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Finding the vector potential \(*\) See if you can devise a vector potential that will correspond to a uniform field in the \(z\) direction: \(B_{x}=0, B_{y}=0, B_{z}=B_{0}\).

Short Answer

Expert verified
The vector potential \(A\) corresponding to a uniform magnetic field in the \(z\) direction can be [\(A_x=-yB_0\), \(A_y=0\), and \(A_z=0\)].

Step by step solution

01

Analyze the given magnetic field components

The given magnetic field components \(B_{x}\), \(B_{y}\), and \(B_{z}\) are \(0\), \(0\), and \(B_{0}\), respectively. This means that the magnetic field vector \(B\) is uniform and pointing in the \(z\) direction.
02

Formulate the curl of the vector potential

The curl of the vector potential \(A\) is equal to the magnetic field vector \(B\). Expanding it in Cartesian coordinates gives us three equations according to the definition of the curl of a vector, which is \(\nabla \times A = B\).
03

Solve for the vector potential

The above step gives us three equations, but only the third one, \(\frac{\partial A_y}{\partial x} - \frac{\partial A_x}{\partial y} = B_0\), is nontrivial. One of the many solutions can be obtained by setting \(A_y = 0\) and \(A_x = -yB_0\). The z-component \(A_z\) can be zero, since it doesn't affect the solution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Field
Understanding magnetic fields is fundamental in physics, especially when studying electromagnetism. Magnetic fields are represented by vectors that show the direction and strength of magnetic forces. In essence, a magnetic field is an invisible influence, caused by moving electric charges and magnetic dipoles, and is measured in teslas (T).
Magnetic fields exert forces on other moving charges or magnetic materials, and they can be uniform or non-uniform. A uniform magnetic field has the same magnitude and direction at every point within it.
In the given exercise, the magnetic field has components where only the z-component is non-zero: \( B_x = 0 \), \( B_y = 0 \), \( B_z = B_0 \). This indicates that the magnetic field is uniform and directed along the z-axis. Knowing the direction and uniformity of the magnetic field helps in determining the vector potential, which can represent the field through its spatial variation.
Curl of a Vector
The curl of a vector field is a crucial concept in vector calculus, particularly when working with electromagnetic fields. It measures the tendency of a vector field to rotate about a point.
Mathematically, the curl of a vector field \( \mathbf{A} \) is represented as \( abla \times \mathbf{A} \). In three-dimensional Cartesian coordinates, it is given by:
  • \( \left( \frac{\partial A_z}{\partial y} - \frac{\partial A_y}{\partial z} \right) \hat{i} \)
  • \( \left( \frac{\partial A_x}{\partial z} - \frac{\partial A_z}{\partial x} \right) \hat{j} \)
  • \( \left( \frac{\partial A_y}{\partial x} - \frac{\partial A_x}{\partial y} \right) \hat{k} \)
The relation between the vector potential \( \mathbf{A} \) and the magnetic field \( \mathbf{B} \) is given by \( \mathbf{B} = abla \times \mathbf{A} \). Hence, finding the vector potential involves solving the curl equations to match the magnetic field, such as in our exercise where only the z-component equation of \( abla \times \mathbf{A} = B \) is non-trivial.
Cartesian Coordinates
Cartesian coordinates is a coordinate system that specifies each point uniquely in a plane by a pair (or three in 3D) of numerical coordinates, which are the signed distances to the point from two fixed perpendicular directed lines, measured in the same unit of length. The orthogonal axes are conventionally labeled as x, y, and z in three-dimensional space.
In vector calculus and physics, Cartesian coordinates are widely used because they simplify mathematical expressions and calculations, especially when dealing with vector fields like the magnetic field.
Putting the curl of a vector potential and the magnetic field in three-dimensional Cartesian coordinates involves breaking down equations into x, y, and z components. This reduction simplifies the problem to solving individual components, as seen in the exercise where the non-trivial equation involves only x and y when finding the vector potential.
Uniform Field
A uniform field is characterized by its constant magnitude and direction throughout a given space. Whether it's electric or magnetic, a uniform field maintains the same intensity and orientation at every point within the field. This consistency makes it much simpler to analyze and work with mathematically.
Uniform magnetic fields are particularly important in applications like magnetic resonance imaging (MRI) and experimental physics setups, as they provide predictable environments where other variables can be controlled or isolated.
In the given problem, the magnetic field is defined as uniform along the z-axis, implying that the vector field remains the same across any plane parallel to the xy-plane. This uniformity simplifies the calculation of the vector potential, leading to a straightforward solution where certain components (like \( A_y \) and \( A_z \)) can be zero without affecting the uniformity of the magnetic field.

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Most popular questions from this chapter

Maximum field in a cyclotron ** For some purposes it is useful to accelerate negative hydrogen ions in a cyclotron. A negative hydrogen ion, \(\mathrm{H}^{-}\), is a hydrogen atom to which an extra electron has become attached. The attachment is fairly weak; an electric field of only \(4.5 \cdot 10^{8} \mathrm{~V} / \mathrm{m}\) in the frame of the ion (a rather small field by atomic standards) will pull an electron loose, leaving a hydrogen atom. If we want to accelerate \(\mathrm{H}^{-}\)ions up to a kinetic energy of \(1 \mathrm{GeV}\left(10^{9} \mathrm{eV}\right)\), what is the highest magnetic field we dare use to keep them on a circular orbit up to final energy? (To find \(\gamma\) for this problem you only need the rest energy of the \(\mathrm{H}^{-}\)ion, which is of course practically the same as that of the proton, approximately \(1 \mathrm{GeV}\).)

Field from an infinite wire \(* *\) Use the Biot-Savart law to calculate the magnetic field at a distance \(b\) from an infinite straight wire carrying current \(I\).

Scaled-down solenoid ** Consider two solenoids, one of which is a tenth-scale model of the other. The larger solenoid is 2 meters long, 1 meter in diameter, and is wound with \(1 \mathrm{~cm}\) diameter copper wire. When the coil is connected to a \(120 \mathrm{~V}\) direct-current generator, the magnetic field at its center is 1000 gauss. The scaled-down model is exactly onetenth the size in every linear dimension, including the diameter of the wire. The number of turns is the same, and it is designed to provide the same central field. (a) Show that the voltage required is the same, namely \(120 \mathrm{~V}\). (b) Compare the coils with respect to the power dissipated and the difficulty of removing this heat by some cooling means.

Field at the center of a disk * A disk with radius \(R\) and surface charge density \(\sigma\) spins with angular frequency \(\omega\). What is the magnetic field at the center?

Rings with opposite currents Two parallel rings have the same axis and are separated by a small distance \(\epsilon\). They have the same radius \(a\), and they carry the same current \(I\) but in opposite directions. Consider the magnetic field at points on the axis of the rings. The field is zero midway between the rings, because the contributions from the rings cancel. And the field is zero very far away. So it must reach a maximum value at some point in between. Find this point. Work in the approximation where \(\epsilon \ll a\)

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