/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 74 Zero field in a sphere In Fig.... [FREE SOLUTION] | 91Ó°ÊÓ

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Zero field in a sphere In Fig. \(1.51\) a sphere with radius \(R\) is centered at the origin, an, infinite cylinder with radius \(R\) has its axis along the \(z\) axis, and an infinite slab with thickness \(2 R\) lies between the planes \(z=-R\) and \(z=R\). The uniform volume densities of these objects are \(\rho_{1}, \rho_{2}\) and \(\rho_{3}\), respectively. The objects are superposed on top of each other; the densities add where the objects overlap. How should the three densities be related so that the electric field is zero everywhere throughout the volume of the sphere? Hint: Find a vector expression for the field inside each object, and then use superposition.

Short Answer

Expert verified
The uniform volume densities of the sphere, cylinder, and the slab should be related as \(\rho_1 = -\rho_3\) and \(\rho_2 = -\rho_3\) such that the electric field becomes zero everywhere inside the sphere.

Step by step solution

01

Electric Field of a Sphere

The electric field \(E_1\) inside a sphere with uniform volume charge density \(\rho_1\) is given by the equation: \(E_1 = \frac{1}{3}\rho_1 r\), where \(r\) is the distance from the center of the sphere.
02

Electric Field of an Infinite Cylinder

The electric field \(E_2\) inside an infinite cylinder with uniform volume charge density \(\rho_2\) is \(E_2 = \frac{1}{2} \rho_2 r\). This is only in the radial direction, i.e, perpendicular to the axis of the cylinder.
03

Electric Field of an Infinite Slab

The electric field \(E_3\) inside an infinite slab with uniform volume charge density \(\rho_3\) is: \(E_3 = \rho_3 z\). This field is along the z-axis, which is vertical.
04

Using the Principle of Superposition

The principle of superposition tells us that if more than one field is present, the resulting field is the vector sum of all fields.The total electric field \(E\) inside the sphere is therefore given by: \(E = E_1 + E_2 + E_3 = \frac{1}{3}\rho_1 r + \frac{1}{2}\rho_2 r + \rho_3 z\). Humanity wants this electric field \(E\) to be zero everywhere in the sphere. It means, every term in the equation must become zero.
05

Equating Each Term to Zero

We equate each term in the equation to zero: \(-\frac{1}{3}\rho_1 r = -\frac{1}{2}\rho_2 r = -\rho_3 z\). Since \(r\) and \(z\) are non-zero in the sphere, both \(\rho_1\) and \(\rho_2\) must be equal to \(\rho_3\) but with opposite signs to make the whole equation zero, i.e, \(\rho_1 = -\rho_3\) and \(\rho_2 = -\rho_3\). This is the relation between the three densities such that the electric field is zero everywhere throughout the volume of the sphere.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Uniform Volume Charge Density
When we talk about a uniform volume charge density, we are referring to a scenario where the charge is distributed evenly throughout a volume of space. In more technical terms, this means that the charge per unit volume, denoted as \( \rho \), is constant. This concept is critical in understanding the behavior of the electric field within various geometric shapes such as spheres, cylinders, and slabs.

For instance, if we have a sphere with a uniform charge density \( \rho_1 \), each small volume element has the same amount of charge spread over it. The simplicity of the charge distribution makes it possible to calculate the electric field inside the sphere using laws like Gauss's law, leading to the relation \( E = \frac{1}{3}\rho r \) that you might have encountered in physics textbooks.
Electric Field of a Sphere
Understanding the electric field of a sphere with a uniform density is a fundamental principle in electromagnetism. Inside a sphere, the electric field varies directly with the distance from the center according to the formula \( E_1 = \frac{1}{3}\rho_1 r \), where \( r \) is that distance and \( \rho_1 \) is the uniform volume charge density.

The essence of this relationship is based on the symmetry of the sphere, allowing us to consider only the radial component of the electric field. Since the field is directly proportional to \( r \), it gradually increases from zero at the center to its maximum at the sphere's surface. This spherical symmetry and the resulting field distribution are fundamental when comparing the electric field inside other shapes or when combining fields using the principle of superposition.
Electric Field of an Infinite Cylinder
When it comes to an infinite cylinder, we're dealing with a geometry that extends indefinitely along one axis, usually referred to as the \( z \) axis. The electric field inside an infinite cylinder is also proportional to the distance from the axis, but the formula differs slightly from that of a sphere: \( E_2 = \frac{1}{2} \rho_2 r \). Here, \( \rho_2 \) is the charge density of the cylinder, and \( r \) now represents the radial distance from the cylinder's axis.

