/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 Combining the current densities ... [FREE SOLUTION] | 91Ó°ÊÓ

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Combining the current densities We have \(5 \cdot 10^{16}\) doubly charged positive ions per \(\mathrm{m}^{3}\), all moving west with a speed of \(10^{5} \mathrm{~m} / \mathrm{s}\). In the same region there are \(10^{17}\) electrons per \(\mathrm{m}^{3}\) moving northeast with a speed of \(10^{6} \mathrm{~m} / \mathrm{s}\). (Don't ask how we managed it!) What are the magnitude and direction of \(\mathbf{J}\) ?

Short Answer

Expert verified
The magnitude of the total current density \(J\) is \(160.25 \text{ A/m}^{2}\) and is directed \(84.29^\circ\) south of west.

Step by step solution

01

Calculate the current density for positive ions

Using the formula for current density, \(J= nqv\), where n is the number of charge carriers (ions), q is the charge of each carrier and v is the velocity of the carriers, the current density (\(J_+\)) of the positive ions is calculated as follows: The charge of each ion, q, will be twice the fundamental charge (since they are doubly charged), thus \(q=2e\), where \(e = 1.6 \times 10^{-19}\) C (the charge of an electron). Therefore, \(J_+ = (5 \times 10^{16} \text{ m}^{-3}) \times (2 \times 1.6 \times 10^{-19} \text{ C}) \times (10^{5} \text{ m/s}) = 16 \text{ A/m}^{2}\). Here, west has been assumed as the positive direction.
02

Calculate the current density for electrons

For the electrons, we consider that the direction of current density caused by the electrons is opposite to their direction of motion (since they are negatively charged). Thus, in this case, the current density (\(J_-\)) is to the southwest. The calculation is similar to that of the ions, using the same formula: \(J_- = (10^{17} \text{ m}^{-3}) \times (-1.6 \times 10^{-19} \text{ C}) \times (10^{6} \text{ m/s}) = -160 \text{ A/m}^{2}\). The value is negative due to the southwest direction as opposed to the positive west direction.
03

Add the individual current densities

The total current density \(J\) is the vector summation of the current densities calculated above, treating west-east as the \(x-\)axis and north-south as the \(y-\)axis. This gives: \(J = J_+ \hat{i} + J_- \hat{j} = 16 \hat{i} - 160 \hat{j} \text{ A/m}^{2}\). Thus, the magnitude of the total current density is \(\sqrt{(16^2 + (-160)^2)} = 160.25 \text{ A/m}^{2}\), and its direction can be calculated using the formula \(tan^{-1}(y/x)\), giving a result of \(84.29^\circ\) south of west.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Charge Carriers
In the realm of electrical physics, charge carriers play a pivotal role. They are particles that carry electric charge, facilitating the flow of electric current. Typical examples include electrons, ions, and holes. Electrons, which are negatively charged, are usually the primary charge carriers in conductors like metals. In semiconductors or other materials, both positive and negative charge carriers can coexist.

The question of charge carriers becomes crucial when analyzing current density. For instance, when an external electric field is applied, these carriers drift in a certain direction. This movement is what constitutes the electric current. In our example problem, the positive ions and electrons are both acting as charge carriers, albeit with differing charges and flow directions.
Velocity
Velocity refers to the speed and direction of the moving charge carriers. It determines how quickly and in which direction these particles are moving. In the context of current density, the velocity of charge carriers directly impacts the calculation of current density through the formula \[ J = nqv \].

In our example, two different velocities are considered: the westward movement of ions at \( 10^5 \text{ m/s} \)and the northeastward motion of electrons at\( 10^6 \text{ m/s} \).These differing directions and magnitudes are crucial for determining the overall current density. A higher velocity indicates a greater rate at which charge carriers move through a material, often resulting in a higher current density if other factors like charge and concentration of charge carriers remain constant.
Vector Summation
Vector summation is critical when calculating the total current density, especially when multiple charge carriers are involved, each moving in different directions. Current is a vector quantity, meaning it has both magnitude and direction.

To find the net current density, it is necessary to add the individual current densities as vectors. For example, in our exercise, the ion current density heading west and the electron current density heading southwest need to be combined into one total vector. This involves:
  • Breaking each current density into its components, aligning with a coordinate system (e.g., x-axis for east-west, y-axis for north-south).
  • Performing the vector addition by summing the corresponding components.
Finally, the magnitude of the resulting vector is determined using the Pythagorean theorem, and its angle using trigonometric functions like tangent inverse, which together describe the direction and strength of the net current.
Electric Charge
Electric charge is the fundamental property of particles that causes them to experience a force in an electric field. This property can be either positive or negative, and its unit of measurement is the Coulomb (C). Negative charges are carried by electrons, while positive charges can be carried by protons or positive ions.

In determining current density, understanding the type and magnitude of charge is key. Using the charge of the fundamental unit, an electron (\( e = 1.6 \times 10^{-19} \text{ C} \)), we calculate the effect of each charge carrier on the current. Doubly charged ions, for example, carry twice this charge, thereby affecting their contribution to current density.

Overall, electric charge is central because it directly influences both the direction and magnitude of current density, as seen with both the ions and electrons in the exercise. Positively and negatively charged carriers move in opposite directions when subjected to an electric field, creating a complex but mathematically resolvable pattern of overall current.

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