ?

Compute the future value of the following deposits made today: a. \(\$ 10,000\) at \(6.75 \%\) compounding annually for 10 years b. \(\$ 10,000\) at \(6.75 \%\) compounding quarterly for 10 years c. \(\$ 10,000\) at \(6.75 \%\) compounding monthly for 10 years

How much money do you need to deposit in a bank each month if you are planning to have \(\$ 5000\) in four years by the time you get out of college? The bank offers a \(6.75 \%\) interest rate that compounds monthly.

You have accepted a loan in the amount of \(\$ 15,000\) for your new car. You have agreed to pay the loan back in four years. What is your monthly payment if you agree to pay an interest rate of \(9 \%\) compounding monthly? Solve this problem for \(i=6 \%, i=7 \%\), and \(i=8 \%\), each compounding monthly.

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