/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 (a) An oxygen-16 ion with a mass... [FREE SOLUTION] | 91Ó°ÊÓ

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(a) An oxygen-16 ion with a mass of \(2.66 \times 10^{-26} \mathrm{~kg}\) travels at \(5.00 \times 10^{6} \mathrm{~m} / \mathrm{s}\) perpendicular to a \(1.20-\mathrm{T}\) magnetic field, which makes it move in a circular arc with a 0.231-m radius. What positive charge is on the ion? (b) What is the ratio of this charge to the charge of an electron? (c) Discuss why the ratio found in (b) should be an integer.

Short Answer

Expert verified
The positive charge on the ion is about 4.80 x 10^{-19} C; the charge-to-electron ratio is 3, indicating 3 electrons were lost.

Step by step solution

01

Understand the Problem

We need to find the charge of an oxygen-16 ion moving in a magnetic field at a certain velocity, causing it to move in a circular path of a given radius. We will apply the formula for the radius of curvature in a magnetic field which involves the mass, velocity, magnetic field strength, and the charge of the ion.
02

Apply the Lorentz Force Equation

The centripetal force needed to keep the ion moving in a circular path is provided by the magnetic Lorentz force. Therefore, we equate the magnetic force to the centripetal force: \[ qvB = \frac{mv^2}{r} \]where \( q \) is the charge, \( v \) is the velocity, \( B \) is the magnetic field strength, \( m \) is the mass, and \( r \) is the radius of the path. We can solve for \( q \):\[ q = \frac{mv}{Br} \]
03

Substitute Given Values

Insert the provided values into the equation:\[ m = 2.66 \times 10^{-26} \, \text{kg}, \; v = 5.00 \times 10^{6} \, \text{m/s}, \; B = 1.20 \, \text{T}, \; r = 0.231 \, \text{m} \]\[ q = \frac{(2.66 \times 10^{-26} \, \text{kg})(5.00 \times 10^{6} \, \text{m/s})}{(1.20 \, \text{T})(0.231 \, \text{m})} \]
04

Calculate the Charge

Calculate \( q \) using the values:\[ q = \frac{(2.66 \times 10^{-26})(5.00 \times 10^{6})}{1.20 \times 0.231} \]\[ q = \frac{1.33 \times 10^{-19}}{0.2772} \approx 4.80 \times 10^{-19} \, \text{C} \]
05

Calculate the Charge Ratio

The elementary charge is \( e = 1.60 \times 10^{-19} \, \text{C} \). The ratio of the ion charge to the electron charge is:\[ \frac{q}{e} = \frac{4.80 \times 10^{-19}}{1.60 \times 10^{-19}} = 3 \]
06

Discuss the Charge Ratio

The ratio of 3 suggests the charge on the ion is three times the charge of a single electron, implying it has lost three electrons. This integer ratio is expected because ions typically gain or lose whole numbers of electrons through ionization processes.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lorentz Force
The Lorentz force is the force exerted on a charged particle when it moves through a magnetic field. This concept is fundamental in magnetism physics, as it combines electricity and magnetism to explain how charged particles like ions move in magnetic fields. The Lorentz force is defined by the equation \[ F = q(v \, \times \, B) \] where \( F \) is the force, \( q \) is the charge of the particle, \( v \) is the velocity, and \( B \) is the magnetic field.For ions moving perpendicular to the field, like in our exercise, the interaction is simplified. The force is entirely due to the magnetic field, which means the particle follows a circular path. This principle is essential in the design of particle accelerators and mass spectrometers. Understanding the Lorentz force helps explain various phenomena and allows us to manipulate ions for scientific and industrial purposes.
Ion Charge Calculation
Calculating the charge of an ion involves using several known values and equations related to its motion in a magnetic field. In our exercise, the original equation utilized was the balance between magnetic force and centripetal force, which led to \[ q = \frac{mv}{Br} \] where \( m \) is the mass of the ion, \( v \) is its velocity, \( B \) is the magnetic field strength, and \( r \) is the radius of the resulting circular path.By substituting known values into this equation, we can derive the ion's charge. It's important for students to recognize that such calculations often involve a series of well-established physics relationships and provide important insight into how ions behave under magnetic influence.
Centripetal Force
Centripetal force is what keeps an object moving in a circular path. For a charged particle in a magnetic field, the Lorentz force provides this centripetal force. The equation for centripetal force is \[ F_c = \frac{mv^2}{r} \] where \( F_c \) is the centripetal force, \( m \) is the mass, \( v \) is the velocity, and \( r \) is the radius of the path.When a charged ion navigates through a magnetic field, its path curves due to the interaction of the magnetic force acting as centripetal force. This concept is crucial, as it aids in understanding the motion of charged particles within magnetic fields, helping explain phenomena, from auroras to the workings of various scientific instruments.
Magnetic Field Effects
Magnetic fields exert forces on moving charges, altering their motion. These effects are central to technologies like MRIs, particle detectors, and electric motors. In a magnetic field, charged particles experience a perpendicular force, which makes them follow a curved path, such as circular or spiral. Understanding these effects:
  • Path Shape: Particles move in a circular or helical path depending on their initial velocity relative to the field direction.
  • Speed and Radius: The faster the particle or the stronger the magnetic field, the smaller the radius of the path.
  • Mass and Charge: Heavier particles or those with higher charges have larger radii.
These insights explain why ions behave predictably in magnetic fields, which is crucial for developing instruments that utilize magnetic field properties to study and measure particles.

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Most popular questions from this chapter

(a) Aircraft sometimes acquire small static charges. Suppose a supersonic jet has a \(0.500-\mu \mathrm{C}\) charge and flies due west at a speed of \(660 \mathrm{~m} / \mathrm{s}\) over the Earth's magnetic south pole (near Earth's geographic north pole), where the \(8.00 \times 10^{-5}\) -T magnetic field points straight down. What are the direction and the magnitude of the magnetic force on the plane? (b) Discuss whether the value obtained in part (a) implies this is a significant or negligible effect.

(a) Triply charged uranium-235 and uranium-238 ions are being separated in a mass spectrometer. (The much rarer uranium-235 is used as reactor fuel.) The masses of the ions are \(3.90 \times 10^{-25} \mathrm{~kg}\) and \(3.95 \times 10^{-25} \mathrm{~kg}\), respectively, and they travel at \(3.00 \times 10^{5} \mathrm{~m} / \mathrm{s}\) in a \(0.250-\mathrm{T}\) field. What is the separation between their paths when they hit a target after traversing a semicircle? (b) Discuss whether this distance between their paths seems to be big enough to be practical in the separation of uranium-235 from uranium-238.

A proton moves at \(7.50 \times 10^{7} \mathrm{~m} / \mathrm{s}\) perpendicular to a magnetic field. The field causes the proton to travel in a circular path of radius \(0.800 \mathrm{~m}\). What is the field strength?

A surveyor \(100 \mathrm{~m}\) from a long straight \(200-\mathrm{kV}\) DC power line suspects that its magnetic field may equal that of the Earth and affect compass readings. (a) Calculate the current in the wire needed to create a \(5.00 \times 10^{-5} \mathrm{~T}\) field at this distance. (b) What is unreasonable about this result? (c) Which assumption or premise is responsible?

(a) A 200-turn circular loop of radius \(50.0 \mathrm{~cm}\) is vertical, with its axis on an east-west line. A current of 100 A circulates clockwise in the loop when viewed from the east. The Earth's field here is due north, parallel to the ground, with a strength of \(3.00 \times 10^{-5} \mathrm{~T}\). What are the direction and magnitude of the torque on the loop? (b) Does this device have any practical applications as a motor?

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