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Laminated conductor A laminated conductor is made by depositing, alternately, layers of silver 100 angstroms thick and layers of tin 200 angstroms thick ( 1 angstrom \(=10^{-10} \mathrm{~m}\) ). The composite material, considered on a larger scale, may be considered a homogeneous but anisotropic material with an electrical conductivity \(\sigma_{\perp}\) for currents perpendicular to the planes of the layers, and a different conductivity \(\sigma_{1}\) for currents parallel to that plane. Given that the conductivity of silver is \(7.2\) times that of tin, find the ratio \(\sigma_{\perp} / \sigma_{\|}\).

Short Answer

Expert verified
The ratio \( \frac{\sigma_{\perp}}{\sigma_{\|}} \) is approximately \(2.67\)

Step by step solution

01

Define the required variables and expressions

To begin, let's consider the conductivity of tin as \( \sigma \). So, the conductivity of silver becomes \( 7.2 \sigma \). As each silver layer is half as thick as each tin layer, there is twice the amount of silver in a given volume as there is tin.
02

Calculate the conductivity parallel to layers (\( \sigma_{\|} \))

For currents flowing parallel to the layers, each part of the composite material will see both materials in series. Consequently, we can use the formula for resistances in series \( R_{\text{total}} = R_1 + R_2 \), which corresponds to \( \frac{1}{\sigma_{\|}} = \frac{1}{\sigma_{\text{Ag}}} + \frac{1}{\sigma_{\text{Sn}}} \). With some algebraic manipulation, we find that \( \sigma_{\|} = \frac{9.2 \sigma }{3} \).
03

Calculate the conductivity perpendicular to layers (\( \sigma_{\perp} \))

For currents flowing perpendicular to the layers, each part of the composite material witnesses the materials in parallel. We use the formula for resistances in parallel \( \frac{1}{R_{\text{total}}} = \frac{1}{R_1} + \frac{1}{R_2} \) , which corresponds to \( \sigma_{\perp} = \sigma_{\text{Ag}} + \sigma_{\text{Sn}} \), leading to \( \sigma_{\perp} = 8.2 \sigma \).
04

Calculate the ratio \( \frac{\sigma_{\perp}}{\sigma_{\|}} \)

Finally, we just need to substitute the values of \( \sigma_{\|} \) and \( \sigma_{\perp} \) we calculated in steps 2 and 3 into the expression \( \frac{\sigma_{\perp}}{\sigma_{\|}} \), which simplifies to \( \frac{8.2 \sigma }{3.07 \sigma } \). After the reduction we get the result.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Laminated Conductor
A laminated conductor is a type of composite material which consists of alternating layers of different conductive materials, often metals, that are deposited in thin films or layers. In this context, it involves layers of silver and tin. The key advantage of such a configuration is that it often combines the desirable properties of both materials, such as improved conductivity or mechanical strength. This is achieved without significantly increasing the material's volume or weight.
  • Laminated conductors, like in this exercise, are called anisotropic. This means they have directional properties, demonstrating different conductivity in different directions.
  • For example, laminated conductors can have different conductivities when the current is passed parallel or perpendicular to the layers.

This anisotropic nature is significant in applications where customized electrical properties are desired, such as in specialized electronic devices or advanced composites used in aerospace and automotive industries.
Electrical Conductivity
Electrical conductivity is a fundamental property of materials that quantifies how easily they allow electric current to pass through them. It is denoted by the symbol \( \sigma \) and is measured in siemens per meter (S/m).
  • High electrical conductivity indicates a material allows electrons to flow freely, making it a good conductor.
  • Conversely, low conductivity indicates a poor conductor or insulator, where electron flow is restricted.

In laminated conductors, the conductivity can vary significantly based on the direction of the current. This is due to the different conductive properties of the materials making up each layer, such as silver and tin in this problem. Silver is notably a better conductor than tin, leading to varying conductivities depending on the direction of electron flow. Understanding these conductivity variations is critical for designing materials with specific electrical behaviors.
Series and Parallel Circuits
The concepts of series and parallel circuits help explain how electrical conductivity behaves in laminated conductors. When conducting layers are oriented in series, the current passes through one material after the other, affecting the total opposition to flow or resistance.
  • In series, total resistance is the sum of individual resistances: \( R_{\text{total}} = R_1 + R_2 \).
  • For conductivities, it’s the inverse sum \( \frac{1}{\sigma_{\|}} = \frac{1}{\sigma_{\text{Ag}}} + \frac{1}{\sigma_{\text{Sn}}} \).

Alternatively, in parallel circuits, the current divides and flows through both materials simultaneously, with the total resistance being lower:
  • The formula for parallel circuits is \( \frac{1}{R_{\text{total}}} = \frac{1}{R_1} + \frac{1}{R_2} \).
  • For conductivities, this gives \( \sigma_{\perp} = \sigma_{\text{Ag}} + \sigma_{\text{Sn}} \).

Understanding these principles is essential when analyzing the composite layered structures and how they manage electrical currents differently based on orientation.
Silver and Tin Conductivity Ratios
When dealing with composite materials like laminated conductors, calculating conductivity ratios offers insights into their electrical behavior. The given exercise uses silver and tin, two metals with differing conductivity values.
  • Silver is a superior conductor, known to have a conductivity about 7.2 times greater than that of tin.
  • This high difference impacts the overall conductive efficiency of the laminated conductor.

By calculating the ratios of conductivity parallel and perpendicular to the layers, designers can predict how efficiently the current will flow through the material. For instance, in the exercise, finding the ratio \( \frac{\sigma_{\perp}}{\sigma_{\|}} \) shows how much more efficiently current flows perpendicular than parallel to the layers, crucial for applications requiring optimal directional conductivity. Understanding these ratios is vital for creating materials tailored for specific electrical demands, capitalizing on the enhanced properties of composite conductors.

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Most popular questions from this chapter

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