/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 A \(200 \mathrm{~m}\) runner wit... [FREE SOLUTION] | 91Ó°ÊÓ

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A \(200 \mathrm{~m}\) runner with a mass of \(70 \mathrm{~kg}\) has an approximately constant speed of \(10 \mathrm{~m} / \mathrm{s}\) through the first curve. The radius of curvature is \(R=25 \mathrm{~m}\). (a) Find the friction force \(f\) on the sprinter through the curve. (b) If we assume that the sprinter is not slipping, how large must the coefficient of static friction be for the sprinter to make the turn?

Short Answer

Expert verified
(a) The friction force is 280 N.(b) The coefficient of static friction is 0.408.

Step by step solution

01

- Determine the centripetal force

To find the friction force acting on the sprinter, start by calculating the centripetal force. The formula for centripetal force is \[ F_c = \frac{mv^2}{R} \]
02

- Plug in the known values

Substitute the given values into the centripetal force formula: mass (\(m = 70 \text{ kg}\)), velocity (\(v = 10 \text{ m/s}\)) and radius of curvature (\(R = 25 \text{ m}\)):\[ F_c = \frac{70 \text{ kg} \times (10 \text{ m/s})^2}{25 \text{ m}} \]
03

- Solve for centripetal force

Calculate the centripetal force:\[ F_c = \frac{70 \times 100}{25} = \frac{7000}{25} = 280 \text{ N} \]
04

- Friction force

The friction force is equal to the centripetal force for the sprinter to make the turn without slipping:\[ f = F_c = 280 \text{ N} \]
05

- Determine the normal force

To find the coefficient of static friction, first calculate the normal force. Since the sprinter is on a flat surface, the normal force (\(F_n\)) is equal to the gravitational force:\[ F_n = mg = 70 \text{ kg} \times 9.8 \text{ m/s}^2 = 686 \text{ N} \]
06

- Calculate the coefficient of static friction

Use the formula \( f = \text{μ}_s F_n\) to find the coefficient of static friction (\(\text{μ}_s\)): \[ \text{μ}_s = \frac{f}{F_n} = \frac{280 \text{ N}}{686 \text{ N}} \]
07

- Solve for the coefficient of static friction

Calculate the coefficient of static friction:\[ \text{μ}_s = 0.408 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Centripetal Force
When an object moves in a circular path, it experiences a force directed towards the center of the circle. This force is known as the centripetal force. It is essential for keeping the object in its curved trajectory. The formula for calculating centripetal force is \( F_c = \frac{mv^2}{R} \). Here, \( m \) represents the mass of the object, \( v \) is its velocity, and \( R \) is the radius of curvature.

In the given exercise, we calculated the centripetal force acting on a 200 m runner with a mass of 70 kg moving at a constant speed of 10 m/s along a curve with a radius of 25 m. Substituting these values into the formula, we found that the centripetal force is 280 N. This force is critical in determining other factors like friction and normal force.
Coefficient of Static Friction
The coefficient of static friction (\text{μ}_s) measures how strongly two surfaces resist sliding against each other without movement. It is a dimensionless value that varies depending on the materials in contact. The formula to calculate the coefficient of static friction when an object is on a flat surface and not slipping is \( \text{μ}_s = \frac{f}{F_n} \), where \( f \) is the frictional force and \( F_n \) is the normal force.

In our exercise, after calculating the frictional force (which equals the centripetal force) and the normal force, we found \( \text{μ}_s \) to be 0.408. This value indicates the minimum coefficient of static friction necessary for the runner to navigate the curve without slipping. Without sufficient static friction, the runner would lose grip and fall.
Normal Force
Normal force (\text{F_n}) is the perpendicular force exerted by a surface against an object resting on it. It balances the object's weight and ensures it stays stationary on the surface. On a flat, horizontal surface, the normal force is equal to the gravitational force acting on the object, which can be calculated using the formula \( F_n = mg \), where \( m \) is the mass and \( g \) is the acceleration due to gravity (9.8 m/s²).

In the exercise, we calculated the normal force for a 70 kg runner, finding it to be 686 N. This normal force plays a crucial role in determining the frictional force and the coefficient of static friction, which are vital for analyzing the runner's motion through the curve.
Kinematics
Kinematics is the branch of physics that studies the motion of objects without considering the forces causing that motion. It involves analyzing parameters such as displacement, velocity, and acceleration. These parameters help us understand how objects move under various conditions.

In our given exercise, kinematics plays a vital role as the runner's constant speed (velocity) and the circular path (curvature radius) are crucial factors. By understanding these, we can apply kinematic equations to determine other aspects like centripetal force. This knowledge is foundational for solving complex motion problems and understanding how forces interact to produce movement.

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