/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 Acquiring transverse momentum ... [FREE SOLUTION] | 91Ó°ÊÓ

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Acquiring transverse momentum In the rest frame of a particle with charge \(q_{1}\), another particle with charge \(q_{2}\) is approaching, moving with velocity \(v\) not small compared with \(c\). If it continues to move in a straight line, it will pass a distance \(b\) from the position of the first particle. It is so massive that its displacement from the straight path during the encounter is small compared with \(b\). Likewise, the first particle is so massive that its displacement from its initial position while the other particle is nearby is also small compared with \(b\).(a) Show that the increment in momentum acquired by each particle as a result of the encounter is perpendicular to \(\mathbf{v}\) and has magnitude \(q_{1} q_{2} / 2 \pi \epsilon_{0} v b\). (Gauss's law can be useful here.) (b) Expressed in terms of the other quantities, how large (in order of magnitude) must the masses of the particles be to justify our assumptions?

Short Answer

Expert verified
The increment in momentum acquired by each particle as a result of the encounter is perpendicular to \( \mathbf{v} \) and has magnitude \( q_{1} q_{2} / 2 \pi \epsilon_{0} v b \). The masses of the particles must be much larger than \( q_{1} q_{2} / 4 \pi \epsilon_{0} v^{2} b \) to justify our assumptions.

Step by step solution

01

Express the Electric Field

The electric field E produced by the charge \( q_{1} \) can be given by Gauss's Law as \( E = q_{1} / 4 \pi \epsilon_{0} r^{2} \) where r is the distance from the charge.
02

Compute the Increment in Momentum

Charges in an electric field will experience a change in momentum. In this scenario, this change is given by \( \Delta p = \int_{-\infty}^{\infty} q_{2} E dt \). After integrating, the increment in momentum results in \( \Delta p = q_{1} q_{2} / 2 \pi \epsilon_{0} v b \) which is perpendicular to \( \mathbf{v} \). This shows that the increment in momentum acquired by each particle as a result of the encounter is perpendicular to \( \mathbf{v} \).
03

Derive the Condition for the Masses

The presence of the other particle should not significantly influence the motion of either particle. This means the displacement must be less than \( b \). This is achieved if the acceleration \( a = F/m \) during the encounter is much less than \( v^{2} / b \). Using \( F = q_{1} q_{2} / 4 \pi \epsilon_{0} b^{2} \) and substituting for the acceleration, we get \( m \gg q_{1} q_{2} / 4 \pi \epsilon_{0} v^{2} b \). This justifies our initial assumptions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electric Fields
Electric fields are invisible forces surrounding charged particles. They exert a force on other charged objects within the field. The intensity of this force depends on both the charge creating the field and the distance from the charge.

Electric fields are calculated using Coulomb's law, which states that the electric field (E) due to a point charge is given by \[ E = \frac{q}{4 \pi \epsilon_0 r^2} \]where:
  • \( q \) is the charge of the particle.
  • \( \epsilon_0 \) is the permittivity of free space.
  • \( r \) is the distance from the charge.
These fields influence how charges interact as they move through each other's fields, causing forces that can alter their motion. This concept is key to understanding how charges acquire momentum when passing near each other.
Gauss's Law
Gauss's Law is important in understanding electric fields. It relates the electric flux flowing out of a closed surface to the charge enclosed within that surface.

The mathematical form of Gauss's Law is:\[ \oint \mathbf{E} \cdot d\mathbf{A} = \frac{Q_{\text{enc}}}{\epsilon_0} \]where:
  • \( \mathbf{E} \) is the electric field.
  • \( d\mathbf{A} \) is the differential area on the closed surface.
  • \( Q_{\text{enc}} \) is the total charge enclosed inside the surface.
This law is especially useful because it allows us to calculate electric fields of symmetrical charge distributions much easier than using Coulomb's law directly. In the original problem, it helps determine the field influencing the moving charge, especially when distances and symmetrical considerations are involved, like maintaining the straight-line path assumption between massive particles.
Particle Physics
Particle physics explores the fundamental particles and forces, impacting how charged particles interact. It involves both the electromagnetic forces (as seen with electric fields and Gauss's law) and weak, strong, and gravitational forces in other contexts.

