/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 The peak value of the ingut to a... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 2: Problem 3

The peak value of the ingut to a half-wave rectifict is \(10 \mathrm{~V}\). The approximate peak value of the output is (a) \(10 \mathrm{~V}\) (b) \(3.18 \mathrm{~V}\) (c) \(10.7 \mathrm{~V}\) (d) \(9.3 \mathrm{~V}\)

Short Answer

Expert verified
The approximate peak value of the output voltage for a half-wave rectifier with an input peak value of 10V is \(10 \mathrm{~V}\) (Option a).

Step by step solution

01

Understanding Half-Wave Rectification

In a half-wave rectifier, the output waveform has the same amplitude as the input waveform during the passing half-cycle, but it is zero during the blocked half-cycle. Because only one half of the input waveform is allowed to pass, the output waveform remains positive (or negative) without changing its peak value.
02

Compare the Given Options

We can analyze the options given to see which one is correct: (a) 10 V: This matches the peak value of the input waveform, which would be the case if no voltage is lost in the rectifier. (b) 3.18 V: This value is significantly lower than the input peak value, indicating a significant voltage loss in the rectifier, which is unlikely. (c) 10.7 V: The output peak value cannot be higher than the input peak value, so this option is incorrect. (d) 9.3 V: This value is slightly lower than the input peak value, indicating a small voltage loss that might be expected in a rectifier.
03

Choose the Correct Option

Considering the characteristics of a half-wave rectifier and comparing the options provided, we can conclude that the approximate peak value of the output voltage is: (a) 10 V

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

If the iop dicde on the circuit board in Figure \(2-84\) is mcorrectly inssalled back ward?, what veltage would you measare at vest point 8 ?

A certuin rectifier filter produces s de output voltage of 75 . with a penk- to-peak ripple voltage of \(0.5 \mathrm{~V}\). Calculote the ripple foctor.

If the lond resistance of a capxitor-filtered full-wave rectifier is redticed, the ripple voltage (a) increases (b) decreases (c) is not affected (d) has a different frequency

When the ruls output voltage of a bridge full-wave rectifier is \(20 \mathrm{~V}\), the peak inverse voltupte nerros the diodes is (ncylecting the diode drop) (a) \(20 \mathrm{~V}\) (b) \(40 \mathrm{~V}\) (c) \(28.3 \mathrm{~V}\) (d) \(566 \mathrm{~V}\)

When the peak ouipat soltrge is \(100 \mathrm{~V}_{n}\), the PIV for each diode in a center-tapped full-wave rectificr is (neglecting the diode drop) (a) \(100 \mathrm{~V}\) (b) \(200 \mathrm{~V}\) (c) \(141 \mathrm{~V}\) (d) \(\$ \mathrm{~V} \mathrm{~V}\)
See all solutions

Recommended explanations on Physics Textbooks

Linear Momentum

Read Explanation

Work Energy and Power

Read Explanation

Physics of Motion

Read Explanation

Mechanics and Materials

Read Explanation

Electrostatics

Read Explanation

Geometrical and Physical Optics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.