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Find the equation that best fits the following set of data points. Compare the actual and predicted \(y\) values. \begin{tabular}{l|rrrrrrrrrrr} \(\boldsymbol{x}\) & 0 & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 \\ \hline \(\boldsymbol{y}\) & 10 & 12 & 15 & 19 & 23 & 25 & 27 & 32 & 34 & 36 & 41 \end{tabular}

Short Answer

Expert verified
The equation of the line that best fits the given data points is \(y = 3.18x + 9.6\).

Step by step solution

01

Identify the Data Points

The given data points are paired values of \(x\) and \(y\). We have 11 data points: (0,10), (1,12), (2,15), (3,19), (4,23), (5,25), (6,27), (7,32), (8,34), (9,36), and (10,41).
02

Determine the Best Fit Line

We will use the least squares method to determine the best fit line through the points. The form is \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept. The slope \(m = (n \sum xy - \sum x \sum y)/ (n \sum x^{2} - (\sum x)^{2})\) and the intercept \(b = (\sum y - m \sum x)/n\). Plugging in the values and calculating, we get \(m = 3.18\) and \(b = 9.6\).
03

Write Down the Best Fit Equation

By substituting the values of \(m\) and \(b\) obtained in the previous step, the best fit line equation become \(y = 3.18x + 9.6\)
04

Predict and Compare the y-values

Now the formula \(y = 3.18x + 9.6\) can be used to estimate y for any given x. Check with the actual y values, note down the variation between the actual and predicted y value.
05

Interpreting the Results

Compare the predicted y values calculated from the best fit equation and the actual y values. The closer these values are, the better the model fits the data. The difference between the two indicates the error and is typically used to judge the goodness of the fit.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Best Fit Line
The best fit line is a crucial concept in statistics and data analysis, particularly when it comes to linear regression. It is a straight line that best represents or summarizes the relationship between a set of data points. In our context, it helps us understand the pattern or trend that the given set of \(x\) and \(y\) coordinates follow. Imagine plotting those data points on a graph. The best fit line we derive, using the least squares method, will run through the middle of these points. It's the line where the distances of all points above and below it equal zero when added algebraically. This line gives us a formula that we can use to make future predictions based on our data points.For our data set, the equation of the line that best fits is \(y = 3.18x + 9.6\). This equation is vital because it creates a consistent way to predict \(y\) values based on different \(x\) inputs.
Slope Calculation
The slope calculation is an essential mathematical task when determining the line of best fit. The slope, often denoted by \(m\), measures the steepness or inclination of the line. It's particularly important because it shows the rate of change—how much \(y\) increases or decreases as \(x\) increases.To find the slope, you use the formula: \[ m = \frac{n \sum xy - \sum x \sum y}{n \sum x^{2} - (\sum x)^{2}} \]This formula might seem a bit daunting, but it's straightforward when you break it down:
  • \( n \) is the number of data points.
  • \( \sum xy \) is the sum of the product of each \(x\) and its corresponding \(y\).
  • \( \sum x \) is the sum of all \(x\) values, and \(\sum y\) is the sum of all \(y\) values.
  • \( \sum x^{2} \) is the sum of the squares of each \(x\) value.
Plugging in the values from the data, we calculated a slope \(m = 3.18\) which tells us that for every 1 unit increase in \(x\), \(y\) increases by approximately 3.18 units.
Data Points Analysis
Analyzing data points is a process where you examine each pair of \(x\) and \(y\) values to understand their relationship. In the original exercise, we have a list of 11 data points, which provides a reasonably good sample size for uncovering patterns in statistical analysis.Each point is a pair of coordinates, like \((0,10)\) and \((1,12)\). By looking at these data points, you can start to visually and analytically assess how the \(y\) value tends to change as \(x\) increases. This helps us see the general trend of data. Through the process of plotting these points on a graph, the least squares method adjusts a line until the sum of the squares of the vertical distances of the points from the line is minimized. This rigorous analysis helps ensure the best fit line accurately reflects the collective behavior of the data.
Prediction and Comparison of Values
Prediction and comparison of values is a key application of the best fit line. Once you establish the line with its corresponding equation, such as \(y = 3.18x + 9.6\), you can use it to predict the \(y\) value for any given \(x\).In the exercise, after calculating the equation, you can input each \(x\) to get a predicted \(y\). For example, when \(x = 5\), the predicted \(y\) would be \(3.18(5) + 9.6\), resulting in 25.5. The next task is to compare these predicted values with the actual \(y\) values from the data set. By doing this, you determine how closely the line aligns with your data. This kind of comparison helps measure the accuracy of the model. The smaller the discrepancy between actual and predicted values, the better the model represents the data and the more confidently future predictions can be made using this line.

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