This difference arises due to the cylindrical symmetry—unlike a sphere, an infinite cylinder does not have a central point but rather an axis of symmetry. Consequently, the field's value at a given point depends on the radial distance, not the overall distance from a point, and this conventional approach finds the field to be linearly increasing from the axis outward.
Electric Field of an Infinite Slab
The electric field of an infinite slab can be surprisingly straightforward, thanks to its uniform volume charge density. An infinite slab is a flat, extended structure, and when it has a uniform charge density \( \rho_3 \), the electric field inside is described by \( E_3 = \rho_3 z \), where \( z \) is the perpendicular distance from the center of the slab.

What sets the infinite slab apart from the sphere and cylinder is its planar symmetry. It's significant to note that while the fields in the sphere and cylinder depend on radial distances, the field in an infinite slab varies linearly with \( z \)—the distance along the axis perpendicular to its surface. The field is constant for any fixed \( z \), providing a unique model of uniform electric fields often used in various applications and theoretical scenarios.
Principle of Superposition
The principle of superposition is a cornerstone of electromagnetism which states that when multiple electric fields exist in the same space, the total electric field is the vector sum of these individual fields. This principle is essential in solving complex scenarios where fields from different charge distributions overlap, like in the original exercise where a sphere, a cylinder, and a slab are superimposed.

To find a condition where the electric field inside the sphere is zero, the principle of superposition mandates that the vector sum of the fields \( E_1 \), \( E_2 \), and \( E_3 \) must add up to zero at every point within the sphere's volume. In mathematical terms, superposing the fields \( \frac{1}{3}\rho_1 r + \frac{1}{2}\rho_2 r + \rho_3 z = 0 \). In practice, this involves manipulating the densities, ensuring that their contributions to the overall field negate each other, resulting in an area where there is no net electric field— and thus bringing around the conditions for equilibrium in the sphere's interior.

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Most popular questions from this chapter

Gauss's law and two point charges ** (a) Two point charges \(q\) are located at positions \(x=\pm \ell\). At points close to the origin on the \(x\) axis, find \(E_{x}\). At points close to the origin on the \(y\) axis, find \(E_{y}\). Make suitable approximations with \(x \ll \ell\) and \(y \ll \ell\) (b) Consider a small cylinder centered at the origin, with its axis along the \(x\) axis. The radius is \(r_{0}\) and the length is \(2 x_{0}\). Using your results from part (a), verify that there is zero flux through the cylinder, as required by Gauss's law.

Escaping field lines * Charges \(2 q\) and \(-q\) are located on the \(x\) axis at \(x=0\) and \(x=a\), respectively. (a) Find the point on the \(x\) axis where the electric field is zero, and make a rough sketch of some field lines. (b) You should find that some of the field lines that start on the \(2 q\) charge end up on the \(-q\) charge, while others head off to infinity. Consider the field lines that form the cutoff between, these two cases. At what angle (with respect to the \(x\) axis) do these lines leave the \(2 q\) charge? Hint: Draw a wisely chosen Gaussian surface that mainly follows these lines.

Zero field \(?\) Four charges, \(q,-q, q\), and \(-q\), are located at equally spaced intervals on the \(x\) axis. Their \(x\) values are \(-3 a,-a, a\), and \(3 a\), respectively. Does there exist a point on the \(y\) axis for which the electric field is zero? If so, find the \(y\) value.

(a) At each corner of a square is a particle with charge \(q\). Fixed at the center of the square is a point charge of opposite sign, of magnitude \(Q .\) What value must \(Q\) have to make the total force on each of the four particles zero? (b) With \(Q\) taking on the value you just found, show that the potential energy of the system is zero, consistent with the result from Problem 1.6.

\(N\) charges on a circle \(N\) point charges, each with charge \(Q / N\), are evenly distributed around a circle of radius \(R\). What is the electric field at the location of one of the charges, due to all the others? (You can leave, your answer in the form of a sum.) In the \(N \rightarrow \infty\) limit, is the field infinite or finite? In the \(N \rightarrow \infty\) limit, is the force on one of the charges infinite or finite?

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