/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 In the film "The World's Fastest... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 4: Problem 17

In the film "The World's Fastest Indian" Anthony Hopkins plays Burt Munro who reaches a velocity of 201 mph in his 1920 Indian motorcycle. (a) At this velocity, how far does the Indian travel in 10 s? (b) How long time does the Indian need to travel \(1 \mathrm{~km}\) ?

Short Answer

Expert verified
(a) 2944 feet. (b) 11.14 seconds.

Step by step solution

01

Convert Velocity from mph to fps

First, convert the velocity from miles per hour (mph) to feet per second (fps) using the conversion factors:1 mile = 5280 feet1 hour = 3600 seconds.Thus, velocity in fps is calculated as follows: \[201 \text{ mph} = 201 \times \frac{5280 \text{ feet}}{3600 \text{ seconds}} = 294.4 \text{ fps}\]
02

Calculate Distance in 10 Seconds

Use the formula for distance traveled: \[\text{Distance} = \text{Velocity} \times \text{Time}\]Substitute the values from Step 1 and the given time (10 seconds):\[\text{Distance} = 294.4 \text{ fps} \times 10 \text{ s} = 2944 \text{ feet}\]
03

Convert 1 km to feet

To find out how long it takes to travel 1 kilometer, first convert kilometers to feet. 1 kilometer is equal to 3280.84 feet.\[1 \text{ km} = 3280.84 \text{ feet}\]
04

Calculate Time to Travel 1 km

Using the formula for time taken:\[\text{Time} = \frac{\text{Distance}}{\text{Velocity}}\]Substitute the distance (3280.84 feet) and the velocity (294.4 fps): \[\text{Time} = \frac{3280.84 \text{ feet}}{294.4 \text{ fps}} \text{Time} 鈮� 11.14 \text{ seconds}\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conversion of Units
When solving physics problems, especially in elementary mechanics, it's crucial to use consistent units. This means converting values from one unit system to another when necessary. For example, if distance is given in miles and time in seconds, you need to convert miles to feet or meters to match the time unit. In our exercise, we converted the speed from miles per hour (mph) to feet per second (fps). Knowing conversion factors is essential: 1 mile is 5280 feet, and 1 hour is 3600 seconds. This allows us to compute velocity in a more manageable unit for the calculations.
Distance Calculation
To find out how far an object travels over time, use the formula:

Distance = Velocity x Time

In our example, after converting Burt Munro's speed to fps (294.4 fps), we needed to determine the distance traveled in 10 seconds. By multiplying the velocity by the time, we get the distance:

294.4 fps x 10 seconds = 2944 feet.

So, the Indian motorcycle travels 2944 feet in 10 seconds at a velocity of 201 mph.
Velocity Conversion
Velocity conversion is a common step in mechanics problems. It involves transforming speed into different units to match the other values in a problem. In our example, Burt Munro's motorcycle speed was initially given in mph. To facilitate calculations, we converted it to fps. Here is how you can do it:

Multiply the speed by the conversion factor:
201 mph x (5280 feet / 1 mile) x (1 hour / 3600 seconds)

This simplifies to:

201 x 5280 / 3600 = 294.4 fps

This conversion is essential because using consistent units makes the math straightforward and less prone to error.
Time Calculation
Another vital aspect of elementary mechanics problems is calculating the time required for an event. This can often be derived using the basic kinematic equation:

Time = Distance / Velocity

For instance, to find out how long it takes the motorcycle to travel 1 kilometer, we first converted 1 km to feet (3280.84 feet). Then, we use the velocity we already converted to fps:

Time = 3280.84 feet / 294.4 fps 鈮� 11.14 seconds

Thus, it takes approximately 11.14 seconds for the motorcycle to travel 1 kilometer. Understanding how to manipulate and use these basic equations is key to solving many elementary mechanics problems.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A car is driving along a straight road. Sketch the position and velocity as a function of time for the car if: (a) The car drives with constant velocity. (b) The car accelerates with a constant acceleration. (c) The car brakes with a constant acceleration.

An electron is shot through a box containing a constant electric field, getting accelerated in the process. The acceleration inside the box is \(a=2000 \mathrm{~m} / \mathrm{s}^{2}\). The width of the box is \(1 \mathrm{~m}\) and the electron enters the box with a velocity of \(100 \mathrm{~m} / \mathrm{s}\). (a) What is the velocity of the electron when it exits the box?

As an expert archer you are able to fire off an arrow with a maximum velocity of \(50 \mathrm{~m} / \mathrm{s}\) when you pull the string a length of \(70 \mathrm{~cm}\). (a) If you assume that the acceleration of the arrow is constant from you release the arrow until it leaves the bow, what is the acceleration of the arrow?

Your roommate sets off early to school, walking leisurely at \(0.5 \mathrm{~m} / \mathrm{s}\). Thirty minutes after she left, you realize that she forgot her lecture notes. You decide to run after her to give her the notes. You run at a healthy \(3 \mathrm{~m} / \mathrm{s}\). (a) What is her position when you start running? (b) What is your position when \(tt_{1}\). (k) How can you use this result to find where you catch up with your roommate? (1) Where do you catch up with your roommate? (m) What parts of your solution strategy are general, that is, what parts of your strategy do not change if we change how either person moves?

When the heliobacter bacteria swims, it is driven by the rotational motion of its tiny tail. It swims almost at a constant velocity, with small fluctuations due to variations in the rotational motion. As a simple model for the motion, we assume that the bacteria starts with the velocity \(v=10 \mu \mathrm{m} / \mathrm{s}\) at the time \(t=0 \mathrm{~s}\), and is then subject to the acceleration, \(a(t)=a_{0} \sin (2 \pi t / T)\), where \(a_{0}=1 \mu \mathrm{m} / \mathrm{s}^{2}\), and \(T=1 \mathrm{~ms}\). (a) Find the velocity of the bacterium as a function of time. (b) Find the position of the bacterium as a function of time. (c) Find the average velocity of the bacterium after a time \(t=10 T\).
See all solutions

Recommended explanations on Physics Textbooks

Magnetism

Read Explanation

Kinematics Physics

Read Explanation

Mechanics and Materials

Read Explanation

Particle Model of Matter

Read Explanation

Atoms and Radioactivity

Read Explanation

Classical Mechanics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.