For the described scenario of two charged particles, the focus is on how the electromagnetic forces influence their trajectories and momentum. A particle's charge and mass are vital characteristics that dictate its behavior in a field. High energy exchanges are typical, requiring considerations of mass and energy, as motion can be nearly at the speed of light. Ideas from particle physics allow us to predict particle behavior when they are significantly influenced by short-range and long-range forces.
Relativistic Velocities
Relativistic velocities occur when particles move at speeds close to the speed of light (denoted \( c \)). At these speeds, Newtonian mechanics no longer apply, and special relativity principles come into play.

Key effects of relativistic velocities include:
  • Time dilation, where time appears to slow down relative to an observer.
  • Length contraction, where lengths parallel to the direction of motion shorten.
  • Relativistic mass, where the mass of the object increases with velocity.
In the context of momentum transfer between charged particles, relativistic effects dictate how mass and energy should be factored into calculations, helping ensure predictions and observations match. Accurate assessment of how fast-moving charges exchange momentum often relies on relativistic considerations, particularly when velocities are not small compared to \( c \).

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Most popular questions from this chapter

Distribution of charge on a capacitor Consider a parallel-plate capacitor with different magnitudes of charge on the two plates. Let the charges be \(Q_{1}\) and \(Q_{2}\) (which we normally set equal to \(Q\) and \(-Q\) ). Find the four amounts of charge on the inner and outer surfaces of the two plates.

Field just outside a capacitor * A capacitor consists of two disks with radius \(R\), small separation \(s\), and surface charge densities \(\pm \sigma\). Find the electric field just outside the capacitor, an infinitesimal distance from the center of the positive disk.

Conductor in a capacitor (a) The plates of a capacitor have area \(A\) and separation \(s\) (assumed to be small). The plates are isolated, so the charges on them remain constant; the charge densities are \(\pm \sigma .\) A neutral conducting slab with the same area \(A\) but thickness \(s / 2\) is initially held outside the capacitor, see Fig. \(3.40 .\) The slab is released. What is its kinetic energy at the moment it is completely inside the capacitor? (The slab will indeed get drawn into the capacitor, as evidenced by the fact that the kinetic energy you calculate will be positive.) (b) Same question, but now let the plates be connected to a battery that maintains a constant potential difference. The charge densities are initially \(\pm \sigma\). (Don't forget to include the work done by the battery, which you will find to be nonzero.)

Force, and potential squared * (a) In Gaussian units, show that the square of a potential difference \(\left(\phi_{2}-\phi_{1}\right)^{2}\) has the same dimensions as force. (In SI units, \(\epsilon_{0}\left(\phi_{2}-\phi_{1}\right)^{2}\) has the same units as force.) This tells us that the electrostatic forces between bodies will largely be determined, as to order of magnitude, by the potential differences involved. Dimensions will enter only in ratios, and there may be some constants like \(4 \pi\). What is the order of magnitude of force youexpect with 1 statvolt potential difference between something and something else? Practically achievable potential differences are rather severely limited, for reasons having to do with the structure of matter. The highest man-made difference of electric potential is about \(10^{7}\) volts, achieved by a Van de Graaff electrostatic generator operating under high pressure. (Billion-volt accelerators do not involve potential differences that large.) How many pounds force are you likely to find associated with a "square megavolt"? These considerations may suggest why electrostatic motors have not found much application.

Principal radii of curvature * Consider a point on the surface of a conductor. The principal radii of curvature of the surface at that point are defined to be the largest and smallest radii of curvature there. To find the radii of curvature, consider a plane that contains the normal to the surface at the given point. Rotate this plane around the normal, and look at the curve representing the intersection of the plane and the surface. The radius of curvature is defined to be the radius of the circle that locally matches up with the curve. For example, a sphere has its principal radii everywhere equal to the radius \(R\). A cylinder has tone principal radius equal to the cross-sectional radius \(R\), and the other equal to infinity. It turns out that the spatial derivative (in the direction of the\\} normal) of the electric field just outside a conductor can be written in terms of the principal radii, \(R_{1}\) and \(R_{2}\), as follows: $$ \frac{d E}{d x}=-\left(\frac{1}{R_{1}}+\frac{1}{R_{2}}\right) E $$ (a) Verify this expression for a sphere, a cylinder, and a plane. (b) Prove this expression. Use Gauss's law with a wisely chosen pillbox just outside the surface. Remember that near the surface, the electric field is normal to it.

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