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The incident voltage wave on a certain lossless transmission line for which \(Z_{0}=50 \Omega\) and \(v_{p}=2 \times 10^{8} \mathrm{~m} / \mathrm{s}\) is \(V^{+}(z, t)=200 \cos (\omega t-\pi z)\) V. \((a)\) Find \(\omega .(b)\) Find \(I^{+}(z, t) .\) The section of line for which \(z>0\) is replaced by a load \(Z_{L}=50+j 30 \Omega\) at \(z=0 .\) Find: \((c) \Gamma_{L} ;(d) V_{s}^{-}(z) ;(e) V_{s}\) at \(z=-2.2 \mathrm{~m}\)

Short Answer

Expert verified
Question: Determine the angular frequency (蠅) and incident current wave (I鈦(z, t)) for a lossless transmission line with the given incident voltage wave V鈦(z, t) = 200 cos(蠅t - 蟺z) V, characteristic impedance Z鈧 = 50 惟, phase velocity v鈧 = 2 * 10^8 m/s, and load impedance Z鈧 = 50 + j30 惟 at z = 0. Answer: The angular frequency (蠅) is omega, and the incident current wave (I鈦(z, t)) is 4 cos(蠅t - 蟺z) A.

Step by step solution

01

Identify the given values

Here's what we know: V鈦(z, t) = 200 cos(蠅t - 蟺z) V Z鈧 = 50 惟 (characteristic impedance) v鈧 = 2 * 10^8 m/s (phase velocity) Z鈧 = 50 + j30 惟 (load impedance)
02

Find 蠅 (angular frequency)

The equation for V鈦(z, t) is given as: V鈦(z, t) = 200 cos(蠅t - 蟺z) Comparing this with the general equation of a wave V(z, t) = A cos(蠅t 卤 尾z), we can identify 蠅 as the coefficient of 't': 蠅 = coefficient of 't' = omega
03

Calculate I鈦(z, t) (incident current wave)

To find I鈦(z, t), we need to divide V鈦(z, t) by the characteristic impedance, Z鈧: I鈦(z, t) = V鈦(z, t) / Z鈧 Plug in the given values and simplify: I鈦(z, t) = (200 cos(蠅t - 蟺z)) / 50 I鈦(z, t) = 4 cos(蠅t - 蟺z) A
04

Calculate 螕鈧 (reflection coefficient at the load)

Use the formula for the reflection coefficient at the load: 螕鈧 = (Z鈧 - Z鈧) / (Z鈧 + Z鈧) Plug in the given values and simplify: 螕鈧 = ((50 + j30) - 50) / ((50 + j30) + 50) 螕鈧 = j30 / (100 + j30)
05

Calculate V鈧涒伝(z) (reflected voltage wave)

We can find the reflected voltage wave using the reflection coefficient and incident voltage wave: V鈧涒伝(z) = 螕鈧 * V鈦(z, t=z/v鈧) Plug in the values and simplify: V鈧涒伝(z) = (j30 / (100 + j30)) * 200 cos(蠅(z/v鈧) - 蟺z)
06

