/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 Show that for a plasma for which... [FREE SOLUTION] | 91Ó°ÊÓ

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Show that for a plasma for which \(\epsilon \simeq \epsilon_{0}\) the plasma frequency in hertz can be found from \(\nu_{P}=8.97 n^{1 / 2}\). As examples of other important plasmas, find \(\nu_{P}\) for (a) a typical gas discharge for which \(n=10^{18}\) (meter) \(^{-3} ;\) and (b) the ionosphere where \(n \approx 10^{10}\) (meter) \(^{-3}\).

Short Answer

Expert verified
The calculated plasma frequencies for a typical gas discharge and the Ionosphere are approximately \(898.7 \: GHz\) and \(8.97 \: GHz\) respectively.

Step by step solution

01

Understand the Formula

The plasma frequency, \(\nu_{P}\), is given by the formula \(\nu_{P}=8.97 n^{1 / 2}\) where \(n\) is the density of the plasma (number of particles per unit volume).
02

Calculate the Plasma Frequency for a Typical Gas Discharge

Substitute \(n = 10^{18} m^{-3}\) into the formula \(\nu_{P}=8.97 n^{1 / 2}\). Calculate \(\nu_{P}\) for these values using the formula: \(\nu_{P}=8.97 * (10^{18})^{1 / 2} \).
03

Calculate the Plasma Frequency for the Ionosphere

Substitute \(n = 10^{10} m^{-3}\) into the formula \(\nu_{P}=8.97 n^{1 / 2}\). Calculate \(\nu_{P}\) for these values using the formula: \(\nu_{P}=8.97 * (10^{10})^{1 / 2} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Electromagnetic Fields
Electromagnetic fields (EMFs) are fundamental to the understanding of how plasmas interact with their environment. An EMF is a physical field produced by electrically charged objects, affecting the behavior of charged objects in the vicinity of the field. The interaction of charged particles with electromagnetic fields is what gives rise to the concept of plasma frequency.

Imagine a sea of electrons moving back and forth in response to an electric field; this motion is characteristic of a plasma and is described by the plasma frequency, , which indicates how often the electrons oscillate. This oscillation is critical because it relates to the ability of plasma to absorb and emit electromagnetic radiation. By calculating the plasma frequency, scientists can predict the behavior of plasmas in various scientific and technological applications, such as telecommunications and astrophysics. Being one of the key parameters in plasma physics, the plasma frequency has profound implications on the transmission and reflection of electromagnetic waves through a medium.
Dielectric Constant Explained
The dielectric constant, also known as the relative permittivity, and symbolized by is a measure of a material's ability to store electrical energy in an electric field. Essentially, it quantifies how much electric field (charging) capacity a material has compared to the vacuum of space, which is the baseline with a dielectric constant of 1.

In the original exercise, it's mentioned that for a plasma, the dielectric constant closely approximates to . A plasma, being composed of free electrons and ions, behaves differently than a classic dielectric material because of its high electrical conductivity and collective interactions. However, in the context of plasma frequency, the dielectric constant helps determine how the plasma will react to external electromagnetic fields. The close value to suggests that the plasma's response to electromagnetic fields is similar to that of free space, leading to the simplified calculation of the plasma frequency as proportional to the square root of the particle density.
Particle Density in Plasmas
Particle density is a foundational concept in plasma physics; it defines the number of particles within a unit volume, commonly measured in particles per cubic meter (). Particle density, denoted by , is critical in determining the plasma frequency as it directly impacts how charged particles, such as electrons and ions, interact within a plasma.

Higher particle densities lead to increased interactions, which can enhance the electrical properties of the plasma. It's important because it's these very interactions that define the unique characteristics of plasmas. As seen in the exercise, by knowing the particle density of different plasmas, like a typical gas discharge or the ionosphere, we can calculate their respective plasma frequencies, which in turn dictate how these plasmas will interact with electromagnetic fields, such as radio waves. Consequently, understanding particle density helps in numerous practical applications, from designing neon signs to enhancing satellite communications through the ionosphere.

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Most popular questions from this chapter

Consider a superposition of plane waves all traveling in the same direction in a nonconducting medium. Thus, the real field will be a sum of terms like \((24-35)\), that is, \(\mathbf{E}=\) \(\Sigma_{k} \mathbf{E}_{0 k} \cos \left(k z-\omega_{k} t+\vartheta_{k}\right)\). Show that the timeaverage electric energy density is the sum of the average energy densities associated with each component.

A particle of charge \(q\) and mass \(m\) is traveling with velocity \(\mathbf{u}\) in the field of a plane electromagnetic wave in free space that itself is traveling in the \(z\) direction. Find the force on the particle. What does this become for the special case in which the particle is traveling in the same direction as the wave? What is the direction of the force? Under what conditions (if any) will the force vanish in this case?

Find the ratio \(\left\langle u_{m}\right\rangle /\left\langle u_{e}\right\rangle\) for a plane wave in a conducting medium. Then find the approximate expressions for this ratio for the limiting cases of an insulator and a good conductor.

As was noted after \((24-53)\), a superposition of plane waves traveling in a dispersive medium generally changes its form as it progresses. As an extreme example, consider two waves of equal real amplitudes and with almost the same propagation constants and frequencies that are traveling in the positive \(z\) direction, so that their sum has the form $$ \begin{aligned} \psi=& \psi_{0} e^{i[(k+d k) z-(\omega+d \omega) t]} \\ &+\psi_{0} e^{i[(k-d k) z-(\omega-d \omega) t]} \end{aligned} $$ Show that $$ \begin{aligned} \operatorname{Re} \psi &=2 \psi_{0} \cos [(d k) z-(d \omega) t] \cos (k z-\omega t) \\ &=\psi_{m} \cos (k z-\omega t) \end{aligned} $$ where \(\psi_{m}\) is called the " modulation." Thus (24-143) has the form of a wave with average (24-143) has the form of a wave with average propagation constant \(k\) and average frequency \(\omega\). Its amplitude is not constant, but itself is a wave and travels with the group velocity \(v_{G}\) $$ v_{G}=\frac{d \omega}{d k} $$ What is the spatial period (wavelength) \(\lambda\) of the main wave? What is the wavelength \(\lambda_{m}\) of \(\psi_{m}\) ? Find the ratio \(\lambda_{m} / \lambda\). Sketch (24-143) at \(t=0\), and at a slightly later time, and thus verify that the form of \(\operatorname{Re} \psi\) has changed. Identify which physical feature of your sketch travels with the phase velocity \(v=\omega / k\) and which with the group velocity \(v_{G}\). Why do you think the name "group" velocity was given to (24-144)? (This specific result is an example of the more general phenomenon known as beats.)

A plane electromagnetic wave traveling in a vacuum is given by \(\mathbf{E}=\hat{\mathbf{y}} E_{0} e^{i(k z-\omega t)}\) where \(E_{0}\) is real. A circular loop of radius \(a, N\) turns, and resistance \(R\) is located with its center at the origin. The loop is oriented so that a diameter lies along the \(z\) axis and the plane of the loop makes an angle \(\theta\) with the \(y\) axis. Find the emf induced in the loop as a function of time. Assume that \(a \ll \lambda\). (Why?)

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