Chapter 1: Problem 9
If two equal charges each of \(1 \mathrm{C}\) each are separated in air by a distance of \(1 \mathrm{~km}\), what is the magnitude of the force acting between them? You will see that even at a distance as large as \(1 \mathrm{~km}\), the repulsive force is substantial because \(1 \mathrm{C}\) is a very significant amount of charge.
Short Answer
Step by step solution
Understand Coulomb's Law
Identify the Given Values
Substitute the Values into Coulomb's Law
Perform the Calculations
Conclusion: Force Evaluation
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electrostatic Force
- If both charges are the same, either both positive or both negative, they repel each other.
- If one charge is positive and the other is negative, they attract each other.
1. **The magnitude of the charges** – Larger charges exert a stronger force. 2. **The distance between the charges** – As the distance increases, the force decreases rapidly. This force can be calculated using Coulomb's Law, which gives us a clear mathematical expression to find the magnitude based on these factors. It's amazing, isn't it? Even at large separations like a kilometer, as seen in the exercise, forces can still be substantial!
Point Charges
- Point charges make it easier to apply equations like Coulomb's Law.
- They simplify the calculation of forces and fields in theoretical scenarios.
Coulomb's Constant
- Reflects the medium through which the charges interact; in this case, it is calculated for air or vacuum.
- Shows that the force between charges is significantly strong even at larger distances.