Calculate V鈧 at z = -2.2m

To find the voltage at z = -2.2m, we need to add the incident and reflected voltage waves: V鈧 = V鈦(z, t) + V鈧涒伝(z) Plug in the values for V鈦(z, t) and V鈧涒伝(z), and set z = -2.2m: V鈧 = [200 cos(蠅t - 蟺 * -2.2)] + [(j30 / (100 + j30)) * 200 cos(蠅 * (-2.2/v鈧) + 蟺 * -2.2)] Now, we can compute the final results: (a) 蠅 = omega (b) I鈦(z, t) = 4 cos(蠅t - 蟺z) A (c) 螕鈧 = j30 / (100 + j30) (d) V鈧涒伝(z) = (j30 / (100 + j30)) * 200 cos(蠅(z/v鈧) - 蟺z) (e) V鈧 = [200 cos(蠅t - 蟺 * -2.2)] + [(j30 / (100 + j30)) * 200 cos(蠅 * (-2.2/v鈧) + 蟺 * -2.2)]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Incident Voltage Wave
In transmission lines, the incident voltage wave represents the portion of electrical energy moving towards a load. In our exercise, this is given by the waveform \( V^{+}(z, t) = 200 \cos(\omega t - \pi z) \) V. Here, \( \omega \) is the angular frequency, and \( \pi \) is the propagation constant expressed as a function of the distance \( z \). The goal is to understand that the incident wave travels without any reflection or interference initially.
Understanding the incident voltage wave is crucial because it tells us about the initial voltage directed towards the load before any part of the signal gets reflected back. When energy is transmitted through the line, a portion of it is absorbed by the load, and the rest may be reflected back, especially if the load impedance is not perfectly matched with the characteristic impedance of the line.
Reflection Coefficient
The reflection coefficient, denoted as \( \Gamma \), is a vital parameter in understanding how much of the wave is reflected back towards the source. It is calculated using the load impedance \( Z_L \) and the characteristic impedance \( Z_0 \) of the line. The formula for the load reflection coefficient is:
\[\Gamma_{L} = \frac{Z_{L} - Z_{0}}{Z_{L} + Z_{0}}\]
This coefficient can take values from -1 to 1, where -1 indicates a total conversion of energy back towards the source, 0 indicates a perfectly matched line with no reflection, and 1 indicates a total reflection.
In the given problem, the load \( Z_L = 50 + j30 \Omega \) differs from the characteristic impedance \( Z_0 = 50 \Omega \), yielding a reflection coefficient \( \Gamma_{L} = \frac{j30}{100 + j30} \). This implies partial reflection due to the reactive component of the load.
Characteristic Impedance
The characteristic impedance \( Z_0 \) of a transmission line is the fundamental parameter that describes its innate opposition to the flow of alternating current (AC) waves. It is a real number for lossless lines, like \( Z_0 = 50 \Omega \) in our example, ensuring that the transmitted signal maintains its integrity over the length of the line.
When the load impedance \( Z_L \) perfectly matches \( Z_0 \), there's no reflected wave, meaning all incident energy is transferred to the load. The relationship between the incident and reflected waves is heavily reliant on \( Z_0 \). In mismatched lines, impedance ensures understanding of how waves will behave at discontinuities or load changes, influencing the voltage and current distribution.
Angular Frequency
Angular frequency \( \omega \) is a measure of the rate of oscillation of the wave and is typically measured in radians per second. Derived from the wave equation \( \omega = 2 \pi f \), where \( f \) is the frequency in Hz, it dictates how rapidly the wave oscillations occur.
In our specific exercise, although \( \omega \) isn't directly given, it can be extracted from comparison in the wave equation format \( V^{+}(z, t) = A \cos(\omega t - \beta z) \). It's identified as the coefficient of \( t \) in \( 200 \cos(\omega t - \pi z) \) V.
Angular frequency is essential since it affects how quickly the wave's phase changes over time, impacting both the timing and potential interference patterns within the transmission line network.

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Most popular questions from this chapter

Two lossless transmission lines having different characteristic impedances are to be joined end to end. The impedances are \(Z_{01}=100 \Omega\) and \(Z_{03}=25 \Omega\). The operating frequency is \(1 \mathrm{GHz}\). \((a)\) Find the required characteristic impedance, \(Z_{02}\), of a quarter-wave section to be inserted between the two, which will impedance-match the joint, thus allowing total power transmission through the three lines. \((b)\) The capacitance per unit length of the intermediate line is found to be \(100 \mathrm{pF} / \mathrm{m}\). Find the shortest length in meters of this line that is needed to satisfy the impedance-matching condition. ( \(c\) ) With the three-segment setup as found in parts \((a)\) and \((b)\), the frequency is now doubled to \(2 \mathrm{GHz}\). Find the input impedance at the line-1-to-line- 2 junction, seen by waves incident from line \(1 .(d)\) Under the conditions of part \((c)\), and with power incident from line 1 , evaluate the standing wave ratio that will be measured in line 1 , and the fraction of the incident power from line 1 that is reflected and propagates back to the line 1 input.

A sinusoidal voltage wave of amplitude \(V_{0}\), frequency \(\omega\), and phase constant \(\beta\) propagates in the forward \(z\) direction toward the open load end in a lossless transmission line of characteristic impedance \(Z_{0}\). At the end, the wave totally reflects with zero phase shift, and the reflected wave now interferes with the incident wave to yield a standing wave pattern over the line length (as per Example 10.1). Determine the standing wave pattern for the current in the line. Express the result in real instantaneous form and simplify.

A standing wave ratio of \(2.5\) exists on a lossless \(60 \Omega\) line. Probe measurements locate a voltage minimum on the line whose location is marked by a small scratch on the line. When the load is replaced by a short circuit, the minima are \(25 \mathrm{~cm}\) apart, and one minimum is located at a point \(7 \mathrm{~cm}\) toward the source from the scratch. Find \(Z_{L}\).

In order to compare the relative sharpness of the maxima and minima of a standing wave, assume a \(\operatorname{load} z_{L}=4+j 0\) is located at \(z=0 .\) Let \(|V|_{\min }=1\) and \(\lambda=1 \mathrm{~m}\). Determine the width of the \((a)\) minimum where \(|V|<1.1 ;(b)\) maximum where \(|V|>4 / 1.1\).

A \(50-\Omega\) lossless line is of length \(1.1 \lambda\). It is terminated by an unknown load impedance. The input end of the \(50-\Omega\) line is attached to the load end of a lossless \(75-\Omega\) line. A VSWR of 4 is measured on the \(75-\Omega\) line, on which the first voltage maximum occurs at a distance of \(0.2 \lambda\) in front of the junction between the two lines. Use the Smith chart to find the unknown load impedance.

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