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Stationary rod and moving charge A charge \(q\) moves with speed \(v\) parallel to a long rod with linear charge density \(\lambda\), as shown in Fig. 5.30. The rod is at rest. If the charge \(q\) is a distance \(r\) from the rod, the force on it is simply \(F=q E=q \lambda / 2 \pi r \epsilon_{0}\) Now consider the setup in the frame that moves along with the charge \(q\). What is the force on the charge \(q\) in this new frame? Solve this by: (a) transforming the force from the old frame to the new frame, without caring about what causes the force in the new frame; (b) calculating the electric force in the new frame.

Short Answer

Expert verified
The force on the charge \(q\) in the new frame is \(F'= q \lambda / 2 \pi r \epsilon_{0} \gamma\), which can be obtained either by transforming the force from the old frame or by calculating the force in the new frame.

Step by step solution

01

Initially, calculate the force in the old frame

In the old frame, the rod is stationary and the force on the charge \(q\) is due to the electric field (\(E\)) produced by the rod's linear charge density (\(\lambda\)). The electric field is given by \(\lambda / 2 \pi r \epsilon_{0}\), and the electrostatic force is then, \(F=q E\), which makes the force \(F=q \lambda / 2 \pi r \epsilon_{0}\).
02

Transform the force from the old frame to the new frame

The transformation of force between frames is given by the formula: \(F'= \gamma F\), where \(F'\) is the force in the new frame, \(F\) is the force in the old frame, and \(\gamma\) is the Lorentz factor given by \(\gamma = 1/ \sqrt{1-(v^2/c^2)}\). In this context, since only the magnitude of the velocity factors into the calculation, the direction has no impact. So, in the new frame, the force is \(F'= q \lambda / 2 \pi r \epsilon_{0} \gamma\).
03

Calculate the electric force in the new frame

As previously stated, the force on charge \(q\) in the new frame is due to the electric field produced by the rod's linear charge density. In the moving frame, the charge density will appear to be \(\gamma \lambda\), due to length contraction. Therefore, the electric field will be \(\gamma \lambda / 2 \pi r \epsilon_{0}\), and the force will then be \(F'= q \gamma \lambda / 2 \pi r \epsilon_{0}\). Since this formula for \(F'\) matches the result obtained from transforming the force from the old frame in step 2, the force on the charge in the new frame is the same regardless of which method is employed to calculate it. This is a good sign that the calculations are correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lorentz transformation
The Lorentz transformation is a crucial concept in the realm of electromagnetism and special relativity, named after the physicist Hendrik Lorentz. It allows us to relate the physical measurements taken in one inertial frame of reference to those in another, moving at a constant velocity. The transformation is essential for understanding how various quantities such as time, length, and force change when transitioning between frames.

In our specific scenario, we're concerned with how to transform the force on a charge when it moves relative to a stationary rod. The transformation is governed by the formula:
  • \( F' = \gamma F \)
Here, \( F' \) is the force in the moving frame, \( F \) is the initial force in the stationary frame, and \( \gamma \) (the Lorentz factor) is expressed as:
  • \( \gamma = \frac{1}{\sqrt{1-(v^2/c^2)}} \)
The Lorentz factor accounts for the relativistic effects of time dilation and length contraction. When an object is moving close to the speed of light, these effects become significant and are crucial in accurate force transformation calculations.
Electric field
An electric field is a field around charged particles that exerts a force on other charges within the field. It's a fundamental concept in electromagnetism. In our exercise, the electric field is generated by a rod with a linear charge density, \( \lambda \). For a charge \( q \) at a distance \( r \) from the rod, the field's formula is given by:
  • \( E = \frac{\lambda}{2 \pi r \epsilon_{0}} \)
This describes how the field strength decreases with distance, inversely proportional to the circumference of the circular field lines (which are implied by the factor \( 2\pi r \)).

In the stationary frame, the force on the moving charge is the product of the charge and the electric field:
  • \( F = qE = q\frac{\lambda}{2 \pi r \epsilon_{0}} \)
This relationship illustrates how the presence of the rod's charge density influences the charge \( q \) by exerting a force that is dependent on the field generated by \( \lambda \).
Charge density
Charge density, often symbolized by \( \lambda \) for a linear charge density, is a measure of electric charge per unit length. It is a pivotal factor in defining the strength and distribution of an electric field generated by charged objects.

In our examination, the charge density of the rod is crucial as it determines the magnitude of the electric field surrounding it. The formula for electric field stemming from a line of charge involves \( \lambda \):
  • \( E = \frac{\lambda}{2 \pi r \epsilon_{0}} \)
In a relativistic context, when observing from a frame moving with the charge, the charge density appears altered due to relativistic effects. The new charge density is:
  • \( \gamma \lambda \)
This is due to length contraction, where the length of the rod as observed in the moving frame is shorter, leading to a higher observed charge density.
Relativistic effects
Relativistic effects become significant when objects move at speeds close to that of light, \( c \). These effects are described in Einstein's theory of relativity and include time dilation, length contraction, and variations in mass and force perceptions. In our exercise, we see these effects in force transformation and change of charge density.

Key relativistic principles applied here include:
  • Time dilation and length contraction, which affect the observation of charge density and electric fields.
  • The use of the Lorentz factor, \( \gamma \), which modifies calculations between the stationary and moving frames, ensuring accurate representations of force.
When analyzing how a charge \( q \) moving relative to a rod gets affected, these relativistic effects ensure that transformed physical quantities (like force) are consistent with the laws of physics as seen in different frames. This framework allows us to predict how electromagnetic interactions change as observed from different reference points.

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Most popular questions from this chapter

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